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Introductory Physics II - Solved Exam 3 | PHYS 1112, Exams of Physics

Material Type: Exam; Professor: Krivosheev; Class: Introductory Physics II; Subject: Physics; University: Clayton State University; Term: Spring 2002;

Typology: Exams

Pre 2010

Uploaded on 08/04/2009

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Download Introductory Physics II - Solved Exam 3 | PHYS 1112 and more Exams Physics in PDF only on Docsity! TIME OF COMPLETION_SOLUTION/ NAMB DEPARTMENT OF NATURAL SCIENCES PHYS 1112, Exam 3 Section 1 Version 1 April 18, 2002 Total Weight: 100 points 1. Check your examination for completeness prior to starting. There are a total of twelve (12) problems on twelve (12) pages. 2. Authorized references include your calculator with calculator handbook, and the Reference Data Pamphlet (provided by your instructor). 3. You will have 80 minutes to complete the examination. 4. The total weight of the examination is 100 points. 5. There are seven (7) multiple choice and five (5) calculation problems. Work 4 out of 5 calculation problems and 6 out of 7 multiple choice. Show all work; partial credit will be given for correct work shown. 6. If you have any questions during the examination, see your instructor who will be located in the classroom. 7. Start: 10:30 a.m. Stop: 11:50 a.m PROBLEM 1-7 8 9 10 il 12 CIRCLE THE SINGLE BEST ANSWER FOR ALL MULTIPLE CHOICE QUESTIONS. IN MULTIPLE CHOICE QUESTIONS WHICH REQUIRE A CALCULATION SHOW WORK FOR PARTIAL CREDIT. 1. You stand two feet away from a plane mirror. How far is it from you to your image? a. 2.00 fi. b. 3.00 ft. ©) 4.00 ft, d. 5.00 ft. 6) 2. Which of the following best describes the image formed by a convex mirror when the object’s distance from the mirror is less than the absolute value of the focal length? a. Virtual, upright, and magnification greater than one. b. Real, inverted, and magnification less than one. 6) CG) Virtual, upright, and magnification less than one. d. Real, inverted, and magnification greater than one. 8. Monochromatic light of unknown wavelength from a distant source is incident on the two slits of Young’s double slit experiment. The slits are separated by 0.500 mm. A screen located 6.50 m from the’slits has interference pattern, in which the first and the second order bright fringes are separated by 7.70 mm. What is the wavelength of the incident light? xl as) f peteur = XL feecen 47 TT hy 2AL r { betent 2s I _ AL soe deoteure ~ f bezéxT) = zT = 7/lOxt0 (4, - ~ -3 a. 7. 70xK/0 “Wy 0. ox0° 7 7Ox/o L. - 6.50 = OS42 roe. £92 410 1 ya SILNKw fo PHYS 1112 Exam 3, Version 1 Spring 2002 5 9. A black widow spider (Latrodectus mactans) is 60.0 cm in front of the first lens of a two- lens system as indicated in the figure. (20) fie 10.0% f+ 50.0e P= 60. OG a. Find the position of the final image relative to the second lens. se ee Peete FER oe +. t— s+ -o}-— 0.0/66< —_—— on 41 100m 0.0% _ = - 0.11666 Q)a- f ST omy Lo pre EPID Ou tS. 000 = 18.57% PHYS 1112 Exam 3, Version 1 Spring 2002 ' po | qi ~ as _ mach Up eee Olan qe qu pr 13.37 Fe 186 few = 002 0.0736 =- 0, OTS86 b. Determine the total magnification, He Athy We - Fo bo ep r 50.00% == ~ 2 ge — 1p.6f ow - | 37 Bee he tat Mz (evo) = © 1% c. Is the final image upright or inverted, enlarged or reduced in size? UPLT EHT ZED UCE)) PHYS 1112 Exam 3, Version 1 Spring 2002 7 11. A tasty lollipop is located 200 cm in front of a concave spherical mirror with a focal length of 50.0 cm. a. Locate the image of the sucker. { i ao t- 20) { T F te. JS _ t— 2. 002 -— 6.607 { "50.00, Woe = 0.01 q- 66.7 CH b. Determine the magnification. Me- Yo _ 66 Te assy P ZOO OH ce. Describe the image (real or virtual, upright or inverted, enlarged or reduced?). REAL INVERTED RE PUcep PHYS 1112 Exam 3, Version ! Spring 2002 10 d. Draw a neat ray diagram to confirm your calculations. PHYS 1112 Exam 3, Version 1 Spring 2002 i 12. To calm troubled waters, a sheet of glass 2.00 com thick is placed in full contact over: water as indicated in the figure. a5) a. What is the critical angle for the glass-air interference? Ye Sa Ge ct —S ¢ a _ too | pues So = 06667 O. "9° b. At what angle of incidence 0 must light approach the water-glass surface so that the light is incident on the glass-air interface at the critical angle? fig hy eh = he for Uf p° u,. puUl?®? 1 - fowl FO vue Me ee bE by 1.83 = 0.75 a Oo PHYS 1112 Exam 3, Version I 6 _ Y g 7 Spring 2002 12 — :
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