Docsity
Docsity

Prepare for your exams
Prepare for your exams

Study with the several resources on Docsity


Earn points to download
Earn points to download

Earn points by helping other students or get them with a premium plan


Guidelines and tips
Guidelines and tips

Derivation of Coefficients for Trend Analysis in Psychology: Linear and Quadratic - Prof. , Assignments of Psychology

A step-by-step derivation of coefficients for trend analysis using linear and quadratic equations in psychology. The example uses age groups as independent variables and calculates the coefficients for each group. The coefficients are then checked for orthogonality to ensure they are not correlated.

Typology: Assignments

Pre 2010

Uploaded on 09/02/2009

koofers-user-9p7
koofers-user-9p7 🇺🇸

10 documents

1 / 2

Toggle sidebar

Related documents


Partial preview of the text

Download Derivation of Coefficients for Trend Analysis in Psychology: Linear and Quadratic - Prof. and more Assignments Psychology in PDF only on Docsity! Psych 610 Handout #8, p. 1 Prof. Moore Derivation of coefficients for Trend Analysis (1) µi = β1(a1 + Xj) + β2(a2 + b2Xj + Xj 2) + β3(a3 + b3Xj + c3Xj 2 + Xj 3) + etc. -- Assume an experiment with 4 age groups – 8, 9, 10, and 11-year-olds. We want to do trend analysis on Age. So the ages are used as the values of X. For linear: cj = a1 + Xj (from Eq. 1). Plug in the age as Xj: c1 = a1 + 8 c1 = -9.5 + 8 = -1.5 Add c2 = a1 + 9 c2 = -9.5 + 9 = -.5 these c3 = a1 + 10 c3 = -9.5 + 10 = .5 c4 = a1 + 11 c4 = -9.5 + 11 = 1.5 ____________ ∑cj = 4a1 + 38 0 = 4a1 + 38; because ∑cj = 0 -38 = 4a1 a1 = -9.5 Now plug in –9.5 for a1 -- So, coefficients for linear are –1.5, -.5, .5, 1.5. If we multiply by 2, we get the values from Keppel Table A –4, -3, -1, 1, 3. -- Next we want to find the coefficients for quadratic trend. We want these coefficients to be orthogonal to the linear coefficients. For quadratic: cj = a2 + b2Xj + Xj 2 (from Eq. 1). Plug in the age as Xj: c1 = a2 + (b2)(8) + 8 2 c1 = 89 + (-19)(8) + 64 = 1 Add c2 = a2 + (b2)(9) + 9 2 c2 = 89 + (-19)(9) + 81 = -1 these c3 = a2 + (b2)(10) + 10 2 c3 = 89 + (-19)(10) + 100 = -1 c4 = a2 + (b2)(11) + 11 2 c4 = 89 + (-19)(11) + 121 = 1 __________________ ∑cj = 4a2 + 38b2 + 366 Now apply orthogonality constraint. ∑cjcj′ = 0.
Docsity logo



Copyright © 2024 Ladybird Srl - Via Leonardo da Vinci 16, 10126, Torino, Italy - VAT 10816460017 - All rights reserved