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Initial Velocity - Introductory Physics - Solved Paper, Exams of Physics

These are the notes of Solved Paper of Introductory Physics and its key important points are: Initial Velocity, Cannon Shoots, Initial Velocity, Kinetic Energy of Ball, Acceleration of Mass, Frictional Force, Velocity of Mass

Typology: Exams

2012/2013

Uploaded on 02/12/2013

sathianarayan
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Download Initial Velocity - Introductory Physics - Solved Paper and more Exams Physics in PDF only on Docsity! _ FROM : FAX NOL: Mar. @? 2683 2:47PM PL Lecty ve 2 Your name Soletion Set eee ee Discussion session number / GSI name Physics 8A Section 2 Midterm #1 March 6, 2003 a) DON’T OPEN THIS EXAM BOOK UNTIL INSTRUCTED TO BEGIN b) Sit one seat away from anyone else. ¢) This exam is 2 hours long and contains 5 problems. 4) Do all your work on the page indicated for each problem. e) Show all work; don’t just write an answer without showing your reasoning. f) This is a closed book exam; calculators and one 8.5” x 11” sheet of notes is allowed. g) To simplify the math, you can take the acceleration due to gravity as g = 10 m/s”. h) Possibly useful equations include: vedx/dt F,=y,N asdv/dt F, = ,N K=Xj,+Vott lar K=l/2mv F =ma=dp/dt U=mgh p=mv U=1/2kx Femv/r W = AU + AK + AE, + AE, W=Fx SCORING - we'll handle this space ; ) 1) All problems have the same maximum credit. 2) 3) 4) 5) TOTAL FROM = : FAX NO. = Mar. @? 2083 @2:47PM P2 and an initial velocity v = 10 m/s at an 1) A cannon shoots a bal! with mass m = 10 kg angle 0 = 30° upward from the horizontal. The top of the canon barrel is at a height h=5 m above the ground. [ae a) How long is the ball in the air? yleve) b) How far horizontally from the cannon does the ball |: 7 c) What is the ball as it hits ound? = * . (a) Vy~= Vee = 10 Gos a8 - BE m/e Y Dog 2 USA = jo Srl = SB rafsee_ h \. “pete ne — \og = _ te 2 ult fire -he Vite £9 Ss. by ke 6 Eyaze fc - + tee bousee the balls uw the Gir fv 62 SEC inetic ener: (1) Re Batp = SVaerGas Sxl 732¥ 1627 |hm i aa - (2 KEP = 37” Vey t a Vey 2b 2 < tm ii tto(My-ate) = semis dm Chy-94)~ 2 7 5-162) 2 396 + OXFQ 2 1002-27 5 (say 5( ») ’ ono 2s kf FROM : FAX NOL: Mar. @? 2683 @2:@9PM PS 4) A mass m = 10 kg is placed at the end of a horizontal and compressed spring that has a - spring constant k = 0 N/m. The spring is then released, releasing its energy to shoot the mass horizontally along a track. The mass enters a vertical loop-de-loop configuration of a track that has a radius r = 10 m. The mass just barely makes it around the loop without losing contact and falling. ™ pore a) What is the velocit ie mass at the toy the loop? b) What was the original displacement e end of the spri m its position of relaxation? it slo He -fo qe the QQ Sa the mas b make P ad lop the Coutripeka ot that poiud w protoled ong le qroorky an nocwal veodren 4 Bee : fq on VA q- Ve "4" > y toro ~ wet/geo wy “th tele Y= Ze 10 Em = (oasm a FROM : FAM NO. : Mar. G7? 2683 B2:89PM Pe 5) Two masses, m, = 20 kg and m, = 30 kg, hang down at the opposite ends of a rope that has been placed over a massless pulley. Initially the masses are held at the same height. Then they are released. ® m, A, a) What is the difference between the height of the two masses at a time t= 2 5 after release? __. T wat acoelerolion | mg-Ts ma Wayitude fe a ; Me | mage en 1 4 To M4e mea foth mouseA | nO ' m - "4 ( a> a= mM ¢ Mos My Re (30720 20 yioz & om fren Bot “For ae, — LY ax0)” ate ly pple atee mm moves i . A upeoyY ynanv0Ty Uy ater 1x ay (ayer He Ogee Wr va aon founwerh . 5 Hay a TOW Atpasobed Fofadlig bg & Aistauer Aths EM
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