ECE 3050 - Spring 2004: Homework Assignment No. 10 Solutions for Circuit Theory, Assignments of Electrical and Electronics Engineering

Download ECE 3050 - Spring 2004: Homework Assignment No. 10 Solutions for Circuit Theory and more Assignments Electrical and Electronics Engineering in PDF only on Docsity! ECE 3050 – Spring 2004 Page 1 Homework Assignment No. 10 - Solutions 1.) Problem 17.21 (17.14) of the text. Low Frequency: Mid-band: v i 2 kΩ 100 kΩ22 kΩ 12 kΩ 4.7 µF 1 µF R I R 4 R 3 R 7 C 1 C 2 892 kΩ 0.1 µF C 3 v i 2 kΩ 12 kΩ 100 kΩ22 kΩ Rin g mA V mS g R R g k k k R k k k A R R R g R k k k mS m m in S m L mid in I in m L = ( ) = = = = = = = + = + ( )( ) = ( ) = 2 0 1 1 0 200 1 5000 1 12 5 3 53 22 100 18 0 3 53 2 3 53 0 200 2 30 1 . . . . . . . . | = | 18k 7.24dB Ω Ω Ω Ω Ω Ω Ω Ω Ω Ω Ω ω 1 1 4 7 10 2 3 53 38 5 0 1 1 10 100 22 82 0 1 2 38 5 82 0 19 2 1 6 2 3 3 3 7 7 C R R x k k rad s i C R R k k rad s f Hz I in g L +( ) = +( ) = = = = +( ) = +( ) = ≅ +( ) = − − . . . ! . . . . Ω Ω Ω Ω | doesn't matter since | ω ω π ECE 3050 – Spring 2004 Page 2 2.) Problem 17.24 (17.17) of the text. SCTC requires : | + << will be dominant = ω π ω ω ω ω ω ω ω ω ω L is ii L L S m R C rad s F M k rad s F k M rad s C R g ≅ = ( ) = = ( ) +( ) = = ( ) +( ) = → ≅ =   ∑ − − 1 2 500 3140 1 10 2 43 1 4 11 1 10 43 1 9 59 1 1 1 3 1 7 2 7 1 2 3 3 3 3 . . . | Ω Ω Ω Ω     = − = ( ) = = = ( ) = → | | from Appendix C g I V V mA V mS g k C k k F F m D GS TN m 2 2 0 2 1 0 400 1 2 50 1 3140 13 2 5 0 152 0 153 . . . . . . Ω Ω Ω µ µ 3.) Problem 17.58 (17.41) of the text. 75 kΩ 43 kΩ 3 V 13 kΩ +12 V 3 kΩ 43 kΩ 100 kΩ 100 Ω 30.1 kΩ vi 75 k Ω Rin Short-Circuit Time Constants R k k k k R k k k R k k k k f k F k F S S S L 1 2 3 100 75 300 15 1 101 3 60 8 43 100 143 10 3 15 1 99 9 101 2 40 1 2 1 60 8 1 1 143 0 1 = + + + ( )[ ] = = + = = + +      = ≈ ( )( ) + ( )( ) + Ω Ω Ω Ω Ω Ω Ω Ω Ω Ω Ω Ω Ω Ω Ω Ω . . . . . . .π µ µ 1 2 40 2 2 43 9 . . . k F Hz Ω( )( )      = µ Open-Circuit Time Constants Using the results from Table 17.2 on page 1334 : | R r C pF mS k k pF mS k mS k k C pF f th x TB TB H + = + = = + ( )( ) +      + + ( )( ) + ( )( ) +       = = 99 9 300 400 3 02 1 6 63 3 1 3 400 0 5 1 6 63 30 1 1 6 63 3 30 1 400 44 1 1 . . . . . . . . . Ω Ω Ω Ω Ω Ω Ω Ω Ω Ω 2 400 44 1 9 02 9 45 9 02 43 9 85 2 π Ω( )( ) = ( ) = −( ) = . . . . . . pF MHz b GBW MHz Hz MHz