Equation Sheet for Exam 3: Magnetism and Electromagnetism, Study notes of Physical Education and Motor Learning

Download Equation Sheet for Exam 3: Magnetism and Electromagnetism and more Study notes Physical Education and Motor Learning in PDF only on Docsity! Equation Sheet for Exam 3 MAGNETISM Lorentz Force BvF ×= q The direction of the cross product is determined from the right-hand rule. Circular motion for a particle in a magnetic field qvB r mv Fma == 2 implies Magnetic force on a segment of wire BIF ×= L (L = length; I = current) ELECTROMAGNETISM Ampère’s Law. The magnetic field due to a long straight wire is Tm/A 104 whereˆ 2 )( 70 0 −×== πμϕ π μ r I rB The direction (φ) is determined by the right- hand rule. The magnetic flux through an open surface with area A is Φ = B A cos θ. If the magnetic field is perpendicular to the surface then θ = 0 and Φ = B A. Faraday’s Law. tΔ ΔΦ−=emf Ideal transformer equations. Alternating current is supplied to the primary coil; 2211 2 2 1 1 VIVI and N V N V == (V = emf, I = current, N = the number of turns of wire I in the coil) OTHER EQUATIONS Newton’s second law t v amaF Δ Δ== where Constant acceleration 2 2 1 000 and at tvxxatvv ++=+= 32 2 21 2 2 1 2 2 1 Law 3rd sKepler' / nGravitatio Universal energy potential Spring energy potential nalGravitatio energy Kinetic aT rmGmF kxU mghU mvK = = = = = RIIVP RVI tQI q rqKqF 2 2 21 law sJoule' /law sOhm' /current Electric / field Electric / force Coulomb == = ΔΔ= = = FE CONSTANTS kg 10671 massproton C 10602.1 /CNm 1099.8 /kgNm 1067.6 m/s 81.9 27 19 229 2211 2 - . e K G g ×= ×= ×= ×= = − −