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Algebraic Geometry: Irreducibility, Cohomology, Schubert Cycles, Curves, Secant Varieties, Assignments of Mathematics

This problem set includes exercises on various topics in algebraic geometry. Topics covered include the irreducibility of projective varieties, computation of cohomology tables, proof of pieri's formula, cusps on plane curves, and secant varieties. Students are expected to assume that k is an algebraically closed field and r is a commutative ring with unit.

Typology: Assignments

Pre 2010

Uploaded on 07/23/2009

koofers-user-h1g
koofers-user-h1g 🇺🇸

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Download Algebraic Geometry: Irreducibility, Cohomology, Schubert Cycles, Curves, Secant Varieties and more Assignments Mathematics in PDF only on Docsity! HOMEWORK 5 This problem set is due Monday October 6. You may work on the problem set in groups; however, the final write-up must be yours and reflect your own understanding. In all these exercises assume that k is an algebraically closed field and R is a commutative ring with unit. Problem 0.1. Recall that “If f : X → Y is a surjective morphism of projective varieties such that (1) Y is irreducible, (2) Every fiber of f is irreducible, (3) Every fiber of f has the same dimension, then X is irreducible.” Show that all three assumptions are necessary. Problem 0.2. Compute the multiplication table for the cohomology of G(2, 5). Problem 0.3. Prove Pieri’s formula σ1 · σλ1,...,λk = ∑ λi≤µi≤λi−1, P µi=1+ P λi σµ1,...,µk where σλ1,...,λk and σµ1,...,µk are Schubert cycles in G(k, n). Problem 0.4. We say that a plane curve F = 0 has a cusp at p if the Taylor expansion of F at p has the form L2 + h.o.t. where L is a line containing p and h.o.t. denotes higher order terms. Show that for d > 2 plane curves of degree d that have a cusp form a projective subvariety of codimension two in Pd(d+3)/2, the space of plane curves of degree d. (Hint: Linearize the problem by considering plane curves that have a cusp at p with tangent direction L.) Problem 0.5. Let X ⊂ Pn be a projective variety. The secant variety to X is the closure of the union of lines spanned by distinct points on X Sec(X) = ∪p,q∈X,p 6=qpq. Prove that Sec(X) is a projective variety of dimension less than or equal to min(2 dim(X) + 1, n). We say that the secant variety is defective if dim(Sec(X)) < min(2 dim(X) + 1, n). Prove that Sec(X) is defective if and only if every point x ∈ Sec(X) lies on infinitely many secant lines to X. Show that the secant variety of the Veronese image ν2(P2) in P5 is defective. Hard Challenge: Show that a surface S in P5 which is not contained in any hyperplane has a defective secant variety if and only if S is the Veronese image ν2(P2). Problem 0.6. More generally, let X ⊂ Pn be a projective variety. The r-secant variety Secr(X) to X is the closure of the union of the Pr−1’s spanned by r distinct points p1, . . . , pr in X in general linear position. Prove that Secr(X) is a projective variety of dimension less than or equal to min(r dim(X)+r−1, n). We say that Secr(X) is defective if the dimension of Secr(X) is strictly less than min(r dim(X) + r − 1, n). Show that Secr(X) is defective if and only if every point on Secr(X) is contained in infinitely many secant Pr−1’s to X. Show that the fourth Veronese image ν4(P2) ⊂ P14 has a defective 5-secant variety Sec5(ν4(P2)). Hard Challenge: Show that among the secant varieties to the Veronese images of P2, Sec2(ν2(P2)) and Sec5(ν4(P2)) are the only defective secant varieties. 1
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