Download Alkenes: Structure and Reactivity - Lecture Slides | CHEM 2010 and more Study notes Organic Chemistry in PDF only on Docsity! 6. Alkenes: Structure and Reactivity Based on McMurry’s Organic Chemistry, 6th edition 2 Alkene - Hydrocarbon With Carbon- Carbon Double Bond Includes many naturally occurring materials Flavors, fragrances, vitamins Important industrial products These are feedstocks for industrial processes 5 Example: C6H10 Saturated is C6H14 Therefore 4 H's are missing This has two degrees of unsaturation Two double bonds? or triple bond? or two rings or ring and double bond H3C C C C C CH3 H H H H H H H H Other Examples of C,H,,:
Dp Aas
of
7 Degree of Unsaturation With Other Elements Organohalogens (X: F, Cl, Br, I) Halogen replaces hydrogen C4H6Br2 and C4H8 have one degree of unsaturation Oxygen atoms: these don't affect the total count of H's C4H8O3 10 If C-N Bonds Are Present Nitrogen has three bonds So if it connects where H was, it adds a connection point, and there an extra H Subtract one H for equivalent degree of unsaturation in hydrocarbon 11 Count pairs of H's below CnH2n+2 Add number of halogens to number of H's (X equivalent to H) Don't count oxygens (oxygen links H) Subtract N's - they have three connections Summary - Degree of Unsaturation 12 6.3 Naming of Alkenes Find longest continuous carbon chain for root Number carbons in chain so that double bond carbons have lowest possible numbers Double bond carbons must be numbered consecutively Cycloalkene nomenclature
ae
CH, 6
5 5 5 ,_ CH;
*_CH;
‘ 4 2
2 3
1,5-Dimethylcyclopentene 1-Methylcyclohexene
15
1,4-Cyclohexadiene
16 Cycloalkene nomenclature CH3 CH3CH31 2 1 2 3 1 2 4 1-methylcyclohexene 3-methylcyclohexene 4-methylcyclohexene Problem 6.4 (Page 175)
|
HC CH 1"
(a) H,C—=CHCHCCH, (b) CH;CH,CH=CCH,CH;
|
CH;
CHz CHs
| |
(c) CH;CH=CHCHCH =CHCHCH,
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TABLE 6.1 Common Names of Some Alkanes?
Compound Systematic name Common name
H,C—=CH, Ethene Ethylene
CH,CH=CH, Propene Propylene
CH,
ane =CH, 2-Methylpropene Isobutylene
CH,
H,C= i CH=CH, 2-Methyl-1,3-butadiene Isoprene
CH,CH=CHCH=CH, 1,3-Pentadiene Piperylene
“Both common and systematic names are recognized by IUPAC for these compounds.
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Alkene Group Names
ae
HO H,C=CH+
Ametiglene group =A vinyl group
H,C=CH— CH, +
An allyl group
22 6.4 Electronic Structure of Alkenes Carbon atoms in a double bond are sp2- hybridized Three equivalent orbitals at 120º separation in plane Fourth orbital is an unhybridized p orbital Combination of an electron pair in an orbital formed by the overlap of two sp2 orbitals of two atoms forms bond between them JA
\
r
a \
ee
yy" : _<
es :
rotation me
‘s ‘c
|
y
aw bond Broken 7 bond after rotation
(p orbitals are parallel) (p orbitals are perpendicular)
Aj
25
26 6.5 Cis-Trans Isomerism in Alkenes The presence of a carbon- carbon double can create two possible structures cis isomer - two similar groups on same side of the double bond trans isomer similar groups on opposite sides Each carbon must have two different groups for these isomers to occur 27 Cis, Trans Isomers Require That End Groups Must Differ in Pairs 180°rotation results in identical (superimposable) structures Bottom pair cannot be superimposed without breaking C=C (ie. rotating around the double bond) X 30 Develop a System for Comparison of Priority of Substituents Assume a valuation system If Br has a higher “value” than Cl If CH3 is higher than H Then, in A, the higher value groups are on opposite sides In B, they are on the same side Requires a universally accepted “valuation” 31 Ranking Priorities: Cahn-Ingold- Prelog Rules Must rank atoms that are connected at comparison point Higher atomic number gets higher priority Br > Cl > O > N > C > H In this case,The higher priority groups are opposite: (E )-1-bromo-1-chloro- propene 32 E,Z Stereochemical Nomenclature Priority rules of Cahn, Ingold, and Prelog Compare where higher priority group is with respect to bond and designate as prefix E -entgegen, opposite sides Z - zusammen, together on the same side 35 If atomic numbers are the same, compare at next connection point at same distance Compare until something has higher atomic number Do not combine – always compare Extended Comparison H H dH
