Download Diffusivity - Microelectronic Devices and Circuits - Solved Exam and more Exams Microelectronic Circuits in PDF only on Docsity! EECSIO5 1 of8 Fall 1999
Microelectronic Devices and Circuits- EECS105
Second Midterm Exam
Wendesday, November 17, 1999
Costas J. Spanos
University of California at Berkeley
College of Engineering
Department of Electrical Engineering and Computer Sciences
Your Name: OFFICIAL SOLVIT OMS
(last) (first)
Your Signature: A F7Q093
1. Print and sign your name on this page before you start.
2. You are allowed two, 8.5""x11” handwritten sheets with formulas. No books
or notes!
3. Do everything on this exam, and make your methods as clear as possible.
Problem 1 /30
Problem 2 /35
Problem 3 (35
TOTAL 594/100 AvetAce — (67 studans)
14.6 STAWDARD DEWATI OW
EECSI05 20f 8 Fall 1999
Problem 1 of 3 Answer each question briefly and clearly. (30 points)
Explain briefly why BJT performance depends so much on the diffusivity of minority carriers (Spts)
lets che diflaston of welnanry tarsters her buat thers to rye re.ene.blosed
colleen funerloa that reofes the praas/'sin woh
How does the small signal output resistance of a BJT depend on its size (emitter-to-base junction
area), when Vas is held constant? (Spts)
vee /| VA
Jee 1,2 BE Veh Qo = iL
Te i proport/mad co Ss , wad Js 1S prapnrloaal to AE.
bot Aph av Ligh Pit =7 ed
Why is it desirable for Vas = 0V in MOS Common Gate applications? (Spts)
The caneat belle, ote gehr 8-4 tn ybnewl
ha Pin? go the bower Ba (dub to Yucb ) 1 des rable
bur phe added copacirmne ( toe!
EECSIOS sof8 Fall 1999
c) Size the biasing transistors and resistor in order to get the proper Vpjq, and proper supply current
(L0pts)
Z2.4V- ).330V
26v Vovgs = 1332. =? BE S0qp4 2 2e
500 |
HA My must hove 133204 Vos =?
Ves,2 29V =?
mead \ 21 og oo [W\~ Frsfpmlor.
pape (O97 Tae"
Ap Ytalox
Vout | Zh + Venez i322 (iY (ia) = 50
v (Z L [alow Yon) 108
“a
L
EECSI05 6 of 8 Fall 1999
Problem 3 of 3 (35 points)
For each of the following questions, make sure that you show the expressions before you plug in
the specific values. A correct expression is worth 70% of the credit, even if the numerical calcula-
tion is incorrect!
You are given the following p-channel common-source amplifier.
254
Ta
~2.5¥
a) Draw the small signal model of the amplifier. Make sure that you include the entire small signal
model of transistor Mj, along with all the relevant capacitances, including ry, Cgy2 and Cyqy
from the current sink transigotr)M). (10 points)
Bs Cod,
i
Vs
Norlie thay oll the blluday smabl siquat wobeages
ge g7ouads: {o/)
UY, Uy, Ye Yon
Thi ' why a0 these cop» ow vere
Alo: Uys, =0V Vosy 0 ther 15 why there 270 Wo
ob pewtlud sev7es rou My in this mode...
EECSIOS 7 of 8 Fall 1999
b) Apply the Miller approximation (ignore all capacitances when calculating the Miller gain), and
derive a symbolic expression for the complete transfer function (hint: this function has two
poles and no zeros) (7 points).
(Ml) tn Aye ~ 9m (to |] orl)
ih -\- yw a +Cm n Hon Hla =
. Est Pe (Pee Wn Colby Tantavéa)’
Count t(n)
Vout Qn , Do Hier {fhe
woo [4+ jwes Cosntay| | Pot (ae Cb) J
Cen __
pode pole
= + We a
PCCysr0x) (Bll foil In)* (Cale Lbs thy)
c) Calculate de gain and the values of the two poles, given that Cg.)=78fF, Cyg:=25fF,
Cyaz=251F, Cyy1=90EF, Cayz=308F (8 points)
de gain Zz - am (Gor ff? fB.) = -32.114
- V2" «bs
Dm = LF flor] 2354 a §
tat Ca Ta)" = Book = Yor
' |
pole | (doe aust) = —— 25,50 rad foc
B, (Cont Gon)
Nasser x (14 32 in): S054 F
{
pole, = ee 754M ted foc
[or |} ft B)- Cnt ldbstGgdy)