Download Math110 Final Exam Questions With Answers and more Exams Nursing in PDF only on Docsity! Math110 Final Exam Questions With Answers Question 1 Not yet graded / 10 pts You may find the following files helpful throughout the exam: The following pie chart shows the percentages of total items sold in a month in a certain fast food restaurant. A total of 4700 fast food items were sold during the month. a.) How many were fish? b.) How many were french fries? Your Answer: a. fish 4700(0.28)=1316 b. French fries 4700(0.4)=1880 a.) Fish : 4700(.28) = 1316 b.) French Fries: 4700(.40) = 1880 Question 2 Consider the following data: 430 389 414 401 466 421 399 387 450 407 392 410 440 417 471 Find the 40th percentile of this data. There are a total of fifteen numbers, so n= 15. In order to find the percentiles, we must put the numbers in ascending order: 387 389 392 399 401 407 410 414 417 421 430 440 450 466 471 For the 40th percentile: Therefore, the 40th percentile index for this data set is the 6th observation. In the list above, the 6th observation is 407. Question 3 In a tri-state conference, 60% attendees are from California, 25% from Oregon, and 15% from Washington. As it turns out 6 % of the attendees from California, 17% of the attendees from Oregon, and 12% of the attendees from Washington came to the conference by train. If an attendee is selected at random and found to have arrived by train, what is the probability that the person is from Washington? P(Train│C)=.06.. P(Train│O)=.17.. P(Train│W)=.12.. P(C)=.60,P(O)=.25,P(W)=.15. We want to find P(W│Train), so use: Question 4 Find each of the following probabilities: a. Find P(Z ≤ -0.87) . b. Find P(Z ≥ .93) . c. Find P(-.59 ≤ Z ≤ -.36). a. P(Z ≤ -0.87)= .19215. b. P(Z ≥ .93)=1- .82381= .17619. This is a left-tailed test, so we must find a z that satisfies P(Z<z)=.015. In the standard normal table, we find z.015 = -2.17. For a left-tailed test, we will reject the null hypothesis if the z-score is less than -2.17. Notice that since the z-score is greater than -2.17, we do not reject the null hypothesis. Question 8 Suppose we have independent random samples of size n1 = 570 and n2 = 675. The proportions of success in the two samples are p1= .41 and p2 = .53. Find the 99% confidence interval for the difference in the two population proportions. Answer the following questions: 1. Multiple choice: Which equation would you use to solve this problem? A. B. C. D. 2. List the values you would insert into that equation. 3. State the final answer to the problem From table 6.1, we see that 99% confidence corresponds to z=2.58. Notice that the sample sizes are each greater than 30, so we may use eqn. 8.2: B. So, the interval is (-.1927,-.0473). Question 9 Compute the sample correlation coefficient for the following data: Can you be 95% confident that a linear relation exists between the variables? If so, is the relation positive or negative? Justify you answer. r= .9910 Sx = 4.2 Sy = 5.7. Note that for n=5 and 95% we get a value from the chart of .87834. The absolute of r is |r|=.9910, which is above .87834. So a positive linear relation exists. Question 10 A trucking company wants to find out if their drivers are still alert after driving long hours. So, they give a test for alertness to two groups of drivers. They give the test to 330 drivers who have just finished driving 4 hours or less and they give the test to 215 drivers who have just finished driving 8 hours or more. The results of the tests are given below. Passed Failed Drove 4 hours or less 250 80 Drove 8 hours or more 140 75 Is there is a relationship between hours of driving and alertness? (Do a test for independence.) Test at the 1 % level of significance. H0: Driving hours and alertness are independent events. H1: Driving hours and alertness are not independent events. We have two rows and three columns, so # of Rows =2 and # of Columns=2. The degrees of freedom are given by: DOF = (# of Rows-1)(# of Columns-1)=(2-1)(2-1)=1. Using this, along with .01 (for the 1% level of significance) we find in the chi-square table a critical value of 6.635.
