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Organic Chemistry: Properties and Naming of Alkanes, Alkenes, and Alkynes, Study notes of Chemistry

This chapter explores the properties and naming of organic compounds, specifically alkanes, alkenes, and alkynes. Topics include the position of carbon in the periodic table, bond energy and stability, hydrocarbon classification, and rules for naming organic compounds. Examples and problem-solving techniques are provided.

Typology: Study notes

Pre 2010

Uploaded on 03/18/2009

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Download Organic Chemistry: Properties and Naming of Alkanes, Alkenes, and Alkynes and more Study notes Chemistry in PDF only on Docsity! C h ap ter 22 - O rg an ic C h em istry 22.1 A lkanes: Saturated H ydrocarbons 22.2 A lkenes and A lkynes 22.3 A rom atic H ydrocarbons 22.4 H ydrocarbon D erivatives 22.5 P olym ers 22.6 N atural P olym ers T h e P o sitio n o f C arb o n in th e P erio d ic T ab le B o n d E n erg y an d th e S tab ility o f C arb o n C h ain s H yd ro carb o n s C + H C om pounds containing only carbon and hydrogen w ith only single bonds and no m ultiple bonds - Saturated hydrocarbons - A lkanes C n H 2n+2 C om pounds containing only carbon and hydrogen w ith only single bonds and no m ultiple bonds, but a ring structure - Saturated hydrocarbons - C ycloalkanes C n H 2n C om pounds containing only carbon and hydrogen w ith double bonds - U nsaturated hydrocarbons - A lkenes C n H 2n C om pounds containing only carbon and hydrogen w ith triple bonds - U nsaturated hydrocarbons - A lkynes C n H 2n–2 N am in g H yd ro carb o n s B ased on the longest chain of carbon atom s P refix + root + suffix L ocation and nature of substituents on chain (T able 22.2) Indicator of the # of C ’s in the longest chain (T able 22.1) C lass of organic com pound -ane for alkanes (-ene for alkenes -yne for alkynes) B o ilin g P o in ts o f H yd ro carb o n s T ab le 22.1 E xam p le P ro b lem : D raw in g A lkan es P roblem : D raw all possible structures for hydrocarbons that have: a) 7 C atom s, no m ultiple bonds, and no rings. b) 5 C atom s, one double bond, and no rings. c) 5 C atom s, no m ultiple bonds, and one ring. P lan: In each case, w e draw the longest carbon chain and then w ork dow n to sm aller chains w ith branches at different points along them . T he process typically involves trial and error. T hen w e add H atom s to give each C atom a total of four bonds. Solution: (only the carbon backbone w ill be show n here) a) com pounds w ith seven C atom s: (9) [C 7 H 16 ] C -C -C -C -C -C -C C -C -C -C -C -C C C -C -C -C -C -C C C C -C -C -C -C C C -C -C -C -C C C C -C -C -C -C C C C C -C -C -C -C C C -C -C -C -C C C C C -C -C -C C C D raw in g A lkan es (co n t) b) com pounds w ith 5 C atom s and 1 double bond: (5) [C 5 H 10 ] C =C -C -C -C C =C -C -C C =C -C -C C -C =C -C -C C -C =C -C c) com pounds w ith 5 C atom s and 1 ring: (5) [C 5 H 10 ] C -C -C -C C C -C -C -C C C C -C -C C C -C -C C -C C -C C C C C C C CH, cH-CH ~CH—CH;-CH;-CH, CH, CH, Condensed formula Depicting Cycloalkanes ACyclopropane BCyclobutane C Cyclopentane D Cyclohexane S o m e S tru ctu ral Iso m ers o f A lkan es A lken es C 2 H 4 E thylene H 2 C =C H 2 C 3 H 6 Propylene H 2 C =C H –C H 3 C 4 H 8 B utene H 2 C =C H –C H 2 –C H 3 C 5 H 10 Pentene H 2 C =C H –C H 2 –C H 2 –C H 3 C 6 H 12 H exene H 2 C =C H –C H 2 –C H 2 –C H 2 –C H 3 C 7 H 14 H eptene H 2 C =C H –( C H 2 )4 –C H 3 C 8 H 16 O ctene H 2 C =C H –( C H 2 )5 –C H 3 S o m e S tru ctu ral Iso m ers o f A lken es T h e In itial C h em ical E ven t in V isio n N am in g an d D raw in g A lkan es , A lken es, an d A lkyn es–II P lan: For (e), the longest chain that includes the m ultiple bond is num bered from the end closer to it. Solution: (a) C H 3 C H 3 C H 3 - C H - C H - C H 3 1 2 3 4 2,3-D im ethylbutane C H 2 - C H 3 H (b) C H 3 C H 3 - C H 2 - C H 2 - C - C - C H 2 C H 3 1 2 3 4 5 6 73-M ethyl-4-ethylheptane N am in g an d D raw in g A lkan es , A lken es, an d A lky n es–III (c) C H 3 H 2 H 2 H 2 H 2 C H 2 - C H 3 1 2 3 1-E thyl-3-m ethylcyclohexane (d) C H 3 C H 3 C H 3 - C H 2 - C - C - C H 3 H C H 3 1 2 3 4 5 2,2,3-T rim ethylpentane chiral center (e)C H 3 - C H 2 - C = C - C H - C H 3 H C H 3C H 3 C H 3 - C H 2 - C = C - C H - C H 3 H C H 3C H 3 cis-2,3-D im ethyl-3-hexene trans-2,3-D im ethyl-3-hexene C onsider carbon bonded to A , B , C , and D . T here are tw o possible structures. O rg an ic O p tical Iso m ers A D B C A D C B B and C do not superimpose T he tw o structures are m irror im ages of each other. T hey are optical isom ers of each other. E ach of the tw o form s is asym m etric - no plane of sym m etry. A n organic m olecule is alw ays chiral if it has a carbon atom that is bonded to four different groups. Representations of Benzene X ylen es –T h e T h ree Iso m ers o f C 8 H 1 0 C H 3 C H 3 C H 3 C H 3 C H 3 C H 3 1,2-D im ethylbenzene (o-xylene) bp = 144.4 °C 1,3-D im ethylbenzene (m -xylene) bp = 139.1 °C 1,4-D im ethylbenzene (p-xylene) bp = 138.3 °C N ap h th alen e an d B en zo [a]p yren e A rom atic C arcinogens N apthalene C 10 H 8 B enzo[a ]pyrene C 20 H 12
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