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Differential Equation Solved Paper., High school final essays of Mathematics

This is Differential Equation Solved paper for Engineering students. Basic Mathematics paper for University Engineering Students.

Typology: High school final essays

2019/2020

Available from 01/13/2022

abdul-samad-28
abdul-samad-28 🇵🇰

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Download Differential Equation Solved Paper. and more High school final essays Mathematics in PDF only on Docsity! Final —- Term ExaminationFall2020 Date:5/2/2021 Course Code: MTH 203 Course Title: Differential equation Prerequisite: CALCULUS Instructor: HIMAYATULLAH Module: 3 Program: BEE Total Marks: 50 Time Allowed: 4hr Note: Attempt all questions.PLO: program learning outcome C:Cognitive Iqra National University, Peshawar INU Department of Electrical Engineering TQRA NATIONAL UNIVERSITY QI.|@ | Analyze (D + 51)(D —1) tothe functions e°*, and sinx Marks 5 CLO2 c4 (b) Marks 5 CLO2 Identify anODE y’ + ay + by = 0 for the basis 1, e~3*.. a Q | @ | Calculat the initial value problem ves 5 y+t+2y +y=0 y(0)=4. y’(0) =-6. a! ) | Analyze the general solution of x7" + 3xy" +y=0. as 5 c4 | © | Discuss the general solution of y” — 2y" +y=0 Marks 5 CcLO1 C2 (>) | Discuss that the given function is the solution of y” - 2y' +2y=0 Marks 5 (+i)x (-i)x CLOI wherey = cy + Oy © Qt ' e2* Marks Analyze the method of variation of parameters for Y” — 4y + 4y = —. 10 * CLO2 c4 | Analyze the method of undetermined coefficient method for y” + 2y —10y= ieee 25x?. cLo2z IQRA NATIONAL UNIVERSITY PESHAWAR DIFFRENTIAL EQUATIONS Answer Sheet of FINAL Term Assignment 2021 NAME: FAWAD AHMAD ID: 13204 Submitted To: Himayat Ullah Sir Q2 (#” Qa g' +a += Jlo)- 4. 'lo= -6 Aurdary Sbadion A+r) +4 =0 N +A ++ -o Soll: z A (Ata) +( A+4)=0 CA+4) (Ata) =o Ay=-4 7 Ar= =4 > Loot ode xed) cud Evel) d= Caren e'* b= (arene 8" J Cre Cr &* Uber = GO, 7 4 Yy = Cie +Ci e (4- c+) ? Since Q- Cue * Oe 2 3 a-nw > Ge -C1e4 0,61 x -b6= -C1 +02 ~6=-G +, -6= Co40n -G= -y+Cr So es tiedox ly & Ludion ; fy ye"-axe” 06" f-(g-an) ef 4 PrsuoeN = Qs CB) - Sell. 3 O-3, 5:1 HO’ + BAY + Y=0 mr +(O-1) wh =o whe +( 3-1) m+ =6 Wie t+ Om +4 =6 7 + 77+ wth1=0 on mri) +4 (ret) *0 (77+4) (o#4)>& == <=" Bb Cat) x (a-&) x Oe + OoCre ar O+0 =O O-=0 So Vex Freel SE 2 KO a PS fbi fos HYovlo Jere Ou Syecfion 22% Jag rp & A-4l +420 ae (A-a) -® (A-2) (A-2)= Se ArveD ) Ar > Tt 13 Coe ZZ gr -(0taa Sox) eS yn = Cr ey Cr box er 2K fre gr * howe” low fe Ww We | g' | ' p> w= / e Jone a” x Onn (90) = --f 4x Ww =x & 22 Nhe -> Nhe™ te_f- 27 POY tngh KF Bun {Le Le e i 2 (€) Se en “ J? - loch thx =-€ Lod fxs dx]+ fh 2"(x) = =e ibae- w+ Ion -- 72love “a ene @P= xe" So Crentd Sebubon J: 0+ J (are Ine de "+me
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