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Electrical Engineering Homework: Finding Norton and Thevenin Equivalents, Assignments of Electrical Circuit Analysis

A collection of electrical engineering homework problems focused on finding norton and thevenin equivalents of various circuits. Each problem includes a figure of the circuit and instructions on how to find the equivalents. The problems were assigned on september 19, 2011, and the deadline for submission is september 23, 2011.

Typology: Assignments

2011/2012

Uploaded on 04/27/2012

koofers-user-bal
koofers-user-bal 🇺🇸

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Download Electrical Engineering Homework: Finding Norton and Thevenin Equivalents and more Assignments Electrical Circuit Analysis in PDF only on Docsity! Homework 13 Due: Friday, September 23 1 For the circuit shown in Figure 1, find Norton equivalent circuit. 1 4 Monday, September 19, 2011 Figure 1: Model circuit for Problem 1. 2 Find the Norton and Thevenin equivalents of the circuit of Figure 2. 1 2 12 Monday, September 19, 2011 Figure 2: Model circuit for Problem 2. 3 (a) Find the Thevenin and Norton equivalent circuits for the network shown in Figure 3, assuming that k = 0.05 S and vs = 40 V. (b) For what value of k is the open circuit voltage zero? For this value of k, determine Rth. 4 (a) Find the Thevenin equivalent for the network shown in Figure 4. (b) If the value of each source are cut in half, what is the new voc ? 2 Kel (@x pves ie ly Fly = © —T) KVL in te lop AXB ives Van = 129 ~ 40, + 20%, Vag = [2 Fle iE, by@ Van 2§ lp + lg Is ——(@) We Know om 5 =e Vip = Vig # ty Ca (2) 26 KCL @D Arde is 0-08 Vy # Cy + & Vv, - Va7 Vx , =e 250 f = Yo _ Vy / to e A 250 a? BO} ; = I iy = = 2 V s = x(007F) —— CD Also Ohms lao 37 YOR Aenstomee gies Vea (Vee) = ¥O Cy Vy = 40 ty — Vagt Vs - WM EB n@D , Ly = O-2 — (406, —Vygt¥o) 6.078 Gi, = 0-015 Uyg ~ 2-8 2 .3at Y= 37.33 +53-33l, —/- + 0:0 2 / Filp : “= Vets = Rag Ge: 22 fs la 8. Find the mesh current i3 (in A): (1) 118 (2) 32/3 (3) 40/7 (4) 41/8 (5) 22/3 (6) 36/7 (7) none of the above 7. Find the equivalent resistance Reg (in ohms): (1) 12 (2)225 (3)8 (4) 24 (5) 25. (6) 19.5 (7) none of the above 12Q 120 12 — Req 120 RaQ pa oe 6. Find node voltage Ve (in V): (1 (2)2 (3)3 (4) 4 (5)5 (6) 6 (7) none of the above A 108 58 Cc 1s eVVV MII MINN 12A o 1s 8V
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