Docsity
Docsity

Prepare for your exams
Prepare for your exams

Study with the several resources on Docsity


Earn points to download
Earn points to download

Earn points by helping other students or get them with a premium plan


Guidelines and tips
Guidelines and tips

MATH 600 Calculus Cheatsheet, Cheat Sheet of Calculus

This cheatsheet provides definitions and theorems related to calculus, including Ck functions, support of continuous functions, total derivative, directional derivative, chain rule, inverse function theorem, and implicit function theorem. It is not a complete cheatsheet.

Typology: Cheat Sheet

2021/2022

Uploaded on 05/11/2023

jugnu900
jugnu900 🇺🇸

4.4

(7)

5 documents

Partial preview of the text

Download MATH 600 Calculus Cheatsheet and more Cheat Sheet Calculus in PDF only on Docsity! MATH 600 Calculus Cheatsheet This cheatsheet is not, of course, complete. Given a natural number k, a function u : Rm → R is called Ck if u has all possible kth derivatives and the kth derivatives are continuous. A function u : Rm → Rn can be written as u = (u1, . . . , un) where each ui : Rm → R. We say u is Ck if each of its components ui is Ck. A function is C∞ if it is Ck for every natural number k. The support of a continuous function u : Rm → R is the closure of the set {x ∈ Rm|u(x) 6= 0}. We write Ck c = {u ∈ Ck|u has compact support}. The total derivative of u : Rm → Rn at x ∈ Rm, denoted Dux, is the linear map Dux : Rm → Rn which best approximates u near x. In a coordinate system, Dux is represented as a n×m matrix, which consists of the partial derivatives of the component functions. The directional derivative of u : Rm → R at x ∈ Rm in the direction V ∈ Rm is DV ux, the derivative of the function uV (t) = u(x + tV ) at t = 0. In a coordinate system, DV ux = Dux · V . The chain rule: If u : Rm → Rn and v : Rn → Rp are both differentiable, then: D(v ◦ u)x = Dvu(x) ·Dux, where · denotes composition of linear maps (in coordinates, matrix multiplication). Inverse Function Theorem. Let x0 ∈ Rm. Suppose u : Rm → Rm is C1 and has Dux0 invertible. Then there are a neighbourhoods W of x0 and V of z0 = u(x0), such that: • u : W → V is invertible • The inverse v : V →W is as smooth as u is. Implicit Function Theorem. Let (x0, y0) ∈ Rm+k. Suppose u : Rm+k → Rk is C1 and that the k × k- submatrix of Du(x0,y0), ( ∂u ∂y ) is invertible. Then there are neighbourhoods W of (x0, y0) and V of x0, and a map g : V → Rk, such that: • g(x0) = y0 • For any x ∈W , u(x, g(x)) = u(x0, y0) = z0 • For any (x, y) ∈ V , if u(x, y) = z0, then y = g(x). • g is as smooth as u is. 1
Docsity logo



Copyright © 2024 Ladybird Srl - Via Leonardo da Vinci 16, 10126, Torino, Italy - VAT 10816460017 - All rights reserved