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GEOMETRIC SEQUENCES, Schemes and Mind Maps of Calculus

In this unit, you will investigate different types of patterns represented in geometric sequences. You will also discern the difference between an arithmetic ...

Typology: Schemes and Mind Maps

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Download GEOMETRIC SEQUENCES and more Schemes and Mind Maps Calculus in PDF only on Docsity! GEOMETRIC SEQUENCES Unit Overview An important mathematical skill is discovering patterns. In this unit, you will investigate different types of patterns represented in geometric sequences. You will also discern the difference between an arithmetic sequence and a geometric sequence. Geometric Sequences Watch this video: Example 2: Increasing Geometric Sequence--Population (02:30) An example of a geometric sequence 5 10 20 40 80 A geometric sequence is one in which each number is multiplied by a constant ratio to get the next number in the sequence. In the example above, notice that each term is multiplied by 2 to get the next term. The following is another example of a Geometric Sequence that still follows the pattern of multiplying by 2. 2 3 4 52, 2 , 2 , 2 , 2 2, 4, 8, 16, 32= Another way to look at this sequence is: 1 2 1 3 2 4 3 5 42, 2, 2, 2, 2a a a a a a a a a= = ⋅ = ⋅ = ⋅ = ⋅ … In each case, the next term in the sequence is the product of the previous term and the constant 2. For a geometric sequence, the number that multiplies the present term to give the next result is called the common ratio. The effect of the common ratio is perhaps better seen in the next example. 2 3 4 1 1 2 3 4 4, 4 3, 4 3 , 4 3 , 4 3 4, 12, 36, 108, 324, 972 , 3, 3, 3, 3a a a a a ⋅ ⋅ ⋅ ⋅ = = ⋅ ⋅ ⋅ ⋅ In this example, the common ratio is 3 and is denoted r = 3. × 2 × 2 × 2 × 2 Example #3: Find the 6th term of the geometric sequence for which 1 2 and 3.a r= = − Substitute the values for n and r into the formula for the nth term of an geometric sequence along with 1 2a = . 1 1 5 6 6 6 (2)( 3) (2)( 243) 486 n na a r a a a −= = − = − = − The 6th term of the sequence is –486. Stop! Go to Questions #1-7 about this section, then return to continue on to the next section. Example #4: Find the explicit formula for the sequence 2, 4, 8, 16, 32, … First, find the common ratio (r). In this example, 4/2 = 2, 8/4 = 2, 16/8 = 2 and 32/16 = 2 so 2 is our common ratio. Using our explicit formula , 1 1 n na a r −= , we will plug in 2 for r and 2 for a1 (the first term). This gives the formula 22 2n na −= × . Using our exponent rules, we could simplify this further. Remember that when we have like bases, we can add exponents. If we think of this as 1 22 2n na −= × , we can add the exponents to get 1 2 12 2n n na + − −= = . Notice that this is an exponential function. If graphed, we would get this: *Geometric sequences are exponential functions. Example #5: Using the explicit formula 15 4n na −= × , state a1 and r. Then, find the first 4 terms of the sequence. First, using the formula, you can easily identify a1 and r. a1 = 5 based on its position in the formula. r = 4, again based on its position in the formula. Now, use the formula to find the first 4 terms. We already know the first term (a1) is 5. 2nd term: 2 1 15 4 5 4 20na −= × = × = 3rd term: 3 1 25 4 5 4 5 16 80na −= × = × = × = 4th term: 4 1 35 4 5 4 5 64 320na −= × = × = × = Example #6: Use the table of values to write a function for the geometric sequence. First, find the common ratio, r. 5 5 1 25 5 5 125 5 5 = − − − = − = − − We see that –5 is the common ratio. Next, identify the first term a1. The first term is –1 so a1 = –1. *Now, since we have 2 negative numbers, make sure to be careful and not make mistakes with those negatives!* We will use our explicit formula, 1 1 n na a r −= , but since we are writing in function notation, we will write it as 1 1( ) nf n a r −= . 1( ) 1( 5) nf n −= − − Notice that the –5 is in parenthesis. This is because –5 is r. All of r is taken to the exponent. Without including the negative in parenthesis, we are making r a positive 5. Also, we are not taking (–1) × (–5). Exponents first, and this will take care of the negative 5. Whatever you get after working the exponent is what will be multiplied by –1. Term # Value 1 –1 2 5 3 –25 4 125 5 –625 Identify each sequence. 2, 1, 0.5, 0.25 "Click here" to check the answer. Geometric, r = ½ or 0.5 Stop! Go to Questions #13-17 about this section, then return to continue on to the next section. Word Problems on Geometric Sequences Example#1: A culture of bacteria doubles every 3 hours. If there are 200 bacteria present at the beginning, how many bacteria will there be after 24 hours? Step #1: Determine whether the situation represents an arithmetic or geometric sequence. Starting with 200 and doubling produces the following sequence. 200, 400, 800,… The sequence 200, 400, 800, … is a geometric sequence. Step #2: Identify the variables. If the bacteria doubles every 3 hours, it will double 8 times in a 24 hour period. So, we are looking for the 8th term of the sequence. 1 200 2, 8a r n= = = Step #3: Substitute and evaluate. Use the formula for a geometric sequence. 1 1 7 8 8 200(2) 25,600 n na a r a a −= = = There are 25,600 bacteria present after 24 hours. Example #2: Mrs. Readworthy is serious when she says she wants her students to study. Each week, she requires them to study 5 times the number of spelling words required the week before. If she starts off the year requiring only 1 spelling word, how many spelling words will students be studying by week 4? From the problem, we discern that a1 = 1 (1 word the first week). We also see the common ratio is 5. From this, we write the formula 1 1 n na a r −= and fill in what we know. 11 5n na −= × . We are solving for week 4, so 4 1 3 4 1 5 1 5 1 125 125a −= × = × = × = . Mrs. Readworthy will require 125 spelling words on week 4. Stop! Go to Questions #18-19 about this section, then return to continue on to the next section. The Fibonacci Sequence There is one special sequence worth noting since we are discussing sequences. That is the Fibonacci Sequence. It is a special pattern found by adding the previous 2 numbers in the sequence. a1 = 1 and a2 = 1. By adding the first 2 terms, a3 = 2. Continuing the pattern 1, 1, 2, 3, 5, 8, 13, … Notice that the pattern is to add the previous two terms to get the next term. Watch this video about the Fibonacci Sequence: Fibonacci Sequence (03:50) Watch this video to see where the Fibonacci Sequence is seen in nature: The Fibonacci Sequence in Nature (03:00) What type of sequence is the Fibonacci Sequence? Is it arithmetic? geometric? Do we add the same number each time to get the next term? No. Do we multiply by the same number each time to get the next term? No. We always add the previous two terms. So, this sequence is not arithmetic or geometric. We can represent it with an explicit formula, but that is beyond the scope of this lesson. However, we can represent it with a recursive formula. Remember, recursive means that it is dependent on knowing the previous term(s). For this sequence, we could write, f (n + 1) = f (n) + f (n – 1) for n ≥ 1. We must also state that f (0) = f (1) = 1. This means that the first two terms are 1. Then the formula basically says that the next term (n + 1) equals the last two terms added together. If you’d like to learn more about this fascinating sequence, take it further and research it. There are many wonderful websites and books on this topic. Stop! Go to Questions #20-30 to complete this unit.
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