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Cu(II) vs. Cu(I): Properties, Oxidation, and Stabilization of Copper Ions, Exercises of Chemistry

Inorganic SynthesisElectrochemistryPhysical ChemistryChemical Equilibria

This document compares the properties, electronic configurations, and oxidation states of Cu(II) and Cu(I) copper ions. It discusses the paramagnetic and diamagnetic nature, colors, and stability of these ions in various compounds and solutions. The document also covers the synthesis and stabilization of Cu(I) in solid and aqueous chloride solutions, as well as the relative stability of Cu+ and Cu2+ complexes.

What you will learn

  • How does the presence of certain anions or complexing ligands affect the stability of Cu(I) in aqueous solutions?
  • What is the role of LeChatelier's Principle in the synthesis of copper(I) chloride?
  • What are the electronic configurations and magnetic properties of Cu(II) and Cu(I) ions?

Typology: Exercises

2021/2022

Uploaded on 09/12/2022

jimihendrix
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Download Cu(II) vs. Cu(I): Properties, Oxidation, and Stabilization of Copper Ions and more Exercises Chemistry in PDF only on Docsity! Cu(II) vs. Cu(I) ! Cu(II) is the stable state of copper. i Configuration 3d 9 with one unpaired electron makes Cu(II) compounds paramagnetic. i Incomplete 3d subshell permits d-d state-to-state electronic transitions, which causes color (typically blue or green). ! Cu(I) is an unstable state of copper. i Configuration 3d 10 with no unpaired electrons makes Cu(I) diamagnetic. i Complete 3d subshell precludes d-d state-to-state transitions, so Cu(I) is colorless like isoelectonic Zn(II). º Cu(I) compounds may be colored with certain anions CuI(s) — pale yellow Cu2O(s) — brick red i Fehling's solution, an alkaline solution of Cu2+ with sodium tartrate, reacts with reducing sugars such as glucose to give brick red Cu2O. Oxidation of Cu(I) ! In aqueous solution, Cu(I) is readily oxidized to Cu(II) in the presence of oxygen: 4(Cu+ º Cu2+ + e–) –Eo = –0.153 V O2 + 4H+ + 4 e– º 2H2O Eo = +1.229 V 4Cu+ + O2 + 4H+ º 4Cu2+ + 2H2O Eo cell = 1.076 V ! Cu(I) undergoes spontaneous disproportionation (autoredox): Cu+ º Cu2+ + e– –Eo = –0.153 V Cu+ + e– º Cu Eo = +0.521 V 2 Cu+ º Cu + Cu2+ Eo cell = +0.368 V i Thus ∆G is negative (spontaneous) for disproportionation. Stability of Cu+ vs. Cu2+ Complexes L Position of the 2Cu+ º Cu2+ + Cu0 equilibrium in the presence of complexing ligands depends on the relative stability of the Cu+ complex relative to the Cu2+ complex. ! Anions or bridging ligands that form complexes with Cu+ may stabilize Cu+ so long as they do not form more stable complexes with Cu2+. ! In the synthesis, formation of [CuCl2] –(aq) effectively removes Cu+ from the solution, thereby driving the equilibrium to the left (LeChatelier’s Principle). ! When CuCl(s) is treated with the chelating ligand ethylenediamine Cu+ is oxidized to Cu2+, because the bis-ethylenediamine copper(II) complex is more stable than the copper(I) complex: 2 CuCl(s) + 2 en º [Cu(en)2] 2+(aq) + Cu(s) + 2 Cl–(aq) ! With non-chelating ligands such as NH3 and pentamethylenediamine [H2N-(CH2)5-NH2] the copper(I) complex is favored. [Cu(NH3)4] 2+(aq) + Cu(s) º 2 [Cu(NH3)2] +(aq) Copper(I) Iodide ! Copper(I) iodide precipitates when any Cu(II) salt is added to a KI(aq) solution. 2Cu2+(aq) + 4I–(aq) º 2CuI(s) + I2 ! I–(aq) is a strong enough reducing agent to reduce Cu2+(aq) to CuI(s). 2I– º I2 + 2e– –Eo = –0.54 V 2(Cu2+ + I– + e– º CuI) Eo = +0.88 V 2Cu2+ + 4I– º 2CuI + I2 Eo cell = +0.34 V Cu+ in Acetonitrile ! CuCl is soluble in actonitrile, CH3CN. i Cu(I) is effectively solvated by CH3CN. i Cu(I) is actually more stable than Cu(II) in acetonitrile. i Tetrahedral ion [Cu(CH3CN)4] + can be isolated in salts with large anions such as ClO4 – and PF6 –.
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