Docsity
Docsity

Prepare for your exams
Prepare for your exams

Study with the several resources on Docsity


Earn points to download
Earn points to download

Earn points by helping other students or get them with a premium plan


Guidelines and tips
Guidelines and tips

Beam Design - Laboratory 3 - Concrete Construction | BCM 38000, Lab Reports of Civil Engineering

Material Type: Lab; Class: Concrete Construction; Subject: BCM-Bldg Construct Mgmt Tech; University: Purdue University - Main Campus; Term: Spring 2007;

Typology: Lab Reports

2010/2011

Uploaded on 09/01/2011

koofers-user-5ur-1
koofers-user-5ur-1 🇺🇸

10 documents

1 / 5

Toggle sidebar

Related documents


Partial preview of the text

Download Beam Design - Laboratory 3 - Concrete Construction | BCM 38000 and more Lab Reports Civil Engineering in PDF only on Docsity! BoM 380 Sc Spring 2007 e Lab # 3 — Beam design / Show ail calculations w PWV VV WV VV VI VV VV VV VV WI al | oe | f | | I 1 For the beam shown above, find the largest load w, the beam can support if bending controls. The bending stress allowable is 1750 psi and the beam is a two-ply 2x6 stringer. L is equal to 4’- 4.” 2. Find the largest load for the beam if shear controls and everything else remains the same as in problem #1. The @ allowable shear stress is 180 psi. 3. What is the allowable load for the beam if the deflection must be limited to 1/360? The modulus of elasticity is 1.5E6 psi and everything else is the same as in problems | and 2. 4. Is the capacity of the beam above controlled by bending, shear, or deflection? Explain. 5. What is the largest span for the beam if it is a single 2x8 and has a load w equal to 248 pif? Assume the wood properties remain the same and the deflection must be less than L/270, 6. Whar is the smallest standard size lumber beam that will carry a load of 375 pif when supported as above with a span of 3’- 6” and an allowable bending stress of 1400 psi, shear stress allowable of 140 psi, and an E = 1. 4E6 psi. Deflection must be limited to 1/240. ob #3 BUM 380-1 | Seg Wo TE= 150 Whit ~ ut Blstel99 5 ) 2°82 in Meox Yo =i 72.9333 ws bh (BUNS SIS a? Hy Q1.59330 2-7 Fi0)_ " vo: Binh S50) TASALS te Sue? eae RAI y Shes 1.45%, (50> upto aya Tee . ', Gialssiy Hi Sin" : wt (74.54. “HR we 1175 a — : \ 2) B+ 190 tof : - a Vlog? bw * 312 / we 762 lal 27 Svunr? Pept ABEL = 1 2aeF uy = Wo Met G3, Hb Min, TR > Te1.50 la, Wier” Qt — Z(Bin[5-Si0.) 7 iaes E* 19 EG psi A? fe * 52} 500 = JAGAIs. . ee. (s2igf 2 GTBSAE TS wy + 44H Bonn * GPE) ~ (UMAIS EG fie” L. “ anes a) s) 2 2HY 4s Mga. 0 * {o> 2144 Fhe] a fo capacity of thar beam 15 convolled by shear becaase He load allonawle by sheav shes» is Aeasticatly less fae Yr lady allowed toy boendiag Z doSsechou - Wet, se bat, USI), ar £|270 1 we 1D = 47b7ia® Le 270 MSEE 2 gh ee a] (28m 0% 5o te OST. gic ee 478 a S €[D + torn % §.98 . bag > a Spe OF he 105 }y, ne
Docsity logo



Copyright © 2024 Ladybird Srl - Via Leonardo da Vinci 16, 10126, Torino, Italy - VAT 10816460017 - All rights reserved