Physics 142 Homework 6: Problems on Chapters 30 and 31, Assignments of Physics

Download Physics 142 Homework 6: Problems on Chapters 30 and 31 and more Assignments Physics in PDF only on Docsity! Phys 142: HOMEWORK – 6 Due on July 27, 2009 Book: "University Physics", Volume 2 of 11th Edition, Young & Freedman Problems on Chap- 30: 30.1, 30.6, 30.21, 30.29, 30.43, 30.54, 30.59, 30.74 Problems on Chap-31: 31.1, 31.12, 31.20, 31.30, 31.33, 31.34 30.1: a)  V,0.270/s)A830(H)1025.3()/( 412  dtdiM and is constant.  b) If the second coil has the same changing current, then the induced voltage is the same and V.270.01  30.6: For a toroidal solenoid, )./(// dtdiiNL B  So solving for N we have: 30.21: a)  RLeRi t /),1(/ /       2 1 2 1 maxmax and,)(1when2/so/   τ/tτ/t eeiiRεi   μss L tτ/t 3.17 50.0 H)10(1.252)ln( R ln2 and)(ln 3 2 1       b)  max 2 2 1 max 2 2 1 ; LiULiU    2/when maxmax2 1 iiUU    2929.02/11eso211 //   τtτte   μssLt 30.7R/ln(0.2929)  30.29: a)  )F1000.6()H50.1(22 2 5 πLCπ ω π T   s.rad105,s0596.0  ω b)  .C1020.7)V0.12)(F1000.6( 45  CVQ c)  .J1032.4)V0.12)(F1000.6( 2 1 2 1 3252 0   CVU d)  .0)cos(,0At  ωtQQqt             )F1000.6)(H50.1( s0230.0 cos)C1020.7()cos(s,0230.0 5 4ωtQqt C.1043.5 4 Signs on plates are opposite to those at .0t e)  )sin(,s0230.0 ωtωQ dt dq it    turns.238 s)/A(0.0260Wb)(0.00285 A)(1.40V)106.12( )/(/ 3     dtdiiN B A.0.0499 H)10(6.00H)(1.50 s0.0230 sin H)10H)(6.00(1.50 C107.20 55 4               i Positive charge flowing away from plate which had positive charge at .0t f) Capacitor: .J102.46 F)102(6.00 C)10(5.43 2 3 5 242        C q UC    Inductor: .J101.87A)(0.0499H)50.1( 2 1 2 1 322  LiU L 30.43: a)  b) Since the voltage is determined by the derivative of the current, the V versus t graph is indeed proportional to the derivative of the current graph. 30.54: a)  .1860A1045.6 0.12 3     V i V R f b)  )/1(ln )/1(ln)1( )/( f f tLR f ii Rt Lii L Rt eii     H.963.0 ))45.6/86.4(1(ln )s1025.7)(1860( 4      L 30.59: μsFVUCCVUV CCCCC 222)V0.12/()J0160.0(2/2 so ;V0.12 222 2 1  Cπf L LCπ f 2)2( 1 so 2 1  H31.9givesHz3500 μsLf  30.74: (a) Steady state: A600.0125 V0.75    R i  (b) Equivalent circuit: F6.14 F35 1 F25 11     s s C C