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Formula Sheet for Introduction to Physics II | PHYS 2212, Study notes of Physics

Formula Sheet Material Type: Notes; Professor: Greco; Class: Intro Physics II; Subject: Physics; University: Georgia Institute of Technology-Main Campus; Term: Spring 2011;

Typology: Study notes

2010/2011

Uploaded on 05/03/2011

ljacobson3
ljacobson3 🇺🇸

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Download Formula Sheet for Introduction to Physics II | PHYS 2212 and more Study notes Physics in PDF only on Docsity! Things you must know Relationship between electric field and electric force Conservation of charge Electric field of a point charge The Superposition Principle Relationship between magnetic field and magnetic force Magnetic field of a moving point charge Other Fundamental Concepts �a = d�v dt d�p dt = �Fnet and d�p dt ≈ m�a if v << c ΔUel = qΔV ΔV = − � f i �E • d�l ≈ − � (ExΔx+ EyΔy + EzΔz) Φel = � �E • n̂dA Φmag = � �B • n̂dA � �E • n̂dA = � qinside �0 � �B • n̂dA = 0 |emf| = � �ENC • d�l = � � � � dΦmag dt � � � � � �B • d�l = µ0 � Iinside path � �B • d�l = µ0 � � Iinside path + �0 d dt � �E • n̂dA � Specific Results � � � �Edipole,axis � � � ≈ 1 4π�0 2qs r3 (on axis, r � s) � � � �Edipole,⊥ � � � ≈ 1 4π�0 qs r3 (on ⊥ axis, r � s) � � � �Erod � � � = 1 4π�0 Q r � r2 + (L/2)2 (r ⊥ from center) electric dipole moment p = qs, �p = α �Eapplied � � � �Erod � � � ≈ 1 4π�0 2Q/L r (if r � L) � � � �Ering � � � = 1 4π�0 qz (z2 +R2)3/2 (z along axis) � � � �Edisk � � � = Q/A 2�0 � 1− z (z2 +R2)1/2 � (z along axis) � � � �Edisk � � � ≈ Q/A 2�0 � 1− z R � ≈ Q/A 2�0 (if z � R) � � � �Ecapacitor � � � ≈ Q/A �0 (+Q and −Q disks) � � � �Efringe � � � ≈ Q/A �0 � s 2R � just outside capacitor Δ �B = µ0 4π IΔ��× r̂ r2 (short wire) Δ�F = IΔ�l × �B � � � �Bwire � � � = µ0 4π LI r � r2 + (L/2)2 ≈ µ0 4π 2I r (r � L) � � � �Bwire � � � = � � � �Bearth � � � tan θ � � � �Bloop � � � = µ0 4π 2IπR2 (z2 +R2)3/2 ≈ µ0 4π 2IπR2 z3 (on axis, z � R) µ = IA = IπR2 � � � �Bdipole,axis � � � ≈ µ0 4π 2µ r3 (on axis, r � s) � � � �Bdipole,⊥ � � � ≈ µ0 4π µ r3 (on ⊥ axis, r � s) �Erad = 1 4π�0 −q�a⊥ c2r v̂ = Êrad × B̂rad � � � �Brad � � � = � � � �Erad � � � c i = nAv̄ I = |q|nAv̄ v̄ = uE σ = |q|nu J = I A = σE R = L σA Edielectric = Eapplied K ΔV = q 4π�0 � 1 rf − 1 ri � due to a point charge
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