-
pe ees
Lower Higher
1 i
CCH: OCH
H H
Higher Lower
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H
2+O—H 20—0-—n
ra i
Higher
CH; H
Facaurr, a
i i
Lower Higher
37 Substituent is drawn with connections shown and no double or triple bonds Added atoms are valued with no ligands themselves Dealing With Multiple Bonds Some Examples:
H
\
H C=CH,
\
c=C
\
H,C CH;
E)-3-Methy1-1,3-pentadiene
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iL
H,C—CH Br
\ /
c=c
/ \
H,C=cC H
\
H
(E)-1-Bromo-2-isopropyl-
1,3-butadiene
/ \
H CH,OH
(Z)-2-Hydroxymethyl-
2-butenoic acid
40
Practice problem 1 p. 178
H CH(CH,),
\ /
C=C
/ \
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Solution
ee
C, C, H bonded
L to this carbon
Low H re Low
C=C
fF *
High H,C CH,OH High
a O, H, H bonded
to this carbon
Z configuration
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45 6.7 Alkene Stability Cis alkenes are usually less stable than trans alkenes
cis-2-Butene trans-2-Butene
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47 6.7 Alkene Stability Compare heat given off on hydrogenation: Ho Less stable isomer is higher in energy and gives off more heat tetrasubstituted > trisubstituted > disubstituted > monosusbtituted
Reaction progress
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Equilibration of 2-butenes
eo
H CH, H,C CH,
\ Acid ye
i \ catalyst / a \
3C H H H
Trans (76%) Cis (24%)
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52 6.7 Alkene Stability Compare heat given off on hydrogenation: Ho Less stable isomer is higher in energy and gives off more heat tetrasubstituted > trisubstituted > disubstituted > monosusbtituted 55 Hyperconjugation Electrons in neighboring filled orbital stabilize vacant antibonding orbital – net positive interaction Alkyl groups are more stabilizing than H 56 Bond strengths/hybridization effects sp3-sp3 bond is weaker than sp3-sp2, sp2-sp2 57 Name each; which is more stable? Problem 13, p. 184 Solvent
ff
,C=CH, + HBr —S> CH,CH,Br
Reactant
Lo
_ HBr
oC — CH, Ether, ye CH,CH,Br
NL
Solvent
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61 Two step process First transition state is high energy point Electrophilic Addition Energy Diagram:
First transition state Carbocation intermediate
Second transition state
AG]
CH,
CH\C — Gly + HBr |
a
a Chi,
CHAC —Br
CH 3
Reaction progress ———»
62
First transition state
Energy
Carbocation intermediate
Second transition state
Reaction progress ————>
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66 Electrophilic Addition for Syntheses The reaction is successful with HCl and with HI as well as HBr. Note that HI is generated from KI and phosphoric acid 67 6.9 Orientation of Electrophilic Addition: Markovnikov’s Rule In an unsymmetrical alkene, HX reagents can add in two different ways, but one way may be preferred over the other If one orientation predominates, the reaction is regiospecific Markovnikov observed in the 19th century that in the addition of HX to alkene, the H attaches to the carbon with the most H’s and X attaches to the other end (to the one with the most alkyl substituents) This is Markovnikov’s rule No alkyl groups
on this carbon
Cl
alkyl groups — 3 i |
Eth
mn this sarbon ~C= CH, + Hcl —“- CH; —0— CH
CHs CH,
2-Methylpropene 2-Chloro-2-methylpropane
2 alkyl groups
on this carbon
je H,C
CH, Br
+ HBr Ether
H H
ie i
1 alkyl group
on this carbon
1-Methylcyclohexene 1-Bromo-1-methylcyclohexane
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Practice Problem 6.2 (p. 188):
CH,CH;
+ HCl — ?
