Docsity
Docsity

Prepare for your exams
Prepare for your exams

Study with the several resources on Docsity


Earn points to download
Earn points to download

Earn points by helping other students or get them with a premium plan


Guidelines and tips
Guidelines and tips

Chapter 04-Electrical Circuit Analysis-Problem Solutions, Exercises of Electrical Circuit Analysis

This is solution to problems related Electrical Circuit Analysis course. It was given by Prof. Gurnam Kanth at Punjab Engineering College. Its main points are: Circuit, Source, Current, Input, Voltage, Y, Transform, Equivalent, Nodal, Analysis, Resistors

Typology: Exercises

2011/2012
On special offer
30 Points
Discount

Limited-time offer


Uploaded on 07/20/2012

anumati
anumati 🇮🇳

4.4

(100)

111 documents

1 / 9

Toggle sidebar
Discount

On special offer

Related documents


Partial preview of the text

Download Chapter 04-Electrical Circuit Analysis-Problem Solutions and more Exercises Electrical Circuit Analysis in PDF only on Docsity! Chapter 4, Problem 1. Calculate the current io in the circuit of Fig. 4.69. What does this current become when the input voltage is raised to 10 V? Figure 4.69 Chapter 4, Solution 1. + − 5 1 41 1i = + =Ω=+ 4)35(8 , === 10 1i 2 1io 0.1A Since the resistance remains the same we get i = 10/5 = 2A which leads to io = (1/2)i = (1/2)2 = 1A. docsity.com Chapter 4, Problem 2. Find vo in the circuit of Fig. 4.70. If the source current is reduced to 1 μA, what is v ? o Figure 4.70 Chapter 4, Solution 2. A 2 1ii 21 ==,3)24(6 Ω=+ , 4 1i 2 1i 1o == == oo i2v 0.5V 0.5μVIf i = 1μA, then vs o = docsity.com Chapter 4, Problem 5. For the circuit in Fig. 4.73, assume vo = 1 V, and use linearity to find the actual value of v . o Figure 4.73 Chapter 4, Solution 5. + − V21 3 1V1 =+⎟ ⎠ ⎞ ⎜ ⎝ ⎛=If v = 1V, o 3 10v 3 22V 1s =+⎟ ⎠ ⎞ ⎜ ⎝ ⎛= 3 10If v = v = 1 s o =15x 10 3 Then vs = 15 vo = 4.5V docsity.com Chapter 4, Problem 6. For the linear circuit shown in Fig. 4.74, use linearity to complete the following table. Experiment V Vs o 1 12 V 4 V 2 -- 16 V 3 1 V -- 4 -- -2V Linear Circuit + _ Vs Vo + – Figure 4.74 For Prob. 4.6. Chapter 4, Solution 6. Due to linearity, from the first experiment, 1 3o s V V= Applying this to other experiments, we obtain: V Experiment Vs o 2 48 16 V 0.333 V 3 1 V 4 -6 V -2V docsity.com Chapter 4, Problem 7. Use linearity and the assumption that Vo = 1V to find the actual value of V in Fig. 4.75. o . + _ 4 Ω 3 Ω 2 Ω 4 V + _ Vo 1 Ω Figure 4.75 For Prob. 4.7. Chapter 4, Solution 7. If Vo = 1V, then the current through the 2-Ω and 4-Ω resistors is ½ = 0.5. The voltage across the 3-Ω resistor is ½ (4 + 2) = 3 V. The total current through the 1-Ω resistor is 0.5 +3/3 = 1.5 A. Hence the source voltage = + =1 1.5 3 4.5 Vsv x If 4.5 1sv V= ⎯⎯→ 14 4 0.8889 V 4.5s v x= ⎯⎯→ = = 888.9 mVThen . docsity.com
Docsity logo



Copyright © 2024 Ladybird Srl - Via Leonardo da Vinci 16, 10126, Torino, Italy - VAT 10816460017 - All rights reserved