Exam 3 Solutions for Thermodynamics | M E 303, Exams of Thermodynamics

Download Exam 3 Solutions for Thermodynamics | M E 303 and more Exams Thermodynamics in PDF only on Docsity! ME 303: Thermodynamics Midterm exam 3: July 26, 2013 In class exam: open book Time: 10:45 am — 12:15 pm Student number: Student name: / \ yo” I have neither given nor received help on this exam. Signature: Provide sufficient detail to demonstrate your understanding. Organize your solution and makc it as clear as possible. Problem E (50 points): 0.3 kg of moist air at 30 °C, 2 bar, and 50% relative humidity is cooled at constant pressure to 20 °C. Ignoring kinetic and potential energy effects, determine (a) whether water vapor condenses, and (b) the rate of work transfer during this process . Sketch the process in p-v and T-v diagrams. frowns M = 2b T= ° = >haY, a [el bs, 32°C Pe pis = Ge %G @ PrP, Trew skE=ePES © Finds cay wet wadonier ob) Q OW. @ : wr a? Splarw: ——o CLesed Syston ] /] Jy \SL —) pow edd T-v die fiber) \ A . l= oT “Toph 1) =°2 446 bev ) = ° (> Per, = A% Ch) = 0. 0.0G2¢6 © gor} bav — lop = 18.4% Ay Ta 7 Top no Condonterbrn oly —s Worl vans MU PB GAA) = Pt (& ~\) a fv the moat & a}, 1. HN eg whoe Pe = ORT BM Path = #R Te oo) heer! real J H.R AY r= R (8) “ft TA Pi + 7 v.28 66 gad tron tot be = 8 DF, 1 = ha Gy ate 2663. By > merry hOne My = e286 = 90902 be y+ 9.90 Foy My RY a Me RT des “Ms — we ery y a ht Se sole (2) _—— 0,223 HT hey. Wa = ax x ex C 4 2b 1) =0.86 by (2 2Ctr + eater 0) wy We = RCTs Ti) = ne eT & tT RR i Rinix = Vase “pe YM + Bete Splevt wade = A