Download Chapter 04-Electrical Circuit Analysis-Problem Solutions and more Exercises Electrical Circuit Analysis in PDF only on Docsity! Chapter 4, Problem 1. Calculate the current io in the circuit of Fig. 4.69. What does this current become when the input voltage is raised to 10 V? Figure 4.69 Chapter 4, Solution 1. + − 5 1 41 1i = + =Ω=+ 4)35(8 , === 10 1i 2 1io 0.1A Since the resistance remains the same we get i = 10/5 = 2A which leads to io = (1/2)i = (1/2)2 = 1A. docsity.com Chapter 4, Problem 2. Find vo in the circuit of Fig. 4.70. If the source current is reduced to 1 μA, what is v ? o Figure 4.70 Chapter 4, Solution 2. A 2 1ii 21 ==,3)24(6 Ω=+ , 4 1i 2 1i 1o == == oo i2v 0.5V 0.5μVIf i = 1μA, then vs o = docsity.com Chapter 4, Problem 5. For the circuit in Fig. 4.73, assume vo = 1 V, and use linearity to find the actual value of v . o Figure 4.73 Chapter 4, Solution 5. + − V21 3 1V1 =+⎟ ⎠ ⎞ ⎜ ⎝ ⎛=If v = 1V, o 3 10v 3 22V 1s =+⎟ ⎠ ⎞ ⎜ ⎝ ⎛= 3 10If v = v = 1 s o =15x 10 3 Then vs = 15 vo = 4.5V docsity.com Chapter 4, Problem 6. For the linear circuit shown in Fig. 4.74, use linearity to complete the following table. Experiment V Vs o 1 12 V 4 V 2 -- 16 V 3 1 V -- 4 -- -2V Linear Circuit + _ Vs Vo + – Figure 4.74 For Prob. 4.6. Chapter 4, Solution 6. Due to linearity, from the first experiment, 1 3o s V V= Applying this to other experiments, we obtain: V Experiment Vs o 2 48 16 V 0.333 V 3 1 V 4 -6 V -2V docsity.com Chapter 4, Problem 7. Use linearity and the assumption that Vo = 1V to find the actual value of V in Fig. 4.75. o . + _ 4 Ω 3 Ω 2 Ω 4 V + _ Vo 1 Ω Figure 4.75 For Prob. 4.7. Chapter 4, Solution 7. If Vo = 1V, then the current through the 2-Ω and 4-Ω resistors is ½ = 0.5. The voltage across the 3-Ω resistor is ½ (4 + 2) = 3 V. The total current through the 1-Ω resistor is 0.5 +3/3 = 1.5 A. Hence the source voltage = + =1 1.5 3 4.5 Vsv x If 4.5 1sv V= ⎯⎯→ 14 4 0.8889 V 4.5s v x= ⎯⎯→ = = 888.9 mVThen . docsity.com