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Discrete Structures Exam 1 for CMSC 203, Fall 2008, Exams of Discrete Structures and Graph Theory

The fall 2008 exam for the discrete structures course (cmsc 203) at the university level. The exam covers various concepts such as sets, functions, logic, and partitions. It includes multiple choice questions, a truth table, and a problem-solving section.

Typology: Exams

2012/2013

Uploaded on 04/27/2013

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Download Discrete Structures Exam 1 for CMSC 203, Fall 2008 and more Exams Discrete Structures and Graph Theory in PDF only on Docsity! Fall 2008 CMSC 203 Discrete Structures Exam 1 1. Circle T for True or F for False as they apply to the following statements: T F The negation of a Conjunctive statement is a Disjunctive statement . T F The negation of an Existential statement is a Universal statement. T F Non-empty sets have at least 2 subsets. T F If F:A → B is function, then F = A × B. T F For any sets A and B, (A ∪ B) ⊆ (A ∩ B). T F The empty set has no subsets. T F N ⊆ Z ⊆ Q ⊆ R ⊆ C. T F Finite sets are Countable. T F That All cars have steering wheels and A motorcycle does not have a steering wheel implies A motorcycle is not a car is an example of Universal Modus Tollens. T F If s is a string over an alphabet Σ, and s is in Σn, then the density of s is n. 2. Find the truth table for the compound statement: [( p ⊕ r) ∨ q] → [p ∧ (¬r → q)] 3. Find the related forms of: For all Integers, x, if x is even, then x is a multiple of 2. CONVERSE: ___________________. NEGATION:_____________________________. 4. Circle the appropriate response when the given argument illustrates Universal Modus Ponens (MP), Universal Modus Tollens (MT), Converse Error (CE), or Inverse Error (IE), : MP MT CE IE All cats eat mice and Tiger is a cat therefore Tiger eats mice. MP MT CE IE All cats eat mice and Tiger is not a cat therefore Tiger does not eat mice. MP MT CE IE All cats eat mice and Tiger does not eat mice therefore Tiger is not a cat. MP MT CE IE All cats eat mice and Tiger eats mice therefore Tiger is a cat. 5. Show that the function f : Z → Z defined as f(x) = (x − 3) is a bijection. 6. Calculate the following (assuming all strings are from the alphabet {0, 1}): (a) |{1, 2, 3} × {4, 5, 6, 7}| (b) d(10010101011001) (c) H(001001100011 , 100101010010) (d) 7. (a) Let f = {(0, 1), (1, 2), (2, 3), (3, 4), (4, 0)}. Find f ° f ° f ° f . f ° f ° f ° f = {(0,___), (1,___), (2,___), (3,___), (4,___)} (b) Find the Inverse of the function of f . f −1 = {(0,___), (1,___), (2,___), (3,___), (4,___)} 8. Use the logic of valid arguments to determine whether or not we can deduce p: p ∨ q ¬t r → s ¬s ∨ t q → r 9. Given a set A and a collection of non-empty subsets of A, {A1, A2, A3, ..., An}, we call this collec- tion a partition of A provided: (i) (A1 ∪ A2 ∪ A3 ∪ ... ∪ An) = A, and (ii) Ai ∩ Aj = ∅ when i ≠ j. (a) What set is partitioned by the collection { {1, 3, 4}, {2, 5}, {7, 8, 9} }? (b) Why is the collection of intervals of the Reals, {... , [−3,−2], [−2,−1], [−1,0], [0,1], [1,2], [2,3], ...} NOT a partition of the Reals? (note: [a,b] = {x ∈ R | a ≤ x ≤ b}. 1.5– 4+( ) 3.7 4+( ) Docsity.com
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