Download First and Second order DE and more Exercises Calculus for Engineers in PDF only on Docsity! Problem Set 1 First order DE (Do at least 5 problems of each type) 1) ๐ฆโฒ = ๐ฆ โ ๐ฅ, ๐ฆ(0) = 1/3 2) ๐ฆโฒ = ๐ฆ4/5, ๐ฆ(0) = 1 3) ๐ฆโฒ = ๐ฅ๐ฆ ๐ฅ2+4 4) 3๐ฅ๐ฆโฒ โ 1 = ln ๐ฅ + ๐ฆ, ๐ฆ(1) = 2 5) ๐ฆโฒ = 1โ2๐ฆโ4๐ฅ 1+๐ฆ+2๐ฅ by using ๐ฆ + 2๐ฅ = ๐ฃ 6) ๐ฅ3๐ฆโฒ + 3๐ฅ2๐ฆ = 1/๐ฅ 7) ๐ฆโฒ = ๐ฆ + ๐ฆ2, ๐ฆ(0) = 0 8) ๐ฆโฒ = 2(๐ฆ โ 1) tanh 2๐ฅ , ๐ฆ(0) = 4 9) Show that ๐ฆ = ๐๐๐ฅ + ๐ฅ + 1 is the solution to ๐ฆโฒ = ๐ฆ โ ๐ฅ when ๐ฆ(0) = 3 10) ๐ฆโฒ๐ฅ ๐๐ ๐ฅ = ๐ฆ, ๐ฆ(3) = ln 81 11) 2๐ฆ๐ฆโฒ + ๐ฆ2 sin ๐ฅ = sin ๐ฅ, ๐ฆ(0) = โ2 12) ๐ฆโฒ + 2๐ฆ = ๐ก2 โ ๐ก + 1, ๐ฆ(1) = 1 2 13) ๐ฆโฒ = ๐ฅ๐ฆ3 โ1+๐ฅ2 14) ๐๐ ๐๐ = โ๐ tan ๐ 15) ๐๐ฆ ๐๐ฅ = ๐ฅ(๐๐ฅ2 +2) 6๐ฆ2 ; ๐ฆ(0) = 1 16) ๐๐ฆ ๐๐ฅ = 2๐ฅ(๐ฆ โ 5) 17) ๐๐ฆ ๐๐ฅ = (1 + ๐โ๐ฅ)(๐ฆ2 โ 1) 18) sin ๐ฅ ๐๐ฆ ๐๐ฅ + ๐ฆ cos ๐ฅ = sin ๐ฅ 19) ๐ฅ๐ฆโฒ + ๐ฆ = ๐ฅ2 + 1 20) ๐๐ฆ ๐๐ฅ + 2๐ฆ = cos ๐ฅ 21) ๐ฅ ๐๐ฆ ๐๐ฅ โ 4๐ฆ = ๐ฅ6๐๐ฅ 22) ๐๐ฆ ๐๐ฅ = 2โ๐ฆ, ; ๐ฆ(1) = 0 23) ๐๐ฆ ๐๐ฅ = ๐ฅ+1 8+2๐ sin(๐๐ฆ) 24) ๐๐ฆ ๐๐ฅ = โ ๐ฅ ๐ฆโ3 ; ๐ฆ(0) = 1 25) ๐ฅ ๐๐ฆ ๐๐ฅ + ๐ฆ = 1 ๐ฅ 26) ๐ฆโฒ + 2๐ฅ๐ฆ = 1 27) ๐๐ฆ ๐๐ฅ + cot ๐ฅ ๐ฆ = cos ๐ฅ 28) 2(๐ฆ โ 4๐ฅ2) + ๐ฅ ๐๐ฆ ๐๐ฅ = 0