Download A long document about logarithm that contains Steps of solving and questions. and more Slides Mathematics in PDF only on Docsity! Module 6
Logarithmic Functions
What Vocabulary Will You Learn?
«common logarithms + logarithmic function
+ logarithm + natural base exponential function
+ logarithmic equation + natural logarithm
Today’s Vocabulary
logarithm
logarithmic function
Recall the exponential function f(x) = 2*. You can graph its inverse by
interchanging the x- and y-values and graphing the ordered pairs.
els
As the value of y
decreases, the value
of x approaches 0.
OO} [NM |= [| =]5!- Io] Be
CO} IN | — fl] 8/= |oo/= Beg
The inverse of y = 2* can be defined as x = 2”. In general, the inverse of
y= b*is x = bY”. Inx = b*, yis called the logarithm, base 6, of x. This is
usually written as y = log, x and is read as log base b of x.
Key Concept - Logarithms with Base b
Words Let b and x be positive numbers, b # 1. The /ogarithm of x
with base b is denoted log, x and is defined as the
exponent y that makes the equation bY = x true.
Symbols Suppose b > O and b #1. For x > O, there is a number y
such that log, x = y if and only if bY = x.
Example If log, 8 = y, then 2” = 8.
Example 2 Exponential to Logarithmic Form
Write each equation in logarithmic form.
a. 7° = 117,649
7® = 117,649 > log, 117,649 = 6
1
3. _*_
1
—3_ 1. 1 __
8° =a > 100g BH = 3
Check
Write 22 = 512 in logarithmic form.
Example 3 Evaluate Logarithmic Expressions
Evaluate log,,, 6.
lOgag 6 =y Let the logarithm equal y.
6 = 216” Definition of logarithm
6' = (63y 63 = 216
6'= 6 Power of a Power
1=3y Property of Equality for Exponential Functions
y=3 Divide each side by 3.
Therefore, log5,, 6 = a
Check
TORNADOS The distance in miles that a tornado travels is y= 10 2 ,
where w represents the speed of the wind in miles per hour.
Part A Write an equation to find the wind speed when the distance
travelled is known.
?
w=. :
Part B Use the equation to estimate the speed of the wind,
to the nearest mile per hour, of a tornado that travels 50 miles.
?
‘mph
A function of the form f(x) = log, x, where b > O and b #i,isa
logarithmic function. The graph of f(x) = log, x represents the parent
graph of the logarithmic functions.
Key Concept » Parent Function of Logarithmic Functions
Parent function — f(x) = log, x F(x) F(x) =log, x,
Type of graph continuous, one-to-one eal
Domain (0, 09), {x|x > O},
or all positive real numbers
Range (—co, oo),
oe real nOmberS. ’ Pe we ae
Asymptote y-axis
x-intercept (1, 0)
Symmetry none
Extrema none
For a function f(x) that is undefined at a vertical asymptote x = c, the
end behavior of f(x) is described as x approaches c from the right (c*)
or as xX approaches c from the left (c_). For the parent function f(x) =
log, X where b > 1, the end behavior is: As x — O*, f(x) > ~, and as
X — ©, f(x) > ~,
Step 3 Graph the ordered pairs.
Step 4 Draw a smooth curve through
the points.
Step 5 Find the intercepts, domain,
range, and end behavior.
x-intercept: 1; no y-intercept
domain: all positive real numbers
range: all real numbers
end behavior: As x — OT, f(x) + —oo, and as x — ©, fx) — ~.
b. g(x)
Step 1
Step 3
Step 4
Step 5
= logix
4
Identify the base.
ie
oa
Graph the ordered pairs.
Step 2 Identify ordered pairs.
Use the points é -1), (1, 0), and (b, 1).
(4-1) > (= ~) or (4, —1)
4
(1, 0)
(6. > (1)
Draw a smooth curve through the points.
Find the intercepts, domain, range, and
end behavior.
x-intercept: 1; no y-intercept
domain: all positive real numbers
range: all real numbers
end behavior: As x — OT, f(x) — oo, and as x — ov, f(x) — —oo,
~
Example 6 Graph Transformations of Logarithmic
Functions
Graph g(x) = 2 log,,.(x + 3) — 1.
g(x) = 2 log,, (x + 3) — 1 represents a transformation of the graph of
f(x) = logig x.
|a] =2 Because |a| > 1, the graph is
stretched vertically.
h=-3 Because h < O, the graph is
translated 3 units left.
k=-—1 Because k < O, the graph is
translated 1 unit down.
