Arithmetic and Geometric Sequences: Selfies and Girls in Math Performance Tasks, Essays (high school) of English

Download Arithmetic and Geometric Sequences: Selfies and Girls in Math Performance Tasks and more Essays (high school) English in PDF only on Docsity! 1 st Performance Task in Math Grade 10- First Quarter 1. Princess takes 60 selfies in an hour, and additional 30 in the next hour. It took her 4 hours to take selfies before she stopped taking them. 2. 3. Numbers of Hours 1 2 3 4 Number of Selfie 60 90 120 150 4. How many selfies did Princess got within 4 hours? a1,= 60, n= 4, d=30 an = a1 + (n-1) d Sn = n/2 {2a1 + (n-1) d} a4 = 60 + (4-1) 30 S4 = 4/2 {2(60) + (4-1) 30} a4 = 60 + (3) 30 S4 = 2 {120 + (3) 30} a4 = 60 + 90 S4 = 2 (120 + 90) a4 = 150 S4 = 2 (210) S4 = 420The 4th term of the arithmetic sequence 60, 90 and 120 is 150. The sum of the first terms of the arithmetic sequence 60, 90, 120 and 150 is 420. Albums Photos: 60 Albums Photos: 60 Albums Photos: 60 Albums Photos: 60 2nd Performance Task in Math Grade 10- First Quarter Arithmetic Sequence Geometric Sequence An arithmetic sequence is a list of numbers with a definite pattern. If you take any number in the sequence then subtract it by the previous one, and the result is always the same or constant then it is an arithmetic sequence. A geometric sequence is a sequence of numbers in which the ratio between consecutive terms is constant. The World Health Organization reported that about 16 million adolescent girls between 15 to 19 years of age give birth each year. Knowing the adverse effects of adolescent childbearing on the health of the mothers as well as their infants, a group of students from Malonoy High School volunteered to help the government in its campaign for the prevention of early pregnancy by giving lectures to 7 barangays about the WHO guidelines on teenage pregnancy. The group started in Barangay 1 and 4 girls attented the lecture. Girls from other Barangays heard about it so 8 girls attended from Barangay 2 – 16 from Barangay3, 32 from Barangay 4, and so on. Barangay 1 2 3 4 5 6 7 Number of girls attended the lecture 4 8 16 32 64 126 256 a1=4 ; a7=256 Since a7=a1 r 6 then 256 = 4 r6 a1=4 a2=4 ¿ a3=4 ¿ a4=4¿ a5=4 ¿ a6=4 ¿ a1=a2a7=256 ;r=2 sn = a1−an5 1−r s7= 4−256(2) 1−2 s7= 4−512 −1 s7= −508 −1 The total numbers of girls who will benefit from the lecture from Barangay 1 to Barangay 7 are 508.