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3 Problems with Solutions on Linear CIR Circuits - Exam 1 | EEN 307, Exams of Electrical and Electronics Engineering

Material Type: Exam; Professor: Narayanamurthi; Class: LINEAR CIR SIGNALS; Subject: Electrical/Computer Eng. (EEN) ; University: University of Miami; Term: Fall 2009;

Typology: Exams

2010/2011

Uploaded on 11/06/2011

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Download 3 Problems with Solutions on Linear CIR Circuits - Exam 1 | EEN 307 and more Exams Electrical and Electronics Engineering in PDF only on Docsity! Name: So LUTION S UM Student ID: EEN 307 Exam 1 Fall 2009 Prof. Murthi PLEASE EXPLAIN YOUR STEPS AND REASONING FOR FULL CREDIT. I CANNOT READ YOUR MIND! Problem 1: Cousider the circuit below, and assume that you can use the ideal op-amp approximations. At time ¢ = 0, the switch closes, and the current source i,(t) is connected Lo the circuit. (a) Write the differential equation characterizing the relaliouship between the output voltage v(t) and the input current 2.{t} Zor t > 0. “(b) For i,(t) = 5mA, find the output voltage vp(é). =o (Ne carcect \tho the Neb Tet Ay teneiover Bag terminal) Gwe Com OX aint Te SeRREe = V8) = ce Nem Vette} = ve) t vite Le ‘ reuler woe por u es Vo) = Rye Pie Jey Stace Ast Cans pont - Oot Lk = 2ye (Sxlo 3) &? . 5 ° 1° — Ast] = SXt0 A 3 = 2 5 x19 k= a5 x a fos = 9.5Xt0 % Sees oT Noi Det yh = a= Les v®) TAL we Ve (2) eA go we tAfect Auk Ce? / Vc () = ASH R, = Rey \ (hen veley= Ry + », = Oo of ke _ fey - (25 “Thom _t ye (seh +625 £278 CS Ace] = Cael pet _¢ = c(t )e 4 bo \ -3 7s Al = [Fee x 125 ) c tis [oOo ~3 ~t Q — éf ee zea) — £08 2 al(e) — ARS = ~*- fax'(“Iee) what ‘ype a lla! Cxamtee th (9 | wee o ine F Cc) Ceo. wh = Olxte Rp pole 0 = jo Xte ye t = 3. [a ber te * We «= ISG He We = pe = 1° Qn “ Rye. “ -~¢ 3 _ -~2 ReC= o-lxte x joxle = ie Ry JR, = ( hye fo Vyltl= Ae cod (vot 1 2) Tne ootpet + Volkl= Agl Hla) Idea (wat + B+ LH/e)) Sa for each cor, fad HMI ZH) \. Mot 3, Wy? en 5°, g=43" f= Sodz. wees) ey = 0454 Coat beats \ ange y at (59H) + ( Jn? Ss ia The pat Sd , Problem 3: Consider the following observed input-output properties of various systems. For each system, explain why or why not the system is a linear time-invariant (LTT) systom. (a) input iQ = ef + ef, ontput y(t) = e* (b) input f(t) = 7cos(3t); ontput y(t) — 4+ 17 cos(3l + 53°). (c) inpué /(Q = 7coa(St — 44°) + e™*; output y(t) = 49 cos(St + 14”) DY eilstgitn/s) (d) input f(d) (e) input (id) output y(t) = dei("/?), 5; 5; output y(t) = Se’. L " 7 cool34) fy 44 eeslt3t + 53°) Ny Re Sasem no not LL. Ne {raeae Suslan C&A feat az Cond Toa at tty eatyet (4 abave) ied we (NM Ceathat at Th inpud . f- Cc) Feoal Stas) eo TF tste whe nei Woe Syston is Magen, F b00(St— 44") [9 FF cos (StH ge) , [Ho] £45) Ba b& ae = h are lt sg) yO? [How, — ZAC3) (4) S as oe! ba 5) d “This implia AB He) = } Laktckh = Net allowed fr LwTt sqateos (Hs) Canact be eo, Nel (rrean / complex) Ce) 6 4}a 5" = 7 bays er Hel YS Thy iy O ° Allows , Se linear. 9
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