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Solution:
ee
2 alkyl groups
on this carbon
/ CH,CH,
CH,CHs;
1 + HCl —~— Cl
1-Chloro-1-ethylcyclopentane
1 alkyl group
on this carbon
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Problem 6.14: Major products?
|
o(. J+na —* “2
(c) CH;,CH,CH,CH = CH, EEO 2
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(b) (CHs),C—=CHCH,CH,; > ?
CH.
(d) Cy + HBr — ?
75
Problem 6.15: Which alkene?
Br Cl
|
(c) CH3;CH,»,CHCH»CH».CHs (d)
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77 Stability of Carbocations and Markovnikov’s Rule More stable carbocation forms faster Tertiary cations and associated transition states are more stable than primary cations 80 Mechanistic Source of Regiospecificity in Addition Reactions If addition involves a carbocation intermediate and there are two possible ways to add the route producing the more alkyl substituted cationic center is lower in energy alkyl groups stabilize carbocation 81 6.10 Carbocation Structure and Stability Carbocations are planar The positively charged carbon is surrounded by only 6 electrons in three sp2 orbitals The fourth orbital on carbon is a vacant p-orbital
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Vacant p orbital
sp Ee
R’
120°
82
Heterolytic bond dissociations
energies:
10005 CHCl
i CH3CH,Cl
= 800+ (CH3)9CHCl - 191
s - (CH3)3CCl
82 600- | 143
gs
Ss
4 400 - 96
o
200 as
2
0
Methyl Ne 22 3°
@ 2004 Thomson/Brooks Cole
(keal/mol)
85
Stabilizing Carbocations:
a
Vacant p orbital
on this carbon. C-H bond more parallel
to p orbital.
C-—H bond perpendicular
to p orbital.
C—H bond more parallel
to p orbital.
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Problem 6.16 : carbocation structure?
CH, CH,
| |
(a) CH;3CH,C—=CHCHCH, + HBr —> ?
(b) [-cuon, +HI — ?
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90 Statement of the Hammond Postulate A transition state should be similar to an intermediate that is close in energy Sequential states on a reaction path that are close in energy are likely to be close in structure - G. S. Hammond carbocation G Reaction In a reaction involving a carbocation, the transition states look like the intermediate 91 Competing Reactions and the Hammond Postulate Normal Expectation: Faster reaction gives more stable intermediate Intermediate resembles transition state 92 “Non-Hammond” Behavior More stable intermediate from slower reaction Conclude: transition state and intermediate must not be similar in this case – not common 95 6.12 Mechanism of Electrophilic Addition: Rearrangements of Carbocations Carbocations undergo structural rearrangements following set patterns 1,2-H and 1,2-alkyl shifts occur Goes to give more stable carbocation Can go through less stable ions as intermediates Carbocation rearrangements:
ee
in ii 1 I
C HC H HC H
pos, Any t Ha DO, A + Do, J
4C C H H.C C H HC C H
| /\ /\
H H (Cl H dH
3-Methyl-1-butene 2-Chloro-3-methylbutane 2-Chloro-2-methylbutane
(approx. 50%) (approx. 50%)
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Hydride Shifts
——
rt " ae an
H,C \ H,C H Hydride H
= Notthy 7 PO eee ay “ain ng? ig ag
3
H H H H
3-Methyl-1-butene A 2° carbocation A3?° carbocation
|e lor
CH, 4H CH, H
H,C._| | LH H,C. | | -H
H~ So SH cl” “se “A
\ /\
H Cl H H
2-Chloro-3-methylbutane 2-Chloro-2-methylbutane
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