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Assignment 9 Solution - General Physic for Life Science Oriented Major | PHYS 2414, Study notes of Physics

HW9 Solutions Material Type: Notes; Professor: Abbott; Class: General Physics for Life Science Oriented Majors; Subject: PHYSICS; University: University of Oklahoma; Term: Spring 2010;

Typology: Study notes

2009/2010

Uploaded on 12/10/2010

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Download Assignment 9 Solution - General Physic for Life Science Oriented Major | PHYS 2414 and more Study notes Physics in PDF only on Docsity! Phys 2414 HW 4 colutions J. We ae given te initial angular velocity ond the change Mm Lime) SO We Cam USE ~ OW. We We © ~7OEY RPM A= Fe oi e 3 sec So We Now neck to Convert FOCO RPM to red. Zou rat Rs ge DSI Daag oe 3S 2. Pest lets convert le given aoseler veloety t0 ©) eed, Lo [RPM= 0.104 Ys We ane told that phe accele«son oemrs over « pervod of t= [Orn = OOO sec. Using d= eS, we have ol = GION OK {173 xiond of) CO See ee st (b) The eguntion dow rabtul acceleration is Gg wr So we rest need fo calcalate co aber FS prin = 200 see off actelerctin. So loz LE = (75 Klo 4!) (300 sce =O, 057 cal | oF S pew oar S64 ner () The fungensia| acceleration ts aver by Qean = XV 3. First, we need +0 Liv he auseler acce eration of _ Aw Wp= i the wheel, Using f= ee: ae we have 390 RpMr~ ZS KP es Converting RPM re eee we have 2 5 me, ~ 3,58 SE _ 65% = SS 2 OSs S. oss o Using le equation C= wy + IKO we have 6- js = 2774 ree. Converting qhis +0 vakians aives Oz j7U5 pad, y= re So X= Can)(is—[ 349 Nas, (. The conmifuye is a Solid cylinder; so T= tma= +(43)(0.01 wy = 0.017 Kart We Cun use Ae Lace ther there (SS @ Constanp Frierimal porgee applied ro Finl rhe ansulem acceleatim, So, oe _ = Onn - ad te-DTx =) w= Z = Laan loota? --66,.67 Yn =-10.61 "h VCS Now to find the number ot yevolutions, We Can Use - 2 toa, lots WEt IAG =F ose = 28% rev bene Ww=0 (a, \Hooo rem t= -1oel 7 The amount at Hime Can be Powel by using _ Zw We o= SP => |] ty aq. 1 =VULS po 1 We vont lod tle Kmetic Evesy ot rhe ball, thick oy ae by KE= Abe Vin + t Tencv® aud or. We are Bien wv. 4q°4 - 5y,.y oe r= 0.04m C= ¥ > ooqm me 71 BS Lem = SMR E(qiN(Q01) = ©, 023 Kgn* ve 4% Se 2 ltd #g) (4. a + (0.023 ha ve (su. 44 ad) i Using Con Servetion ot enesy, we a2 Pyke kDwr = bebo . foe Lssm) Since the center of mass of the folk is ae $4, fee = 1 (3.49) = |. 59h t Zz 6 eo ae eee spud “%, = 616 “Ys Movs out we teow rhe gular welocity, Ve tor => Where ris tL, So
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