5 Solved Problems on Strength of Materials - Examination 2 | ENGR 2530, Exams of Engineering

Download 5 Solved Problems on Strength of Materials - Examination 2 | ENGR 2530 and more Exams Engineering in PDF only on Docsity! Name: RIN: Problem 1: For the beam and loading shown, the dimensions are AB = BC = CD = DE = Im, EF = 0.5m. Determine: (a) The equations of shear force and bending moment for the beam AF. Draw the shear force diagram and bending moment diagram (15 points) (b) Find the maximum absolute values of shear force and bending moment. Find the locations that experience these values (5 points) (c) The required section modulus, if the allowable normal stress is 7 =.120 MPa (5 points) 12 kN 2 kN/m | <7 A B Cc D E F () Find sencker fr © A. G Rule hihi! Bod! telcan BLE 4y «pact lead g My 20 " Laem /mn 92” 1% aor ' : ' ' r Re Ra (4:5) -2(3:5) Ra Me Jo pe lon pe] mH | os: +g -2(i26 eee => [Ra =  (a) bdbirw £Qnakons Za thioh fue & Beraliny onongent Arkin AB Arwhken BC Aicker CA 1 it <Xal¥ iy gr — 5, pel) ea De Ryze ' $ x es Feo Shu Br ro Ve Ry eo yo 8ti2=0 V-@ 4/220 [ve-4] vir gmro S™M=0 sm:a M- $420 mba eir(tee | mex +iz(a-i)~ & 7? [az -axtir | [os -4xrra] bebor OE ,2(2-3) { SM +0 M- bat te IM zt (x-t) - & +? (x-3) (2-3) =0 M- 8x +(2(r) Zz - -X 4X FH IY V-@+l2 t 2 20 sm 20 4a (1-3-5) =O [wr nee] Name: RIN: Problem 2 : The cross-section of the beam shown is a hollow square. The moment vector M on the beam for the loading situation shown is in the Y-Z plane. All dimensions are in millimeters. (a) Find the distribution of normal stress across the cross-sectional area. In other words, find the normal stress as a function of the Y and Z coordinates. Express your answer in terms of the variables and z. (15 points) (b) Find the Y and Z coordinates of the locations of maximum-tensile and maximum compressive stress. Indicate these points on the figure. (5 points) (c) If the normal stress in the member is not to exceed 113.23 MPa, find the maximum magnitude of the moment M. (5 points) co? ® O Compute more 9 ee Zz —_ — $ eo Mes | - Ly 1, = 100) - SC Aca 36" iL 2 17 Cmaa, ; = 49rx10% mm? Ma TENSILE = -Ma3s 4 + Mdbd 3S 2 L L 2M Poy 3s ted 3S T 6, 2 a [Od +057 362 we és 492X 10 pssxieh® MONE ohpibottor on Fa. (5) Mow Ail Bion Ly egpetasnceo! oo by A root ch coorcknets (4,2) = (- 50mm, somnm) Max. Compbestint bat 5 vyenirod by Bo pact wilh condinal (ya)e (50mm, 50mm) 11323 (¢) Y O,, - Ripa xi0° Pa, Name: RIN: Problem 3: In the cross-section of the prismatic beam shown, a load P=231.7 KN is applied at the point A into the plane of the paper, The point A is located on the line of symmetry. All dimensions are in millimeters. Find: (a) The total normal stress at the point. B, located at the other end of the line of symmetry (15 points) (b) The neutral axis. Draw the neutral axis on the figure (10 points) NEUTRAL 20 7 AXIS @) Nad te fod wed &_ contiscolal menent of sp Guka. Y = SA; Ya SA Aeok or , / G0 000 | : > 853333. 33 | 3 40 000 5200 3 72000 Moret of nab fm vers seckorn T= Sir anv] = 928095693 mmr (6) Qe Q,+ 4. tG, Boer Gr? G3, q Q,+ 26, 2 Ot tag 421075 + 2x [68 FSX Blles Vv Ti = 8016 un? Hin @ 22 MG = COOK BOE = 195° 94? bb [> I 27-422 Name: RIN: Problem 5 (Bonus question, 10 points) : For the beam in problem 3, locate the neutral axis as a function of the load P. The emsanion fo etal rdvonl Bit -3 oy = -P + P GF-5 38x10 Ja 5200K10° 9280956-93 X10 TA condih on fo relict wea 4 Oy 7-0 + Tle kecation of Me rethol ema