laboratory parallel RLC, Lab Reports of Electrical Circuit Analysis

Download laboratory parallel RLC and more Lab Reports Electrical Circuit Analysis in PDF only on Docsity! REPUBLIC OF THE PHILIPPINES BATANGAS STATE UNIVERSITY COLLEGE OF ENGINEERING, ARCHITECTURE AND FINE ARTS ELECTRICAL ENGINEERING DEPARTMENT EE – 403 ELECTRICAL CIRCUITS 2 LABORATORY EXPERIMENT NO. 2 : SERIES RLC CIRCUITS SUBMITTED BY: ALFEREZ, NHORIEL ARELLANO, CHEZ JERVIANNE ANTIVEROS, KATHERINE BAJA, CHRISTINE JOY BATHAN, GIAN LORENZ SALAZAR, LYKA MAE EE - 2202B SUBMITTED TO: SIR DAVE IAN CATAUSAN I. INTRODUCTION Resistance and impedance both represent opposition to the flow of the alternating current. Both are measured in terms of the same unit, the ohm. To determine the magnitude of the total impedance, get the sum of the impedance of each of the elements in series. As long as all the necessary calculations are carried out by vector algebra, use the two relationships studied earlier under DC circuits. The total impedance may not always increase with the addition of another element in series. Capacitive reactance could cancel out inductive reactance and vice versa. An extreme case would have the capacitive reactance completely cancelling out the inductive reactance. This results in resonance high voltages and current could result. To know the concept of a series RLC circuit is to study basic knowledge concerning it, starting with the RLC circuits itself. In an RLC circuit; the resistor (R), inductor (L), and capacitor (C) are connected to the supply (voltage). This circuit was named after its components. These elements are passive in nature (consume energy rather than producing it) and have linear relationship (between voltage and current). RLC circuits have many applications as oscillator circuits. It can be used for tuning and selecting narrow range of frequencies (radio waves) and sometimes referred to as a second-order circuit as any current or voltage in the circuit can be described by a second order differential equation in a circuit analysis. The RLC circuit exhibits the property of resonance in the same way as LC (inductor and capacitor) circuit exhibits, but in this circuit the oscillation dies out quickly as compared to LC circuit due to the presence of resistor in the circuit. The three circuit components (elements); resistor, inductor and capacitor, can be combined in a number of different topologies (can be connected across the voltage in series and in parallel), though there are other various arrangements possible. Figure 2C Figure 2D c. Measure the voltage eT , eR , eL and eC. To measure the voltage eT refer to figure 3a. Record the data at table 2. Repeat the step for the lamp, inductor and capacitor. Refer for the figure 3b, 3c and 3d. Figure 3A Figure 3B Figure 3C Figure 3D d. Using Ohm’s Law, compute the voltage and current for each component. Record it at Table 1 and 2. Use the formula oF Solving for resistance P=lE £ P=EE Solving for Inductive Reactance X= 2nfl X= 2(m€)(60)(2.5372) Xi = 956.5018657 ohms Solving for Capacitive Reactance xe= sae Ng <= 2ey(60)(Sx10-%) Xc = 530. 5164771 ohms GIVEN: P=100W £=220V f=60Hz L=2.5372H C=5 uF Solving for magnitude of impedance Z=R+j(K-Xe) Z = 484 + 956.502) + 530.516j ohms Z = 484 +j 425.985 ohms IZ] = v(R*2 + j (XL — xc)? 12] = 484)" + 425.985)" Solving for phase angle of impedance pan 1 425.985 é£= tan cram Solving for current = 22020" “ GHET63 24135" 1 = 0.34121062 — 41.35°A Or i 1 = 341.2106 2 — 41.35° mA Datas presented on table 1 and 2 proved that there are minimal differences on simulation vs computation. b. Give possible reasons for any discrepancies. There are some possible reasons why there are minimal discrepancies in the results. Computations include estimations of decimals, especially in the final answers. Simulations are powered by the internet and may take several errors when it is first opened. Simulation programs also have built-in high precision parameters that sometimes a person would neglect in an actual computation. B. Circuit Design a. Design a series RLC circuit which is connected to 220 V , 50 cycles, having a 100W, capacitor C and inductor L. The total impedance is 609.8121 ohms and the capacitive reactance is 530.5165 ohms. Find the value of R, L and C Given: V= 220 V ZT= 609.8121 Ω P= 100 W XC= 530.5165 Ω f= 50 Hz Required: Resistance (R) Inductance (L) Capacitance (C) Solution: Computing for the value of Resistance (R): Computing for the value of Capacitance (C): Computing for the value of Inductive Reactance (L): Computing for the value of Inductance (L):