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Heat Equation Special Solution - Tools in Mechanical Engineering - Lecture Slides, Slides of Mechanical Engineering

These are the Lecture Slides of Tools in Mechanical Engineering which includes Steady Heat Equation, Bounday Conditions, Fourier Sine Coefficients, Original Variable, Temperature Distribution, Constant Temperature, Contour Plot, New Variable etc.Key important points are: Heat Equation Special Solution, Unsteady Heat Equation, Homogeneous Solution, Boundary Conditions, Heat Equation and Matches, Temperature Distribution, Equivalent Problem, Original Problem

Typology: Slides

2012/2013

Uploaded on 03/27/2013

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Download Heat Equation Special Solution - Tools in Mechanical Engineering - Lecture Slides and more Slides Mechanical Engineering in PDF only on Docsity! Heat Equation Special Solution 2 2 2 1 2 1 2 One-dimensional unsteady heat equation: A bar of length L with both ends at constant temperatures and , respectively ( 0, ) , u( , ) Also, the initial temperature distribution u uc t x T T u x t T x L t T ∂ ∂ = ∂ ∂ = = = = 1 2 1 2 inside the bar is given: ( , 0) ( ) for 0 If 0, the solution is given in chapter 11.5, say ( , ) ( , ) is the homogeneous solution. If 0, we can define a new distribution function h O u x t f x x L T T u x t U x t T T T = = ≤ ≤ = = = = = ≠ ( , ) ( , ) ( , )h O Ou x t u x t T U x t T= + = + Docsity.com 2 2 2 2 2 2 , the new function also satisfies the heat equation and matches both boundary conditions ( 0, ) ( 0, ) 0 Also ( , ) ( , ) 0 Therefore the solution is: O O O O O O u U U uc c t t x x u x t U x t T T T u x L t U L t T T T ∂ ∂ ∂ ∂ = = = ∂ ∂ ∂ ∂ = = = + = + = = = + = + = 1 2 2 2 2 2 2 2 2 2 2 2 ( , ) ( , ) where ( , ) is the homogeneous solution. If Introduce a new solution u(x,t)=U(x,t)+ψ(x) ( ) In order for ( , ) to satisfy the heat equatio Ou x t U x t T U x t T T u U U uc c u c c t t x x x u x t ψ ψ = + ≠ ⇒ ∂ ∂ ∂ ∂ ∂ ′′= = = − = − ∂ ∂ ∂ ∂ ∂ n 0 ( )x ax b ψ ψ ′′⇒ = = + Docsity.com 2 2 2 2 2 2 0 The original problem: (0, ) 0 , (1, ) 100 , ( ,0) ( ) The new problem: (0, ) 0 , (1, ) 0 , ( ,0) ( ) 100 The solution ( , ) ( , ) 100 2From chapter 11.5: ( ,0)n u uc t x u t C u t C u x f x U Uc t x U t C U t C U x f x x u x t U x t x C U x L ∂ ∂ = ∂ ∂ = ° = ° = ∂ ∂ = ∂ ∂ = ° = ° = − = + = ( ) ( ) 2 1 0 0.000986 1 sin 1002 (50 100 )sin [( 1) 1] 100( , ) [( 1) 1]sin L n n n t n n x dx L x n x dx U x t n x e n π π π π π ∞ − =       = − = − − = − + ∫ ∫ ∑ Docsity.com ( ) 20.000986 1 ( , ) ( , ) 100 100 [( 1) 1]sin 100n n t n u x t U x t x n x e x n π π ∞ − = = + = − + +∑ 0 0.2 0.4 0.6 0.8 10 20 40 60 80 100100 0 u0 x( ) u10 x( ) u50 x( ) u200 x( ) u500 x( ) 10 x Docsity.com
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