Experiment 6: Stoichiometry - Method of Continuous Variations | CHEM 1045, Lab Reports of Chemistry

Download Experiment 6: Stoichiometry - Method of Continuous Variations | CHEM 1045 and more Lab Reports Chemistry in PDF only on Docsity! Date Performed: 10/14/08 Name: Edward Dobyns Date Submitted: 10/21/08 Partner: Kelly Gass Instructor: Jianyuan Zhang Experiment 6: Stoichiometry- Method of Continuous Variations Objectives: To determine the stoichiometry of the reaction between sodium hypochlorite(NaClO) and potassium iodide(KI) in aqueous solution. Experimental Data: Volume of NaClO = 131.00mL ± 0.5mL Mass of dish = 41.53g ± 0.01g Mass of dish and KI = 58.13g ± 0.01g Mass of KI = 16.6g ± 0.01g V of NaCl O (mL) V of KI (mL ) Initial Temp. of NaClO ( )℃) Initial Temp. of KI ( )℃) Final Temp . ( )℃) 45.0 5.00 21.25 21.17 24.63 40.0 10.0 21.70 20.86 25.92 35.0 15.0 21.67 21.13 27.24 30.0 20.0 21.62 21.10 26.35 25.0 25.0 21.62 20.39 25.36 20.0 30.0 21.64 20.68 24.53 15.0 35.0 21.49 20.80 23.62 10.0 40.0 21.22 20.86 22.53 5.00 45.0 21.09 20.88 21.63 Sample Calculations: Mole Fraction of NaClO Mole Fraction= Volume of NaClO Volumeof NaClO+Volume of KI = 45.0mL 50.0mL = 0.90 = mole fraction of NaClO moles= Mass Molar Mass Mole Fractionof NaClO=¿ T Intial= (T 1V 1 )+(T2V 2 ) (V 1+V 2) T Intial=¿ T Intial= (974.25 )+(105.85) (50.0) T Intial= (1080.1) (50.0) T Intial=21.60 ⁰C ∆T of NaClO = T Final - T intial ∆T of NaClO = 24.63 C – 21.60⁰ ∆T of NaClO = 3.03 C⁰ Calculations of a & b a = the mole fraction of NaClO a = 45.0mL 50.0mL = 0.90 = mole fraction of NaClO b= the mole fraction of KI b = 1-mole fraction of NaClO