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5th Math Week 4: Cryptarithms, Study notes of Calculus

A Cryptarithm is a mathematical puzzle where the digits in a sum have been replaced by letters. ... Can you find a solution to all of these cryptarithms?

Typology: Study notes

2021/2022

Uploaded on 08/05/2022

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Download 5th Math Week 4: Cryptarithms and more Study notes Calculus in PDF only on Docsity! 5th Math Week 4: Cryptarithms     A  Cryptarithm  is  a  mathematical  puzzle  where  the  digits  in  a  sum  have  been  replaced  by  letters.   • In  each  of  the  puzzles  below,  each  letter  stands  for  a  different  digit   • 0  is  never  the  first  digit  of  any  number.   Can  you  find  a  solution  to  all  of  these  cryptarithms?   Do  any  of  them  have  more  than  one  solution?         Do  any  of  them  have  more  than  one  solution?     How  can  you  be  sure  that  you  have  found  all  the  solutions  to  each  cryptarithm?     Source:     http://nrich.maths.org/11107   Week 4: Notes & Solutions   Notes  &  Hints   • Try  to  think  about  the  biggest  or  smallest  numbers  you  could  add  together  in  each  case.   • Does  that  tell  you  anything  about  the  digits  of  the  number  that  they  sum  to  ?   • If  you  add  two  2  digit  numbers  together  to  make  a  3  digit  number,  what  could  the  first  digit  of  that  number   be?     Solution   Here  is  a  list  of  all  the  solutions  we  have  managed  to  find  for  each  puzzle.  Please  let  us  know  if  you   discover  any  more!     1)  A=5,B=1.   2)  A=1,B=9,C=0.   3)  A=9,B=1,C=0.   4)  A=9,B=2,C=1,D=0.   5)  A=9,B=1,C=0.   6)  A=2,B=6,C=3          or  A=4,B=7,C=2          or  A=6,B=8,C=1.   7)  A=2,B=1,C=9.   8)  A=2,B=3,C=9.   9)  A=9,B=2,C=1.   10)  A=5,B=0,C=1.   11)  A=2,B=1,C=4              or  A=2,B=6,C=5              or  A=4,B=2,C=8              or  A=4,B=7,C=9.   12)  A=1,B=2,C=4              or  A=2,B=4,C=8              or  A=2,B=5,C=0              or  A=3,B=7,C=4              or  A=4,13)B=9,C=8.   13)  A=5,B=9,C=6.   14)  A=4,B=5,C=9.   15)  A=7,B=2,C=1.   16)  A=9,B=2,C=1,D=0,E=4.   17)  A=1,B=8,C=5.   18)  A=1,B=4,C=8.   19)  A=1,B=9,C=8.   20)  A=4,B=7,C=6.   21)  A=2,B=9,C=8.   22)  A=9,B=4,C=1,D=6.   23)  A=5,B=7,2,D=8.         Explanation  of  #1     A+A+A=BA.      A+A+A  must  equal  a  number  above  10  because  it  equals  a  two  digit  number  (BA).   Then  you  must  work  out  which  three  numbers  under  10  are  added  together  to  equal  a  number   under  30  with  the  same  second  digit.  A  also  has  to  be  4  or  above  because  3×3=9  which  is  not  a   two  digit  number.  Then  try  trial  and  error  with  this  information   4+4+4=12   5+5+5=15   6+6+6=18   7+7+7=21   8+8+8=24   9+9+9=27   By  doing  this  you  will  be  able  to  find  out  your  answer.   A=5   B=1     Several  people  worked  out  that  for  the  next  few  problems,  the  first  digit  of  the  total  would  be  1.   MJ  from  the  Bourne  Academy  explained  it  like  this:    
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