Example 8 Write Logarithmic Functions From Graphs
Identify the value of k, and write a function for the graph as it
relates to f(x) = log, x.
ay)
The graph has been translated 5 units up, so
k = 5 and the function is g(x) = log, x + 5.
Check
Write a function for each graph as it relates to f(x) = log, x.
a. glx) = fx) + k b. g(x) = k « fix
— gx)=_ 2
Practice
Example 1
Write each equation in exponential form.
1. log,, 225 = 2 2. logs 55 = —3 3. log, 55 =2
11. 22=512 12. 643 =16
Example 3
Evaluate each expression.
13. log, 64 14. 10gi99 100,000 15. log, 625
16. log,, 81 17. logy 35 18. log,, 0.00001
23. STRUCTURE The value of a guitar in dollars after x years can be modeled by the
equation y = g(1.0065)*, where g is the initial cost of the guitar. If a guitar costs
$400, write an equation to find the number of years it takes for a guitar to reach
a certain value.
Example 5
Graph each function. Then find the intercepts, domain, range, and end behavior.
24. fix) = logix 25. f(x) = log: x
9 5
24.
| Ay! 25.
|
si |
|
|
oO
LC
|
ry |
cs
x-intercept: 7; no y-intercept x-intercept: 1; no y-intercept
D: (0, 00) R: (—00, oo) D: (0, 00) R: (—90, 00)
end behavior: As x — 0*, fix) =
end behavior: As x — 0*, fx) — ~,
oo, and as x — 00, fx) > —oo.
and as x — ©, f{x) — —oo,
26. f(x) = log, x
26.
x-intercept: 1; no y-intercept
D: (0, 00) R: (—©o, 00)
end behavior: As x — 0*, f(x) =
—oo, and as x — ©0, fx) — oo,
27.
27. f(x) = logg x
x-intercept: 1; no y-intercept
D: (0, 00) R: (—o0, 00)
end behavior: As x — 0*, f(x) + —oo,
and as x — %, f{x) — ov.
Example 7
32. Consider g(x) = logy, (x — 4) and 32a. -
p(x) shown in the graph.
a. Graph g(x).
b. Compare the end behavior of g(x)
and p(x).
32b. g(x): As x — 4°, g(x) — —oo, and as
X — 00, g(x) — 00, p(x): As x — OF,
1 p(x) — ©, and as x > o,
p(x) + —9.
33. Consider f(x) = logy, (x + 2) and the
logarithmic function g(x) shown
in the table.
a. Graph f(x) and g(x).
b. Compare the end behavior of f(x)
and g(x).
27
33a.
33b. f(x): As x — —2*, f(x) — —oo, and
as X — ©9, f(x) — ©, g(x): As
x — 07% g(x) — —oco, and as
X — 00, g(x) — co.
Example 8
Identify the value of k. Write a function for each graph as it relates to f(x) = log, x.
34. g(x) = f(x) +k 35. h(x) = k = f(x) 36. j(x) = f(x) +k
4y
4y
Learn Logarithmic Equations
A logarithmic equation contains one or more logarithms.
Key Concept - Property of Equality for Logarithmic Equations
Symbols If b is a positive number other than 1, then
log, x = log, y if and only if x = y.
Example If log, x = log, 7, then x = 7. If x = 7, then log, x = log, 7.
This property also holds true for inequalities.
Example 1 Solve a Logarithmic Equation by
Using Definitions
Solve log, x = 2
>
log, x= 3 _ Original equation
x= 43 Definition of logarithm
x = (22) 4= 2?
x = 2° or 32 Power of a Power
Check
Solve log,3 (—5x) = log,3 (—2x? + 3).
?
x=
Learn Properties of Logarithms
Because logarithms are exponenis, the properties of logarithms can
be derived from the properties of exponents. For example, the Product
Property of Logarithms can be derived from the Product of Powers
Property of Exponenits.
Key Concept - Product Property of Logarithms
Words The logarithm of a product is the sum of the logarithms of
its factors.
