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Charge per Unit Area - Introductory Physics - Solved Paper, Exams of Physics

These are the notes of Solved Paper of Introductory Physics and its key important points are: Charge Per Unit Area, Nonconducting Rod, Electric Field, Charge Per Unit Area, Metallic Strip, Magnetic Field, Current Density, Hall Effect

Typology: Exams

2012/2013

Uploaded on 02/12/2013

sathianarayan
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Download Charge per Unit Area - Introductory Physics - Solved Paper and more Exams Physics in PDF only on Docsity! FROM : FAX NO. t Mar. @? 2882 12:29PM PL Physics 8B Spring 2002 (Section 2) MIDTERM 1 Useful data: &) = 8.85 x 10°? CUN-m’ o- be k= 8.99 x 10° N-m/C? Ad e=i6x10PC : : . +3 Each problem is worth 10 points. L a& 1. In the diagram, what is the potential at point _ —_ P? Assume g = 1.0 pC and d = 0.30 m. +eoaO*@P a tee 2. Along, thin nonconducting rod has a charge per unit length of -5.0 x 10° Cém uniformly distributed along its length. The rod is located along the axis of a conducting cylindrical shell with inner radius 10.0 cm, outer radius 20.0 cm, and a net charge per unit length of +8.0 x 10” C/m, What is the magnitude and direction of the electric field at a distance from the rod of (a) 5.0 cm, (b) 15.0 cm, (c) 25.0 cm? What is the charge per unit area (not per unit length!) on the (d) inside surface and (e) i 2 outside surface of the shell? CronpeSectronel weew In the diagram, what is the charge on and potential difference across the 4.0 [LF capacitor? 100V In the circuit, find the current going through each battery, and the power of each hattery, stating + — ¢oy 4 Of whether energy is supplied or absorbed by it. qav t=20v A current of 3.0 A is passing through a metallic strip of width 5.0emand , : thickness 0.20 mm (thickness refers to the dimension going in and out of Jb the page). There are 8.5 x 10 conduction electrons/m’ in the strip. A magnetic field of 0.40 T is applied perpendicular to the strip (out of the page). (a) What is the current density? (b} What is the electron drift . soe velocity? (¢) What are the magnitude and direction of the electric field resulting from the Hall effect? FROM : FAX NO. f Mar. @? 2aA2 12:29PM Pe Phy sea Pe deehen, 2. Sper 2002 Midteren #1 Salatrens Midterm 8D Lolatens oO -1 (2-2 4- &), ran Ure, & & 2 a 2 z D re, 4 CLo ato §) Lec hes cio) (420) wy Lovjot Vv ( Mar. @? 2842 12:51PM PS FROM + FAX NOL t 4 Go armed le tt fovy coun ttre lack wrae! ay +3 9.9 -N.Ov-6.9+9 et ‘ : Fu (5) 2 =e Ot OL A ey, | 7? Go arowk owe loup c loubucers 6.0 —~ Yor, -j.0 20 St hoa 3 “? Funct rales Cp Hee ty eye “poe >= 0.15 & 0 = (6.060.795)? ¥0W trey ny r - ES 1 i 1 eos C4T00G2E) + VI Peels YY Re Fey Bycp e Colctar + 2.0 Wy Abra’ G Couerent oppart emt) FROM : FAX NO. of S fal Ts ez FO - (@ocVoare4re7*) ° Foxfa T Atwt ® 6) Tenew TD. Porso™ Va > he CPS e QV Gere) 2 2,2 4107 My @ 2 O12 +107 NCO Ye} > pRepo! He @D and feted gaer He Jett) @ 4 4 4 £ ant yyy Mar. @? 2842 12:31PM Feel eR cy AK lebh rs elector mn h lett, Pe
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