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Lecture 7: Circuit Analysis - Equivalent Circuits and Source Transformations, Slides of Microelectronic Circuits

A series of slides from a university lecture in the electrical engineering and computer science (eecs) department, specifically eecs40, taught by professor king during the fall 2003 semester. The lecture covers the topics of equivalent circuits, source transformations, and circuit simplification using the node-voltage method and mesh-current method. The slides explain how to replace complex circuits with simpler equivalent circuits, transform sources, and analyze circuits using nodal analysis and mesh analysis.

Typology: Slides

2011/2012

Uploaded on 02/27/2012

elmut
elmut 🇺🇸

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Download Lecture 7: Circuit Analysis - Equivalent Circuits and Source Transformations and more Slides Microelectronic Circuits in PDF only on Docsity! 1 Lecture 7, Slide 1EECS40, Fall 2003 Prof. King Lecture #7 OUTLINE • Node-Voltage Method (cont’d) – circuits with dependent sources • Source Transformations • Mesh-Current circuit analysis – method – circuit with a current source Reading Chapter 4.3-4.9 Lecture 7, Slide 2EECS40, Fall 2003 Prof. King Equivalent Circuit Concept • A network of voltage sources, current sources, and resistors can be replaced by an equivalent circuit which has identical terminal properties (I-V characteristics) without affecting the operation of the rest of the circuit. + vA _ network A of sources and resistors iA ≡ + vB _ network B of sources and resistors iB iA(vA) = iB(vB) 2 Lecture 7, Slide 3EECS40, Fall 2003 Prof. King • Voltage sources in series can be replaced by an equivalent voltage source: • Current sources in parallel can be replaced by an equivalent current source: Source Combinations i1 i2 ≡ i1+i2 – + – + v1 v2 ≡ – + v1+v2 Lecture 7, Slide 4EECS40, Fall 2003 Prof. King Circuit Analysis Approaches • The Node-Voltage method can always be used to solve a circuit, but techniques for simplifying circuits (using “equivalent circuits”) are useful: – series and parallel combination reductions – ∆-Y and Y-∆ conversions – source transformations – Thevenin and Norton equivalent circuits (to be covered in Lecture 8) 5 Lecture 7, Slide 9EECS40, Fall 2003 Prof. King Derivation of Relationship between vs and is L s L RR vi + = RLR iL is + vL – a b – + RL iL+ vL – vs R s L L iRR Ri + = ss Riv = a b Lecture 7, Slide 10EECS40, Fall 2003 Prof. King Source Transformation Example • Find Io – + 60 V 6 Ω – + 15 V 3 Ω 3 ΩIo 6 Lecture 7, Slide 11EECS40, Fall 2003 Prof. King NODAL ANALYSIS (“Node-Voltage Method”) 0) Choose a reference node 1) Define unknown node voltages 2) Apply KCL to each unknown node, expressing current in terms of the node voltages => N equations for N unknown node voltages 3) Solve for node voltages => determine branch currents MESH* ANALYSIS (“Mesh-Current Method”) 1) Select M mesh currents such that at least one mesh current passes through each branch M = #branches - #nodes + 1 2) Apply KVL to each mesh, expressing voltages in terms of mesh currents => M equations for M unknown mesh currents 3) Solve for mesh currents => determine node voltages Formal Circuit Analysis Methods *A mesh is a loop that does not enclose any other loops. A mesh current is not necessarily identified with a branch current. Lecture 7, Slide 12EECS40, Fall 2003 Prof. King 1. Select M mesh currents. 2. Apply KVL to each mesh. 3. Solve for mesh currents. Mesh Analysis: Example #1 7 Lecture 7, Slide 13EECS40, Fall 2003 Prof. King Problem: We cannot write KVL for meshes a and b because there is no way to express the voltage drop across the current source in terms of the mesh currents. Solution: Define a “supermesh” – a mesh which avoids the branch containing the current source. Apply KVL for this supermesh. Mesh Analysis with a Current Source ia ib Lecture 7, Slide 14EECS40, Fall 2003 Prof. King Eq’n 1: KVL for supermesh Eq’n 2: Constraint due to current source: Mesh Analysis: Example #2 ia ib
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