Symbols For all positive numbers b, m, and n, where b # 1,
log, mn = log, m + log, n.
Example log, 8(4) = log, 8 + log, 4
You can use the Product Property of Logarithms to approximate
logarithmic expressions.
Key Concept - Quotient Property of Logarithms
Words
Symbols
Example
The logarithm of a quotient is the difference of the
logarithms of the numerator and the denominator.
For all positive numbers b, m, and n, where b # 1 and
n #0, log, 7 = log, m — log, n.
10g é = logg 2 — logg3
Key Concept - Power Property of Logarithms
Words
Symbols
Example
The logarithm of a power is the product of the logarithm
and the exponent.
For any real number rn, and positive numbers m and b,
where b # 1, log, m” = n log, m.
log, 3’ =7 log, 3
Products and Bases
Because the base of
the logarithm is 3 and
you are given an
approximation for
log, 5, the first step in
simplifying should be
to look for how to write
405 as a product of a
power of 3 and 5.
Example 4 Quotient Property of Logarithms
Use log, 5 = 1.465 to approximate the value of log, z.
9 3? 9 3?
log; 5 = 1093 5 5 5
= log; 32— log 35 Quotient Property of Logarithms
=2-—log35 Inverse Property of Exponents and
Logarithms
= 2 — 1.465 or 0.535 Replace log, 5 with 1.465.
Check
Use log, 5 = 0.8982 to approximate the value of log, ate.
5 2
lO9¢ 7296 ~
@ Apply Example 6 Solve a Logarithmic Equation by
Using Properties
SOUND The loudness of a sound L in decibels is defined by
L =10 log,, R, where R is the relative intensity of the sound. A choir
director wants to determine how many members could sing while
maintaining a safe level of sound, about 80 decibels. If one person
has a relative intensity of 10© when singing, then how many people
could sing with the same relative intensity to achieve a loudness of
80 decibels?
1 What is the task?
Describe the task in your own words. Then list any questions that you
may have. How can you find answers to your questions?
Sample answer: | need to find the number of people to reach 80 decibels.
How can | represent the relative intensity of sound when | do not know
the number of choir members? Which properties will | need to use? | can
reference the definitions of the properties of logarithms.
2 How will you approach the task? What have you learned
that you can use to help you complete the task?
Sample answer: | will interpret the situation to write R in terms of the
number of choir members x. Then, | will write an equation, and solve
for x. Finally, | will interpret the solution in context. | have learned how
to solve logarithmic equations and check for extraneous solutions.
3 What is your solution?
Use your strategy to solve the problem.
What expression represents the relative intensity R of a choir with
x members? x +10 ®
How many members should the choir have to reach a relative intensity
of 80 decibels?
100 members
4 How can you know that your solution is reasonable?
@ write About It! Write an argument that can be used to defend your
solution.
Sample answer: | can simplify R for x = 100 and solve for L. So,
R =100(10®) = (10)°.
Therefore, 80 = 10 log,, 10® = 10(8) = 80, which checks.
Example 2
Solve each equation.
7. log, (2x? — 4) = log, 2x
8. log. (x? — 6) = log. x
9. log, (x? — 8) = log, 2x
12. log, (6x? — 3) = log, 7x
Examples 3 and 4
Use log, 2= 0.5, log, 3 ~ 0.7925, and log, 5 ~ 1.1610 to approximate the value of
each expression.
13. log, 30 14. log, 20 15. log, 5
16. log, 5
17. log, 9 18. log, 8
Example 5
Use log, 3 ~ 1.5850 and log, 5 ~ 2.3219 to approximate the value of each expression.
19. log, 25 20. log, 27 21. log, 125
22. log, 625 23. log, 81 24. log, 243
Lesson 6-3
Common Logarithms
Today’s Goals
e Solve exponential
equations by using
common logarithms.
e Evaluate logarithmic
expressions by using
the Change of Base
Formula.
Today’s Vocabulary
common logarithms
Example 1 Find Common Logarithms by Using
Technology
Use a calculator to evaluate log 8 to the nearest ten-thousandth.
