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Solving Systems of Equations using Elimination Algebraically, Slides of Linear Algebra

These notes provide a step-by-step guide on how to solve systems of linear equations algebraically using elimination with addition and subtraction. the elimination method in standard form, determining which variable to eliminate, adding or subtracting equations, substituting back to find the other variable, and checking the solution.

Typology: Slides

2021/2022

Uploaded on 09/27/2022

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Download Solving Systems of Equations using Elimination Algebraically and more Slides Linear Algebra in PDF only on Docsity! Notes 5.3 Solving systems of equations using elimination with addition and subtraction. Solving Systems of Equations • So far, we have solved systems using graphing and substitution. These notes show how to solve the system algebraically using ELIMINATION with addition and subtraction. • Elimination is easiest when the equations are in standard form. Ex 1 Continued Step 4: Substitute back in to find the other variable. x + y = 5 (3) + y = 5 y = 2 Step 5: Check your solution. (3, 2) (3) + (2) = 5 3(3) - (2) = 7 The solution is (3, 2). What do you think the answer would be if you solved using substitution? x + y = 5 3x – y = 7 2) Solve the system using elimination. 4x + y = 7 4x – 2y = -2 Step 1: Put the equations in Standard Form. They already are! Step 2: Determine which variable to eliminate. The x’s have the same coefficient. Step 3: Add or subtract the equations. Subtract to eliminate x. 4x + y = 7 (-) 4x – 2y = -2 3y = 9 y = 3 Ex 2 Continued Step 4: Plug back in to find the other variable. 4x + y = 7 4x + (3) = 7 4x = 4 x = 1 Step 5: Check your solution. (1, 3) 4(1) + (3) = 7 4(1) - 2(3) = -2 4x + y = 7 4x – 2y = -2
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