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Understanding Electromagnetic Induction: Currents, Faraday's Law, and Magnetic Energy, Slides of Physics

Various aspects of electromagnetic induction, including induced currents, faraday's law, magnetic flux, and magnetic energy. It includes examples and formulas to help understand the concepts.

Typology: Slides

2012/2013

Uploaded on 07/12/2013

raghav
raghav 🇮🇳

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Download Understanding Electromagnetic Induction: Currents, Faraday's Law, and Magnetic Energy and more Slides Physics in PDF only on Docsity! Short Version : 27. Electromagnetic Induction Docsity.com 27.1. Induced Currents 4 results from Faraday / Henry (1831) 1. Current induced in coil by moving magnet bar. 2. Moving the coil instead of the magnet gives the same result. v = 0, I = 0 v > 0, I > 0 v >> 0, I >> 0 v < 0, I < 0 Docsity.com Magnetic flux B d  B AMagnetic flux: Reminder: 0d  B A For a uniform B on a flat surface: cosB BA    B A Move magnet right  more lines thru loop Docsity.com Example 27.1. Solenoid A solenoid of circular cross section has radius R, consists of n turns per unit length, and carries current I. Find the magnetic flux through each turn of the solenoid. B A  20 n I R  B out of plane I B Docsity.com Example 27.2. Nonuniform Field A long, straight wire carries current I. A rectangular wire loop of dimensions l by w lies in a plane containing the wire, with its closest edge a distance a from the wire, and its dimension l parallel to the wire. Find the magnetic flux through the loop. 0 2 a w a I l dr r     B d  B A 02 a w a I l d r r      0 ln 2 I l a w a     Area element for integration Docsity.com Example 27.4. Changing Area Two parallel conducting rails a distance l apart are connected at one end by a resistance R. A conducting bar completes the circuit, joining the two rails electrically but free to slide along. The whole circuit is perpendicular to a uniform B, as show in figure. Find the current when the bar is pulled to the right with constant speed v. B l xB B A  Bd d t   E Let x = 0 be at the left end of rail. B l v  I R  E B l v R   CCW S x C I Docsity.com 27.3. Induction & Energy Direction of emf is to oppose magnet’s motion. Lenz’s law : Direction of induced emf is such that B created by the induced current opposes the changes in  that created the current. Magnet moving right RH rule: thumb // m. Loop ~ magnet with N to left. RH rule: thumb // m. Loop ~ magnet with S to left. Magnet moving left m I I m Docsity.com Motional EMF & Len’s Law Motional emf: induced emf due to motion of conductor in B. Square loop of sides L & resistance R pulled with constant speed v out of uniform B. Force on e:  e  F v B downward force  upward I (CW) Force on current carrying wire: mag I F L B ,mag net applied F F Docsity.com Example 27.5. Designing a Generator An electric generator consists of a 100-turn circular coil 50 cm in diameter. It’s rotated at f = 60 rev/s to produce standard 60 Hz alternating current. Find B needed for a peak output voltage of 170 V, which is the actual peak in standard 120 V household wiring. 1 costurn B A     2 cos 2 2 d dN B f t d t         Bd d t   E   2 cos 2 2 dB f t         2 22 sin 2 2 dN B f f t           2 2 0.5170 2 100 60 / 2 mV B s       2 22 2peak dN B f       E 323 10B T  Loop rotation Docsity.com Swiping a credit card. Patterns of magnetization on the strip induce currents in the coil. EM induction is basis of magnetic recording ( audio, video, computer disks, …). Modern hard disks: Giant magnetoresistance. Coil Iron Magnetic strip Card motion Information stored in magnetization pattern Docsity.com Eddy Currents Application: Metal Detectors Eddy current: current in solid conductor induced by changing . Usage: non-frictional brakes for rotating saw blades, train wheels, … Transmitter coil Receiver coil Current detector Nothing between coils Metal between coils AC Induced Current Strong I Weak I : alarm. Docsity.com Example 27.6. Solenoid A long solenoid of cross section area A and length l has n turns per unit length. Find its self-inductance. 