Engineering Outreach Lab 2 -Advanced Power Systems Protection | ECE 504, Lab Reports of Electrical and Electronics Engineering

Download Engineering Outreach Lab 2 -Advanced Power Systems Protection | ECE 504 and more Lab Reports Electrical and Electronics Engineering in PDF only on Docsity! ECE 504 Lab 2, Page 1/2 Advanced Power Systems Protection Fall 2008 Example ECE 525: Engineering Outreach Lab 2 Due: December 16 The ATP system was configured as below, with two source supplying two lines from opposite ends. Each line segment has a series impedance of 1+j10 Ω with Z0 = 3Z1. The source impedance on each source is also 1+j10 Ω. The simulated CT's have a CTR of 1:1 The voltage transformers on the upper line have a VTR of 1:1 System Oneline 208 VLL Zsrc1=1.+j10.0 ohm Zsrc0=1.+j10.0 ohm Bus R ZLine1_1=0.5+j5.0 ohm ZLine1_0=1.5+j15.0 ohm ZLine3_1=0.5+j5.0 ohm ZLine3_0=1.5+j15.0 ohm ZLine2_1=0.8+j8.0 ohm ZLine2_0=2.4+j24.0 ohm ZLine4_1=0.2+j2.0 ohm ZLine4_0=0.6+j6.0 ohm 67 Pload=300W Unity pf Bus 2 VTs B1 B3 B2 B4 FC FA FB 208 VLL Zsrc1=1.+j10.0 ohm Zsrc0=1.+j10.0 ohm 0% BUS1 FSR • Faults will be applied at Location C (145% and 155% of line in front of the relay (comtrade files in the LocC directory) • Faults will also be at following locations (all will be in the LocD folder): o Right in front of the relay (0% in the figure) o On Bus 1 as shown in the figure o Behind the relay at location FSR (90% of line impedance behind the relay) • You do not need to worry about faults at Location FA or FB • The instantaneous overcurrent elements in the MathCAD relay are already set using settings that work reasonably well (and don’t have any transient overreach) for the forward direction faults: Level1P_pu = 7.1 (A) Level2P_pu = 5.05 (A) Level1Q_pu = 3.48 (A) Level2Q_pu = 2.48 (A) Level1G_pu = 5.43(A) Level2G_pu = 3.45 (A) *Note that these are 3I0 settings ECE 504 Lab 2, Page 2/2 Advanced Power Systems Protection Fall 2008 ATPDraw System Diagram: RemoteS 100% Z_SRC BUSR LOAD F155 75% CTB1 P S 83% F145 IN1I V CTC1 P SCTA1 P S I I I V CTB2 P S IN2 CTA2 P S CTC2 P S LocalS Z_SRC 90% BUS1 Z_SRC 10% FSR FR BUS F 0% Please Note: breaker all breakers are now closed. Lab 2 Procedure: 1. The relay instantaneous overcurrent elements are set for you based and do not need to be reset 2. Determine the directional relay for a torque based phase element (set to act for a 3 phase fault): TPforward= 1 Note that this needs to be set high enough to ensure that you don’t react to load (the default is set to 1 3. You also need to choose the maximum torque angle Torque equation for phase A (TSB and TSC will be similar) TSA_r1v VA_r1cpxv IA_r1cpxv⋅ cos θ VA_r1v θ IA_r1v − MTA+    ⋅:= Phase A direction: A32F_r1v TSA_r1v TPforward>:= Type 32 element: P32F_r1v 1 A32F_r1v B32F_r1v∧ C32F_r1v∧( )( )if 1 P32F_r1v 1− 0.01≥if 0 otherwise := i. Notice that the forward direction decision on Phase A is ANDed with the direction decision on each of the other phase. 4. Determine settings for zero sequence directional element First the minimum percentage of zero sequence current (a = |I0|/|I1) to activate the element. Default is set small a0 0.0001:= 5. Determine the minimum negative impedance to identify a fault as forward (one option is to set this at -(Zline0/2 + 0.001)) Z0Forward 0.1−:=