Characteristic Permanent Action - Introduction to Structural Design - Old Exam Paper, Exams of Structural Analysis

Download Characteristic Permanent Action - Introduction to Structural Design - Old Exam Paper and more Exams Structural Analysis in PDF only on Docsity! CORK INSTITUTE OF TECHNOLOGY INSTITIÚID TEICNEOLAÍOCHTA CHORCAÍ Semester 2 Examinations 2009/10 Module Title: Structural Design Module Code: CIVL7018 School: Building and Civil Programme Title: Bachelor of Engineering in Civil Engineering - Award Programme Code: CCIVL_7_Y3 External Examiner(s): Ms. M. Kyne, Mr. J. Murphy Internal Examiner(s): Dr. N. Power, Ms. S. Corcoran Instructions: Answer all questions Use separate answer books for each section Duration: 2 Hours Sitting: Autumn 2010 Requirements for this examination: Candidates may refer to 1. PP1990:2007 – ‘Structural Eurocodes’ Extract from Structural Eurocodes for students of structural design 2. PP7312:2002 - ‘Structural Design’ Extracts from British Standards for students of structural design 3. ‘Approved Design Aids’ – (CIT Booklet) Note to Candidates: Please check the Programme Title and the Module Title to ensure that you have received the correct examination paper. If in doubt please contact an Invigilator. Pad Footing B3 Design the pad footing to column B3. (Assume a pinned connection between column and its footing). Design Information: Exposure: moderate Loading: NService = 925kN NUltimate = 1235kN Materials: Concrete: C35 Reinforcement: fy = 460N/mm 2 Soil Conditions: Safe bearing capacity of the soil at formation level = 220kN/m 2 A B C D E 5000 5000 5000 5000 1 2 3 4 4 5 0 0 4 5 0 0 4 5 0 0 S la b S la b 475 x 250 T Beam 475 x 250 T Beam 475 x 250 T Beam Stairs/ Lift Stairs/ Lift All columns are 275 x 275 PLAN ELEVATION Roof 2 nd 1 st 2 7 0 0 2 7 0 0 GENERAL OFFICE GENERAL OFFICE PIN PIN PIN PIN PIN FIG. QA2 fnd. 3 0 0 0 General won Layer Lightweight Mortar of Density . . lortar (Bed Masonry Unit Purpose | saint >0. 600< pis 800 | 800<py<t Mortar | Joint 0.5 mm kg/m? 300ky/m? and <3 mm ) gf’ S/n Group 1 0,55 0,75 03 04 Group 2 045 0,70 0,25 0,30 Clay Group 3 035 0,50 0,20 0,25 Group 4 0,35 0,35 0,20 0,25 Cateium Siticate | OP! 0,55 0,80 i t Memumement® | Group 2 0,45 0,65 t t Group 1 0,55 0,80 0,45 0.45 Aggregate Group 2 0's 0,65 0,45 0.45 Conerete Group 3 0,40 0,50 t i Group 4 0,35 i t t Autoclaved Aerated Group 1 0,55 0.80 0,45 0.45 Concrete Manufactured 5 rn 4 7 [ cious Group 1 0,45 0.75 t t ‘ “ « Natural Stone | tour | 0,45 i t § Class of Execution Control: ~ ™ 4” (Special) 5° (Normal) Material Masonry made with: Units of Category I, Designed Mortar®? 2,2 2,5 Units of Category I, Prescribed Mortar“? 2,5 2,7 Units of Category II, Any Mortar®°?-# 27 3,0 Anchorage of reinforcing steel 2,5* 2,7" Reinforcing steel and prestressing steel LIs* 1,157 Ancillary Components“! 2,5 27 Lintels in accordance with IS EN 845-2 See NA to IS EN 845-2_| See NA to IS EN 845-2 Equivalent Prescribed Mortars (Proportion of Materials by Compressive Volume) (see Note, Strength Cement : Lime : Cement : Sand with or Mortar A) Sand with or Mason: = hi Designation Class”) 7 without Air without Air Cement : Sand ‘Hutraiament Entrainment M12 1:0to%:3 Not suitable Not suitable (i) M6 1:%:4to4% 1:2%to3% 1:3to4 (ii) M4 1:1:5to6 1:4to5 1:5to6 (iii) M2 1:2:8t09 1:54 to 6% 1:7 to 8 (iv) Question B2 (25 marks) i) What is the load bearing capacity of the stud wall illustrated in Fig.QB2. Express your answer in terms of a uniformly distributed load, in units of kN/m ii) Determine what effect, reducing the c/c’s of the noggings to 1000mm has on the bearing capacity of the stud wall. Refer to loading and design information in accordance to the appropriate code – EC5 and BS 5268. Figure QB2 Timber Stud Wall DESIGN INFORAMTION for EC5 Durability: Class 3 Loading Duration: Medium and Long term Material Data: C22, wtimber = 5kN/m 3 DESIGN INFORAMTION for BS5268 Durability: Dry Exposure Loading Duration: Long term Material Data: C22, wtimber = 5kN/m 3 EN 338-2003 (E) Table 1— strengin classes - characteristic valuss Poplar and softwood species Hardwood species cM [s* is 0 | c2z [em [ez [= [“ [* [= B30) [P= DEO) [Pp | 70 Sirengih properties (in Nim") Bending Taw w]e )@ jo |= l= jv] = )m |S |u| |= | jo leo |r Tension paralle! fm = (8 ta fat fez fas fre fae at [a4 30 a1 [oe [so }ae |a2 Tension perpendicular | fq, [04 [05 [05 os jos jos jos joe joe os joe joe joe fos jos Compression parallel fy, | 16 [47 |1a |sa foo Jor Jz Joa jas | 28 2a jaa fos Joe |oo |az | 24 Compression fi 22 |2a |24 26 |27 |28 a1 [32 |ao ar perpendicular same f 20/22 |24 J25 |28 |20 [24 as jas |ao [34 46 Shear a Stiffness properties (in kNimm”) Mean modulus of er a mw yt [ws] w@ [i [iw [mo [wo pa elasticity parallel modulus of elasticity parallel Eom = fT [5A 10.0 rie | 14a] tee Mean modulus of Emme | 0.23 | 0.27 0.50 0.93 | 1.13] 1.23 elasticty perpendicular Goon | 044/05 083 4.00 | 0,60 | 0,68] 0,70 | 0.88 | 1,08 | 1,25 Mean shear modulus