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Angular Frequency of Waves - Optics and Modern Physics - Solved Past Paper, Exams of Physics

This is the Solved Past Paper of Optics and Modern Physics which includes De Broglie Wavelength, Kinetic Energies, Normalized Wave Function, Ground State, Potential Height, Kinetic Energy of Electrons etc. Key important points are: Angular Frequency of Waves, Succession of Identical Crests, Half-Second Interval, Wave Speed, Frequency and Angular Frequency, Compute Wavelength, Propagation Constant of Waves

Typology: Exams

2012/2013

Uploaded on 02/23/2013

anushka
anushka 🇮🇳

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Download Angular Frequency of Waves - Optics and Modern Physics - Solved Past Paper and more Exams Physics in PDF only on Docsity! 2. A youngster in a boat on a lake watches waves that seem to be an endless succession of identical crests passing with a half-second interval between each. Each disturbance takes 1.5 s to sweep along the the length of the 4.5 m long boat and are 30 cm from top to bottom. a) What is the wave speed? The waves travel the 4.5 m length of the boat in 1.5 s, so the speed is v = 4.5 1.5 = 3 m/s b) What are the frequency and angular frequency of the waves? The period is 0.5 s, which makes the frequency ν = 1 0.5 = 2 Hz Then we can get the angular frequency by ω = 2πν = 2π(2) = 4π = 12.57 rad/s c) Compute the wavelength and propagation constant of the waves. Since v = λν, we have λ = 3 2 = 1.5 m Then k = 2π λ = 2π 1.5 = 4.19 m−1 d) Write down a wave function describing these waves, taking the positive x-axis to be in the direction of propagation. The general form of the wave equation solution is ψ(x, t) = A cos(kx− ωt) Putting in the values from above, and recognizing that the amplitude is one-half of the wave height (from crest to trough), we get ψ(x, t) = 0.15 cos(4.19x− 12.57t) It would be acceptable to have used sin rather than cos.
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