Circuit Analysis Using Nodal, Thevenin, and Superposition, Exercises of Electrical Circuit Analysis

Download Circuit Analysis Using Nodal, Thevenin, and Superposition and more Exercises Electrical Circuit Analysis in PDF only on Docsity! #1 NODAL Ve = My 7 GC 2) ye Ne = Vg 2 éq.1 V+elirlg ote Eg.a A Tas Tales 1’ by. Lo ale — (-% Ta * see! = #7 CS) TH? oO.24 —_—_ 2 - Yo-w = o- (-2) Be Goes Xf Bz oA & %eG7F 1 ee ( T2 = 2thth= 2to.2r +3 ne BA % S.&eTA #1 THEVENIN = foif[e +4 ~ & t¥ Rae = 4u ee Rn vine MeN Veen -Va 84.2 Vez Va +2 M@>= -Vm4t2 €4.2 @t+l2 = Th %.3 b> Ty th +7 C4. + Rt = A pw - Vote = A Re awl SR. = Vas 2M Te =. ETHTRE 4 42 a KF 32.007 A O.2Ay — = t —— a + 2-0cOoTA Lal w& v wn \e on | > : #2 NODAL W Newel + : ak “°° T2> Utlo tT - %i, 20 rNi-vs _ “e-Va | > | . {fNv- Va 3 (2 Ven) a 3 i 2 z (> OV2-4N4 - V2 =O ON -2Va = 2N2 7 EN2 +G0 Sa - 2¥2 ~PVq = Go Ee. 4 pe 4V, +0V2 =O _&- S os = - r =~Eege= Vig 3 oe = ~4¢(fe =" ee © 2 © 7 = va -Y3 3 8 -¢ Va-Ve\ pole Vo = -64V wT ~ @ A 7 \ : Ny _ = 3 (yo) - @(-6 ~ he *? 43 2 go) ~ eC BNA-Na = Ne aN: pe 43 2 nee BNA -@Va 7 tvs =O Cq-G Mee lsq-V fq 446 ix 426 25 Mp = leva ~ 15 V9 = 300 Is Va -@V2 -~1 n= 18° 2 =O ee a + $4 teve __=— eDet ee See : = (FO ay . t2Ve - SVs 33Va = tS Ve = 308 &.T ms € Ls 7 : . 30V_ -10V,-= S40 ee = 3°90 = 3534 153 on BNE ~Ete = 3 ______—— 3——___— V4 -Va th a. hs ae A Voge St es hag, To toeh stesso Ne VA = 2 > ee - i ~ 4 -O¢ ~%0 2 #3 NODAL ve =_va -€3) yet Vet+3 £94 =, baal Ty = Ta +0n &%. 2 26n To= it +Iy €9.3 Ca, 22% Ia = fo +e tly Ta -In-i-Iy =o cy¢