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Circle Motion - General Physics - Past Exam, Exams of Physics

It is the notes of Past Exam of General Physics which includes Air Resistance, Rock of Mass, Circular Shape, Speed of Roller Coaster, Moment of Inertia, Mass of Plank etc. Key important points are: Circle Motion, Identical Blocks, Same Radius Turn, Vertical Height, Force on Friction, Arc of Vertical Centre, Number of Revolutions

Typology: Exams

2012/2013

Uploaded on 02/07/2013

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Download Circle Motion - General Physics - Past Exam and more Exams Physics in PDF only on Docsity! rey Physics 220 — Exam AZ March 4%, 2002 This exam consist of 10 problems that are worth 10 points each for a total of 100 paints, Please check that you have all af the questions. Fotraulas and constants: voy, Lat neu t+ O48 at yee st + OS ar voy + Jax view! + Zay xothdi(y, + v0 yy, byt F=ma Foun = Ee fw 7, (Static fever} Fou. = py N (sliding friction) aover KE=(.5m¥" PE gniny = MBH W = Fal coed power = work/At p=my Ap = impulae = F At G= 6.67 2 1" Noth Mass of the Earth = 4.93 x HP ke Radius of the Earth - 6.38% 1° m Mass of the Mars = 6.43 x 10" leg Radzus of the Murs = 3.37 x 10" m g= 98 mi! Ll, AS) kw sack of coal is dropped on a 2000 kg tailpoed Alatear that was initially moving at 3.0 ms. After the sacks tests ott the flaicar, find the speed of the flatear in ms: fy) 06 m, 2 Sooks M2 + toow ky o ‘ Mp = © ‘25 = 3. vs (4) 42 = 3 (5) OR Rs 5 (a) 5.7 () 36 mvt Me, = Cm tm Vv, (1B O16 5 ED Vy 2 Te + Mz Veo my, tine : zon} (3) Ve = Gey s 24s 2 Seb 2. Two identical blocks in the figure are released simuliancously from rest on # frictionless inclined Plane. A staris at the top, and B starts halfway down. Lf the time it takes to reach the bottom of the ramp is t, for block A and 1, for block B. Then t/t, is: i} i Gp & 2 4 033 {B {3} 25 6 4 {7} as (8) 8 m 6 Ke Block A (1) V2 For Blect B hye tha . ma dhe = Vy Werk 3 7. Inan automatic clothes drier, a hollow cylinder moves the clothes on a vertical circle (racing = 0,32 mj. The appliance is designed so that the clothes tumble gently as they dry. This means that when a piece of clothing reaches an angle 6 above the horizontal, it loses contact with the wall of the cylinder and falls onto the clothes below, Find the number of revolutions per second that the cylinder should make in order that the clathes lose contact with ihe wall when 6 = 70". (U 1? (4) (5) (6) (7) (8) (3) 1g) [cos = cos (qo-eh = Smo 2.1 75 O82 13 O12 thal 31 Fab ene my ost Ni = Io-e Le “4,9 o Efe tN Ungiesp = -mt ~ pra Sin o = av — r Vs ¥rg sing wt: ¥ ~ Vegding — To ate FO Rpe = OES Hy 6. A basketball Gm = 0.60 kg) is dropped érom rest. Just before striking the floor, the magnitude of the basketball's momentum is 3.1 kg m/s, Find the height (in meters) fom which the basketball was dropped. il) 026 (2) 1S GB 04s (4) 082 (S033 (6) 0.75 at (B} 27 @ 32 {10 0.01 + was F, Gy 723 ms 9, A projectile of mass 0.750 keg is shot straight up with an initial speed of 18.0 ms. If the projectile Tises to a maxinvnum height of only 11.8 m, find the magnitude of the average force (in Newtons) due to air resistance. pms o-7s0 ks Anay = ig he (I) 1.03 V¥, = 18.5 my (293 (3) 7.35 (4) 4.90 We = AKE +44PE = Fd cosa {5} 8.12 (5.93 (7) 0.397 Ym (poe) 4 ing Chg ~ he) => Fdeos Hos - FQ (@) 0.623 b08 2 Wm) Fe emi = mah 2 295n d 10. Masses mI and m2? ate connected by a massless string of fixed length that goes over a massless frisionless pulley, Ag mass mi falls due to gravity, m2 pulls mass m] actos the table. The coefficient of kinetic friction between ml and the table is p,. Find the tension (in Newtons) in the string, Assumc mi =m2=2.0kg, and p, = 16 ’ (42 2} 368 FBR for me @ 98 {6} a i F (7) 0.381 3) 126 ao (3) bs FOR fon mi Jhyeo > New,sd => NeW, = og cn mo 0 : Zfys Tf ema w (®~ T= my, 4 +f, ust (MEH Te ™.mg (144) = thew 6 Mate,
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