1 turn B A  0B n IB of solenoid: 0 n I A 1 turnn l   2 0 n l I A 2 0L n l AI   Docsity.com B L I  Bd d t   E d IL d t   back emf Rapid switching of inductive devices can destroy delicate electronic devices. +direction = V  along I. d I /d t < 0 Docsity.com Inductor + (higher voltage) 0d I d t  E E 0d IL d t   E + (higher voltage)  (lower voltage)  (lower voltage) Docsity.com L < 0 ; | L |  2 2 0 d I d IR L d t d t    0 0LI R  E E 0 0 d II R L d t   E 0LL R d L d t   EE / 0 R t L L e  E E   00L t   E E  0 1 LI R  E E  /0 1 R t LeR   E Inductive time constant = L / R c.f. capacitive time constant = RC I   V = IR  But rate is  + _ Docsity.com Example 27.8. Firing Up a Electromagnet A large electromagnet used for lifting scrap iron has self-inductance L = 56 H. It’s connected to a constant 440-V power source; the total resistance of the circuit is 2.8 . Find the time it takes for the current to reach 75% of its final value.  /0 1 R t LI eR   E  /1 R t LI e   2.80.75 1 exp 56 t H          20ln 0.25t   28 s Docsity.com / 0 R t LI I e Short times: IL can’t change instantaneously. Long times: L = 0 ; inductor  wire. Switch at A, I . Switch at B, battery’s shorted out. I  exponentially. 0 0 d II R L d t   E  /0 1 R t LI eR   E 0d II R L d t    0 0t  0 t R    E 0 0I t  0 t   Docsity.com Magnetic Energy in an Inductor RL circuit: 0 0LI R  E E  20 0LI I R I  E E 2 0 0 d II I R L I d t   E Power from battery Power dissipated Power taken by inductor L d IP L I d t  U P d t  d IL I d t d t   2 1 2 L I  0 0U I   Energy stored in inductor: Docsity.com Example 27.10. MRI Disaster Superconducting electromagnets like solenoids in MRI scanners store a lot of magnetic energy. Loss of coolant is dangerous since current quickly decays due to resistance. A particular MRI solenoid carries 2.4 kA and has a 0.53 H inductance. When it loses superconductivity, its resistance goes abruptly to 31 m. Find (a)the stored magnetic energy, and (b) the rate of energy release at the instance the superconductivity is lost. 61.5 10 J    231 0.53 2.4 102 H A  21 2 U L I 2P I R    23 32.4 10 31 10A     51.8 10 W  In practice, Cu / Ag are incorporated into the superconducting wires to reduce R. Docsity.com Magnetic Energy Density Solenoid with length l & cross-section area A : 20L n A l (Eg. 27.6) 2 2 0 1 2 n A l I21 2 U L I 2 0 1 2 B A l   0B n I Magnetic Energy Density : 2 0 1 2B u B   c.f. electric energy density : 20 1 2E u E Docsity.com Conservative & Nonconservative Electric Fields For stationary charges (electrostatics) : 0d  E l E is conservative Induced fields (electromagnetics) : 0d  E l E is non-conservative W against E E does W I Docsity.com GOT IT? 27.7 The figure shows three resistors in series surrounding an infinitely long solenoid with a changing magnetic field; the resulting induced electric field drives a current counterclockwise, as shown. Two identical voltmeters are shown connected to the same points A and B. What does each read? Explain any apparent contradiction. Hint: this is a challenging question! VA  VB = IR 3R IE VA  VB = 2IR Docsity.com Diamagnetism Superconductor is a perfect diamagnet (Meissner effect). B  0 B = 0: net = 0 This e slows down. This e speeds up. net  0 Classical model of diamagnetism (not quite right) Docsity.com
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