Answer Key Empirical and Molec Formula WS.pdf, Exercises of Chemistry

Download Answer Key Empirical and Molec Formula WS.pdf and more Exercises Chemistry in PDF only on Docsity! Name Key Period v Worksheet: Calculating Empirical & Molecular Formulas 1. The empirical formula for the compound having the formula H2C,0, is: [A] CoH [Cc] COH [D]}C,0.H, — [E] COH2 2. Calculate the empirical formula of a compound that is 85.6% C and 14.4% H (by mass). H 4 a ¢C 85.6 ayn et = 14,25_ COACH: ) [BCH IC]CHs DICH. EH “Teor gel hol oS 2 3. A compound is analyzed and found to contain 12.1% carbon, 16.2% oxygen, and 71.7% chlorine (by mass). Calculate the empirical formula of this compound. 2 fa he EE: ao) (ICO, —[e]Coaci_ |DJGoCK = feJCoc! ype HS 1600 4. A compound contains 40.0% carbon, 6.7% hydrogen, and 53.3% oxygen (by mass). Calculate the empirical formula. Be ' Catt Pe S33. “20! F, i = 3.3 1A) C220 | CH.D)IC] CHO [D] C,Ho2 [E] C3HeO3 ne “3 46 pa ae * 5. A compound contains 25.94% N and 74.06% O (by mass). What is the empirical forfhil la? Z25:949N_ 1,8. Tb 7 “ wef = | x2 = 2 [Was | T40lg O _ 1u.00 = H.b3 2 265 x2 > 5 6. Determine the empirical formula ofa compound containing 54.2% F and 45.8% S (by mass). Sa, 26h SS 35 aE : “9 " 2 3. . m =7i VAS 19.00 g/mol ~ Nsepgs |e eS 32.079/mo? wen a 7. Acompound has 40.68% carbon, 5.12% hydrogen, and 54.20% oxygen (by mass) Calculate its empirical formula. : 209 O HOW 35S = 3.387 Sil2gH _ 5.004 St26q = 3.397 Os 120O'4lonat S55 VON mal SA MOOG 5-397 =ly2<2 = 14 x2= 3 = 14222 8. A7.33-g sample of lanthanum, La, combines with oxygen to give 10.29 g of the oxide. Calculate the empirical formula of this oxide. 10.296 — 2.334 — 246g e& 7.33gl4 =,0527 29420 1S Bil g/mol 39887 —— pA = 1850 23.5 4927 21a nat O527 9. Calculate the molecular formula of a compound with the empirical formula CHO —_ and a molar mass of 150 g/mol 30 1s0 430-5 TA] CsH.O3 [C] CoHs02 [D] CeHeO, —[E] CoH 206