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Chapter 4:
Bandpass Modulation and Demodulation
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Today’s Agenda Review Differential Phase Shift Keying D8PSK Example docsity.com
7 If v,(t) = Acos(@)t + 45°) and w,(t) = Acos(@pt — 45°)
: Decision:
1. Calculate z,(t) as
2) = fr) w (Oat
2. Find the quadrant of (Zp), 24)
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4.6 Complex Envelope
= Areal bandpass waveform s(t) can be represented using complex
notation sect
s(t) =Re{g(e""}
Where g(t) is known as the complex envelope, expressed as:
= The magnitude of the complex envelope is:
RN=|gMl=yr Orv
= And its phase:
I(t
a(t) = tan! 2
x(t)
= g(t) is called the baseband message or data in complex form and
e/"0', the carrier wave in complex form
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= Then the modulation can be expressed as the product of the two
s(t) = Re{[ x(t) + jv(t)] [cos @,f+ jsin @t]}
= x(t)cos @,t—- y(t)sin @yt
4.6.1 Quadrature Implementation of a Modulator
= Consider a baseband waveform g(t) appearing at discrete times k
=1,2,..., Then g(t), x(t) and y(t) can be written as g,, x,,y,. Let x,=y,
=0.707A; Then complex envelope can be expressed in discrete form
as! g, =x, + jy, =0.707 A+ j0.707 A
= The modulation process suggests:
s(t) = Re{g, e”””}
= Re{[ x, + jv, ] [cos o,f + jsin a,t]}
= xX, COS W ,f- y, SM Oy
1
= 0.707 Acos w,f-0.707 Asin @,f = Acos [oy + 4)
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= Detector in general calculates the
coordinates of the incoming signal
by correlating it with locally
generated waveforms such as:
\2/T cosw,t and V2/T sinwgt Angie
measured
by datector
ysl)
Ld (ay : by}
Stored
signal vector
(ag, bz) 6
Currently
= The detector then measures the = _ ved
signal vector
angle between the currently
received signal vector and the
previously received signal vector.
a
th
ym 20M
fet, M
in wylt)
Fig 4.16 — Signal space for DPSK
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4.5.2 Detection of Binary PSK
Differential Encoding
message (first bit
arbitrary), d,
Sample Index,k 0 |1 12 6 |7 |8 |91]10
Information Message, a, 1 11 1 11 0 );0]1
Differentially Encoded 141 41 141 {0 1171
shift, 6,
Corresponding phase 070 |0
Encoding Schemes
d, = di, ® ay,
d, = di ® ay,
@
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Decoding Scheme
r(k)
n
a, =n, On,
a(k)
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