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Nodal Analysis: Determining Node Voltages in Linear DC Circuits, Study notes of Law

An introduction to nodal analysis, a method used to determine multiple unknown node voltages and branch currents in a linear DC circuit. The technique involves selecting a reference node, assigning voltages to the remaining nodes, assuming directions for currents, and applying Kirchhoff's Current Law (KCL) to each node. examples and step-by-step solutions for various circuits.

Typology: Study notes

2021/2022

Uploaded on 09/07/2022

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Download Nodal Analysis: Determining Node Voltages in Linear DC Circuits and more Study notes Law in PDF only on Docsity! EE301 – NODAL ANALYSIS-PART I 1 8/31/2016 Learning Objectives a. Apply Ohm’s Law using nodal voltages b. Apply the Node Analysis method to determine multiple unknown node voltages and branch currents in a simple DC circuit Nodal analysis Nodal analysis is based on a systematic application of KCL. The technique allows us to obtain a set of simultaneous equations to solve for voltages and current in any linear circuit. It is a powerful technique—but it is just that: a multi-step procedure. It is not a formula (and thus it’s not on the formula sheet) and it is somewhat more difficult to grasp than the subjects studied up to this point— until one has progressed through a number of problems. So, if you want to do poorly on the six-week exam, now is the time to doze off. Big picture, the technique works as follows. Given a circuit with n nodes: Step 1. Select a reference node. Step 2. Assign voltages Va, Vb, Vc …. to the remaining nodes, identifying any known voltages. Step 3. Assume a direction for the current passing through each resistor adjacent to a node with an unknown voltage and express the branch currents in terms of node voltages. Step 4. Apply KCL to each node. Step 5. Solve the resulting simultaneous equations to obtain the unknown node voltages. So, let’s take it slow by considering the circuit below: We first select a reference node, and assign labels to the remaining nodes. The circuit above has four nodes. Let’s select the reference node (ground) to be the bottom node (Step 1 complete!), and let’s label the remaining three nodes as a, b, and c, as shown below: Now, each of the labeled nodes, a, b, and c, will have a voltage associated with it: , ,a b cV V V . Now…we are not quite done with Step 2; we have to identify any know voltages. EE301 – NODAL ANALYSIS-PART I 2 8/31/2016             1 2 3 6 4 4 0 3 3 12 8 8 b a b a b b b c b V V V i V V i V V V i                      1 2 3 0 6 12 0 4 3 8 b bb i i i V VV         Look at the figure above: Are any of the quantities , ,a b cV V V known? 6 V, 12 Va cV V  Step 2 complete! Next, for Step 3, we assume a direction for the current passing through each resistor adjacent to a node with an unknown voltage (node b). Stated another way, we are going to write the branch currents. I have chosen to label the currents as 1 2 3, ,i i i in the direction shown below. But we’re not done with Step 3: we now have to express each of the branch currents in terms of node voltages. This is done using Ohm’s Law, but you have to be careful about the polarities. The way I have labeled the direction of 1i assumes that the voltage drop across the 4 resistor has its positive polarity at node b. Stated another way, I am assuming that bv is greater than av . So, expressing the currents as 1 2 3, ,i i i in terms of the node voltages, we have: Step 3 complete! Next, we apply KCL to node b. This is one equation in one unknown. You can solve this with some simple algebra, and we find… You should convince yourself that now that we know bv we can determine any other quantity in the circuit (such as the currents 1 2 3, ,i i i ). That’s it!! That’s all there is conceptually to nodal analysis!! EE301 – NODAL ANALYSIS-PART I 5 8/31/2016 Example: Solve for UNKI in the circuit below. Use nodal analysis! Solution: 5 EE301 – NODAL ANALYSIS-PART I 6 8/31/2016 Example: Solve for UNKI in the circuit below. Use nodal analysis! Solution: 6
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