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Derivation - Advanced Hydrology - Lecture Slides, Slides of Aeronautical Engineering

These are the Lecture Slides of Advanced Hydrology which includes Method of Matching Points, Method of Moments, Maximum Likelihood Method, Population Parameter, Sample Parameter, Estimation etc.Key important points are: Derivation, Convolution Equations, Curve Method, Hydrograph, Surface Discharge, Constant Outflow, Duration of the Unit Graph

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2012/2013

Uploaded on 03/28/2013

ekanath
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Download Derivation - Advanced Hydrology - Lecture Slides and more Slides Aeronautical Engineering in PDF only on Docsity! Lecture 5: Derivation of S-curve and discrete convolution equations Module 3 Docsity.com • It is the hydrograph of direct surface discharge that would result from a continuous succession of unit storms producing 1cm(in.)in tr –hr • If the time base of the unit hydrograph is Tb hr, it reaches constant outflow (Qe) at T hr, since 1 cm of net rain on the catchment is being supplied and removed every tr hour and only T/tr unit graphs are necessary to produce an S-curve and develop constant outflow given by, Qe = (2.78·A) / tr where Qe = constant outflow (cumec) tr = duration of the unit graph (hr) A = area of the basin (km2 or acres) Module 3 Unit hydrograph S – Curve method Docsity.com Module 3 Unit hydrograph Time (hr) 2-hr UH 2-HR lagged UH’s Sum 0 0 0 1 75 75 2 250 0 250 3 300 75 375 4 275 250 0 525 5 200 300 75 575 6 100 275 250 0 625 7 75 200 300 75 650 8 50 100 275 250 0 675 9 25 75 200 300 75 675 10 0 50 100 275 250 0 675 11 25 75 200 300 75 675 Example Problem Contd… Docsity.com 0 100 200 300 400 500 600 700 800 0 2 4 6 8 10 12 14 Q (c fs ) Time (hr) S-curve 2 hr UH Lagged by 2 hr Draw your S-curve, as shown in figure below Make a spreadsheet with the 2-hr UH ordinates, then copy them in the next column lagged by D=2 hours. Keep adding columns until the row sums are fairly constant. The sums are the ordinates of your S-curve. Module 3 Unit hydrograph Example Problem Contd… Docsity.com Time (hr) S-curve ordinate S-curve lagged 3hr Difference 3-HR UH ordinate 0 0 0 0 1 75 75 50 2 250 250 166.7 3 375 0 375 250 4 525 75 450 300 5 575 250 352 216 6 625 375 250 166.7 7 650 525 125 83.3 8 675 575 100 66.7 9 675 625 50 33.3 10 675 650 25 16.7 11 675 675 0 0 Unit hydrograph Example Problem Contd… Docsity.com Unit hydrograph Contd…. P1 P2 P3 Input Pn U1 U2 U3 U4 U5 Un-m+1 n-m+1 Unit pulse response applied to P1 Unit pulse response applied to P2 n-m+1 Un-m+1 Output Qn Output ∑ − + = = m* n m n m 1 m 1 Q P U Combination of 3 rainfall UH Docsity.com The set of equations for discrete time convolution ∑ − + = = m* n m n m 1 m 1 Q P U n = 1, 2,…,N =1 1 1Q PU = +2 2 1 1 2Q P U PU = + +3 3 1 2 2 1 3Q P U P U PU −= + + +M M 1 M 1 2 1 MQ P U P U ..... PU + += + + + +M 1 M 2 2 M 1 M 1Q 0 P U ..... P U PU − − − − += + + + + + + +N 1 M N M M 1 N M 1Q 0 0 ..... 0 0 ..... P U P U − − += + + + + + + +N M 1 N M 1Q 0 0 ..... 0 0 ..... 0 P U Unit hydrograph Contd…. Docsity.com Solution • The ERH and DRH in table have M=3 and N=11 pulses respectively. • Hence, the number of pulses in the unit hydrograph is N-M+1=11-3+1=9. • Substituting the ordinates of the ERH and DRH into the equations in table yields a set of 11 simultaneous equations Module 3 Unit hydrograph − − = = =2 2 11 1 Q P U 1,928 1.93x404U 1,079 cfs/ in P 1.06 Similarly calculate for remaining ordinates and the final UH is tabulated below n 1 2 3 4 5 6 7 8 9 Un (cfs/in) 404 1,079 2,343 2,506 1,460 453 381 274 173 Example Problem Contd… Docsity.com
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