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Direct Multiplication Method - General Physics - Solved Past Paper, Exams of Physics

This is the Solved Past Paper which includes Gravitational Acceleration, Gravitational Force, Spring Constant, Work Done by Spring Force, Change in Potential Energy, Frictional Force, Minimum Speed etc. Key important points are: Direct Multiplication Method, Cross-Products, Unit Vectors, Compute Torque on Object, Determinant Method, Sloppy Notation, Lack of Vector Signs, Magnitude of Torque, Two Specified Vectors

Typology: Exams

2012/2013

Uploaded on 02/25/2013

ekbal
ekbal 🇮🇳

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Download Direct Multiplication Method - General Physics - Solved Past Paper and more Exams Physics in PDF only on Docsity! 3. (10 pts) Compute the torque on an object if a force of ~F = −3 ı̂ + 7 ̂ − 4k̂ N is exerted at the position ~r = 6 ı̂ − 10̂ + 9k̂ m. You can either multiply out all 9 terms and then work the cross-products of the unit vectors or use the determinant method. Both techniques give the same answer. First, the direct multiplication method: ~τ = ( 6 ı̂ − 10 ̂ + 9 k̂ ) × ( −3 ı̂ + 7 ̂ − 4 k̂ ) = −18 (̂ı × ı̂)+42 (̂ı × ̂)−24 ( ı̂ × k̂ ) +30 (̂ × ı̂)−70 (̂ × ̂)+40 ( ̂ × k̂ ) −27 ( k̂ × ı̂ ) +63 ( k̂ × ̂ ) −36 ( k̂ × k̂ ) = 42 k̂ + 24 ̂− 30 k̂ + 40 ı̂− 27 ̂− 63 ı̂ ~τ = −23 ı̂− 3 ̂ + 12 k̂ N · m And then the determinant method: ~τ = ∣ ∣ ∣ ∣ ∣ ∣ ı̂ ̂ k̂ 6 −10 9 −3 7 −4 ∣ ∣ ∣ ∣ ∣ ∣ = ı̂(40 − 63) − ̂(−24 + 27) + k̂(42 − 30) ~τ = −23 ı̂− 3 ̂ + 12 k̂ N · m There was a lot of very sloppy notation used in this problem. The most prevalent was a lack of vector signs, like: τ = r × F which is not correct! The magnitude of the torque is not equal to the product of the magnitudes of r and F . You must also multiply by the sin of the angle between them! However, with the vector symbols it is correct, ~τ = ~r × ~F Also, there were a lot of vector components written with i, j, and k rather than ı̂, ̂, or k̂. i, j, and k are just (scalar) variables unless you specifically indicate, with the hat symbol, that they are unit vectors. Another notational mistake occurred in the actual vector multiplication. Torque is a vector, so the type of product must have a vector as a result. Therefore it cannot be the result of a dot product! So ~τ = ~r · ~F is completely wrong. You could compute the dot product of ~r and ~F , but it does not give anything related to the torque. I also saw the expression written as ~τ = ~r ~F or even with the components of the two specified vectors, ~τ = ( 6 ı̂ − 10 ̂ + 9 k̂ ) ( −3 ı̂ + 7 ̂ − 4 k̂ ) (with or without appropriate hats on the unit vectors) but with no multiplication symbol. For multiply- ing vectors, you must specify which multiplication you intend to use, otherwise it does not make sense. ~A ~B is not defined. You can’t do it. While I did not subtract any points for these notational errors, I did take off points if the order of the vectors in the cross product was reversed, ~F × ~r, since this gives −~τ rather than ~τ .
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