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First and Second order DE, Exercises of Calculus for Engineers

many problems for practicing first and second-order DE

Typology: Exercises

2020/2021

Uploaded on 02/13/2022

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dongteen ๐Ÿ‡น๐Ÿ‡ญ

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Download First and Second order DE and more Exercises Calculus for Engineers in PDF only on Docsity! Problem Set 1 First order DE (Do at least 5 problems of each type) 1) ๐‘ฆโ€ฒ = ๐‘ฆ โˆ’ ๐‘ฅ, ๐‘ฆ(0) = 1/3 2) ๐‘ฆโ€ฒ = ๐‘ฆ4/5, ๐‘ฆ(0) = 1 3) ๐‘ฆโ€ฒ = ๐‘ฅ๐‘ฆ ๐‘ฅ2+4 4) 3๐‘ฅ๐‘ฆโ€ฒ โˆ’ 1 = ln ๐‘ฅ + ๐‘ฆ, ๐‘ฆ(1) = 2 5) ๐‘ฆโ€ฒ = 1โˆ’2๐‘ฆโˆ’4๐‘ฅ 1+๐‘ฆ+2๐‘ฅ by using ๐‘ฆ + 2๐‘ฅ = ๐‘ฃ 6) ๐‘ฅ3๐‘ฆโ€ฒ + 3๐‘ฅ2๐‘ฆ = 1/๐‘ฅ 7) ๐‘ฆโ€ฒ = ๐‘ฆ + ๐‘ฆ2, ๐‘ฆ(0) = 0 8) ๐‘ฆโ€ฒ = 2(๐‘ฆ โˆ’ 1) tanh 2๐‘ฅ , ๐‘ฆ(0) = 4 9) Show that ๐‘ฆ = ๐‘๐‘’๐‘ฅ + ๐‘ฅ + 1 is the solution to ๐‘ฆโ€ฒ = ๐‘ฆ โˆ’ ๐‘ฅ when ๐‘ฆ(0) = 3 10) ๐‘ฆโ€ฒ๐‘ฅ ๐‘™๐‘› ๐‘ฅ = ๐‘ฆ, ๐‘ฆ(3) = ln 81 11) 2๐‘ฆ๐‘ฆโ€ฒ + ๐‘ฆ2 sin ๐‘ฅ = sin ๐‘ฅ, ๐‘ฆ(0) = โˆš2 12) ๐‘ฆโ€ฒ + 2๐‘ฆ = ๐‘ก2 โˆ’ ๐‘ก + 1, ๐‘ฆ(1) = 1 2 13) ๐‘ฆโ€ฒ = ๐‘ฅ๐‘ฆ3 โˆš1+๐‘ฅ2 14) ๐‘‘๐‘Ÿ ๐‘‘๐œƒ = โˆ’๐‘Ÿ tan ๐œƒ 15) ๐‘‘๐‘ฆ ๐‘‘๐‘ฅ = ๐‘ฅ(๐‘’๐‘ฅ2 +2) 6๐‘ฆ2 ; ๐‘ฆ(0) = 1 16) ๐‘‘๐‘ฆ ๐‘‘๐‘ฅ = 2๐‘ฅ(๐‘ฆ โˆ’ 5) 17) ๐‘‘๐‘ฆ ๐‘‘๐‘ฅ = (1 + ๐‘’โˆ’๐‘ฅ)(๐‘ฆ2 โˆ’ 1) 18) sin ๐‘ฅ ๐‘‘๐‘ฆ ๐‘‘๐‘ฅ + ๐‘ฆ cos ๐‘ฅ = sin ๐‘ฅ 19) ๐‘ฅ๐‘ฆโ€ฒ + ๐‘ฆ = ๐‘ฅ2 + 1 20) ๐‘‘๐‘ฆ ๐‘‘๐‘ฅ + 2๐‘ฆ = cos ๐‘ฅ 21) ๐‘ฅ ๐‘‘๐‘ฆ ๐‘‘๐‘ฅ โˆ’ 4๐‘ฆ = ๐‘ฅ6๐‘’๐‘ฅ 22) ๐‘‘๐‘ฆ ๐‘‘๐‘ฅ = 2โˆš๐‘ฆ, ; ๐‘ฆ(1) = 0 23) ๐‘‘๐‘ฆ ๐‘‘๐‘ฅ = ๐‘ฅ+1 8+2๐œ‹ sin(๐œ‹๐‘ฆ) 24) ๐‘‘๐‘ฆ ๐‘‘๐‘ฅ = โˆ’ ๐‘ฅ ๐‘ฆโˆ’3 ; ๐‘ฆ(0) = 1 25) ๐‘ฅ ๐‘‘๐‘ฆ ๐‘‘๐‘ฅ + ๐‘ฆ = 1 ๐‘ฅ 26) ๐‘ฆโ€ฒ + 2๐‘ฅ๐‘ฆ = 1 27) ๐‘‘๐‘ฆ ๐‘‘๐‘ฅ + cot ๐‘ฅ ๐‘ฆ = cos ๐‘ฅ 28) 2(๐‘ฆ โˆ’ 4๐‘ฅ2) + ๐‘ฅ ๐‘‘๐‘ฆ ๐‘‘๐‘ฅ = 0
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