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Electrical Engineering Homework: Circuit Analysis and Power Calculation, Assignments of Electrical Circuit Analysis

Electrical engineering homework problems focusing on circuit analysis, loop equations, mesh equations, and power calculations. The problems involve finding currents, voltages, and resistances in various circuits, including series-parallel combinations and dependent sources. Students are expected to apply circuit analysis techniques and principles to solve the problems.

Typology: Assignments

2011/2012

Uploaded on 04/27/2012

koofers-user-bal
koofers-user-bal 🇺🇸

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Download Electrical Engineering Homework: Circuit Analysis and Power Calculation and more Assignments Electrical Circuit Analysis in PDF only on Docsity! Homework 9 Due: Wednesday, September 14 1 (a) For the circuit of Figure 1, R1 = 3 kΩ, R2 = 15 kΩ, R3 = 12 kΩ, Is = 100 mA and gm = 1.2 mS. Find I1 and Vx by writing two equations in the two unknowns I1 and Vx. The first equation is the usual loop equation and the second determines the relationship of I1 and Vx. (b) Given your answer to (a), find the equivalent resistance, Req, seen by the inde- pendent source. (c) Find the power delivered by the dependent source. Sunday, September 11, 2011 Figure 1: Model circuits for Problem 1. 1 2 The circuit of Figure 2(a),(b) represents two non-ideal batteries Vs1 = 7 V and Vs2 = 8 V with internal resistances R1 = 10 Ω and R2 = 40 Ω (faulty connection) respectively connected in parallel to supply power to a load of R3 = 40 Ω. The panels (a) and (b) of Figure 2 correspond to the same circuit redrawn with different loop currents. The point of this problem is to verify that different sets of independent loop equations produce the same element currents and branch voltages. (a) Write the loops equations and find I1and I2 for the circuit of Figure 2(a), and then find the voltage across and the power consumed by R3. (b) Write the new loop equations and find I1 and I2 for the circuit of Figure 2(a), and then find the voltage across and the power consumed by R3. Sunday, September 11, 2011 Figure 2: Model circuit for Problem 2. 3 The mesh equations for the circuit of Figure 3 are 20 −40 −5−15 65 −25 −5 −25 35   i1i2 i3  =  v1−v2 0  (1) Find R1, R2, R3, R4, and rm. 2 Vx FY 2 = = 8 FE 2 0.96 Roa, Te loo m GP kaAL ©) ere deliviree de, by f feurcea - — Cn %x) ( Yee) ~ Ca) Ry (4, ~ In We ) _ X Car Ven bho Ry — 82-98 w @) Li ty R, be NA Ne R = 104 aaah Age ene és A Ba 4on to x. | ft Bae OAL > ; Le Vs, 2 | v2 G a uy Vs, = 7) ky *) Vy t 3 (a) | (b) Leep2) Ve = 7, 8, rs (Z,-L) Lap J: Vy GF tZ)R, + Bp Z, Leap hh : Von = Z, Rp + R, (7,J, Coop Ta. : Ver Veg = K C474) 4 Ry Dy Cf, TRY TH k, Ty Ve, — hy Ft (RARE = Vey SD ty > 40 T, = 7 ~Yyot, + &T, = -8 t= O-1R T.2 ~O-057A Re, ha) z; + R, Ty = Vey R, I, + &k, rR )L = My iy $2 SOT, tloT, = 7 \ loZ, # SBLly = —] ‘ T= O15 A L Ti = -005 A vy bs Ves = Lee 2, =F, €3 = OIS Yo = 6V bes lasp i, ay i p= (ni _ HP ia = PDR FOB) Rs 7Pi2 > ~V, = a ° >) ~¥, leap i ~ 2) 3 Ff irk Py t mh. i = . 32) O= fis-)e@, 4 () bAIRy ey g ,\3 if TP + (RM) lt ER) tps Vv -— Pp . = . >) (, # (2,4 Yn ) i t (ry) a J CR Jt + / ie : 3 7 7 V5, _ 3) H( ae fa - QO 14. We are trying to calculate 4 using superposition. First, we calculate # with only the voltage source active as shown in Figure (1). Second, we calculate # with only the current source active as shown in Figure (2). Find #”, i and 4, . an “ ~ 22 AM & - NW i | i” | mL Bj _|20r 64 0 iL aie) a= 41 4an= Figure (1) Figure (2) (1) P=1A, 4° =0.6A, and §, =1.6A (QM =2A, {P=12A, and i =3.2A G3) P=1A, £0.64, and §, -0.4A @) P=2A, {P=12A, and i, =0.8A (5) @=1A, 4 0.64, and 4, 0.44 (©) (P=2A, =1.2A and 4 =-0.8A (7) QP =H1A, HP =12A, and 4 =2.2A 2. Find the equivalent resistance, Reg (in ©). 5Q 102 100 AAG MAPS Reg 3 400 3 (1) 10 @) 15 (3) 20 (4) 25 (3) 30 (6) 35 (7) 40 14. The voltage v(t) across an element and the current i(t) through the element are shown in the figure. v(t) (V) i() (mA) 40) is) iy 2. 3 tts) 404 =y it) sv + v(t) | | | 1 2 3 Which of the following plots best represents the power absorbed by this element? pc) (W) (1) a “| 0.24 0) p(t) (W) () 02 1 2 3. (ts -0.24 3) pit) (W) (6) 02+ TINY Y ” 0.24 pit) (W) pct) Cw) 0.2 ys) 0.2 11. Find the value of R; in the circuit below, so that n= 6 A. th fis lin= wo? Sra $10 3 Rg aia 29 G32 (52 (69 (N79 Dee lo G kK; , G3 x/o L=6 ~ 7 +63 /¢663- 06;=0 Ga ~ =¥ R;= (440 (8) 8a (7 3. There is a circuit that has only resistors in it. It has two input ports: one for a voltage input (Vyx) and another one for a current input (Ipy). The output Vour is measured at two different sets of input conditions, and the results are shown below in the table. Using the two measurement results, find Voyr when Vpy = 15V and Ipgp= —3A. Linear circuit Vw @| containing 1 @ dv Only Resistors Pod + Vout Uy dar Vour 20V 2A 2V 10V 4A 6V 15V 3A ? () 2V Q)4v G) 6Vv (4) 8V (6)-2V (@-4V ()-6V 2. Find the equivalent resistance, Reg (in ©). 5Q 102 100 AAG MAPS Reg 3 400 3 (1) 10 @) 15 (3) 20 (4) 25 (3) 30 (6) 35 (7) 40 EAS ) 14. The voltage v(t) across an element and the current i(t) through the element are shown in the figure. v(t) (V) i() (mA) 40) is) iy 2. 3 tts) 404 =y it) sv + v(t) | | | 1 2 3 Which of the following plots best represents the power absorbed by this element? pc) (W) (1) a “| 0.24 0) p(t) (W) () 02 1 2 3. (ts -0.24 3) pit) (W) (6) 02+ TINY Y ” 0.24 pit) (W) pct) Cw) 0.2 ys) 0.2
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