Press 8, Lx and [enter] The result is 0.903089987, so
log 8 = 0.9031.
logts
>
» J83889937
@ Example 2 Solve a Logarithmic Equation by
Using Exponential Form
SCIENCE The amount of energy E in ergs that is released by an
earthquake is related to its Richter scale magnitude M by the
equation log E = 11.8 + 1.5M. Although the scale was created in the
1930s, earthquakes that occurred before its invention have been
estimated using the Richter scale. For example, an earthquake in
Cyprus in 1222 is estimated to have measured 7 on the Richter
scale. How much energy was released?
logF=11.8+ 1.5M Original equation
log F= 11.8 + 1.5(7) M=7
log EF = 22.3 Simplify.
E = 10223 Exponential form
E= 2 x 1072 Use a calculator.
The earthquake released approximately 2 x 1022 ergs of energy.
Example 3 Solve an Exponential Equation by Using
Logarithms
Solve 11* = 101. Round to the nearest ten-thousandth.
11% = 101 Original equation
log 1% = log 101 Property of Equality for Logarithms
xX log 11 = log 101 Power Property of Logarithms
log 101 _ .
x= log 11 Divide each side by log 11.
xX = 1.9247 Use a calculator.
The solution is approximately 1.9247.
Example 4 Solve an Exponential Inequality by Using
Logarithms
Solve 62Y —5 < 53Y. Round to the nearest ten-thousandth.
6-5 < 5 Original inequality
log 6°75 < log 5°¥ Property of Inequality for
Logarithmic Functions
(2y — 5)log 6 < 3ylog5 Power Property of Logarithms
2ylog6— 5log6 < 3ylog5 Distributive Property
—5 log 6 < 3y log 5 —2y log 6 Subtract 2y log 6 from each
side.
—5 log 6 < y(3 log 5 — 2 log 6) Distributive Property
—5 log 6 .
3log5 — 2logé <y Divide each side by
3 log 5 — 2 log 6.
{yl y > —7.1970} Use a calculator.
Check
Test y= 0.
64-5 < 5%
6200)-5 < 53(0)
6-5 < 509
me< 1 True ¥
Original inequality
Replace y with 0.
Simplify.
Negative Exponent Property
Learn Change of Base Formula
The Change of Base Formula allows you to write equivalent logarithmic
expressions that have different bases.
Key Concept - Change of Base Formula
Symbols For all positive numbers a, b, and n, where a # 1and b #1,
log,
log, n= log, a
l0G,, 17
Example log, 17 = Tog, 8
10
Check
Evaluate logg 30. Round to the nearest ten-thousandth.
log, 30 = 2?
44 Example 6 Use the Change of Base Formula
MUSIC The musical centis "~"—
a unit of relative pitch.
One octave consists of
1200 cents. The formula
to determine the
difference n in cents
between two notes with
beginning frequency a
and ending frequency b is
n = 1200(log, F). Find the
frequency of pitch a if pitch b is 1661.22 and the
difference between the pitches is 1600 cents.
Step 1 Write the equation in terms of common logarithms.
n= 1200(log, 7) Original equation
1600 = 1200(logq@g155) «11 = 1600 and b = 1661.22
4 _
3> 092 (Te6122 35) Divide each side by 1200.
Bo
3
log e612
log 2 Change of Base Formula
Step 2 Use a calculator to solve for a.
Enter each side of the equation as a
function in the Y= list. Then, use the
. . . ——
intersect feature to find the value of a. ;
Intersection
RE4406.0124 Y=1.3332333
The functions intersect at
(4186.0121, 1.333).
(0, 6000] sel: 500 by [—5, 5] scl: 1
Pitch a has a frequency of about 4186.01 Hz.
Example 2
7. BIOLOGY There are initially 1000 bacteria in a culture. The number of bacteria
doubles each hour. The number of bacteria N present after f hours is given by
N = 1000(2)!. How long will it take the culture to increase to 50,000 bacteria?
8. SOUND An equation for loudness L in decibels is given by L = 10 log R, where R
is the relative intensity of the sound compared to the minimum threshold of
human hearing. One city’s emergency weather siren is 138 decibels loud. How
many times greater than the minimum threshold of hearing is the siren?
Example 3
Solve each equation. Round to the nearest ten-thousandth.
9, 49% = 37 10. 8°? = 50 11. 7¥=15