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mathematics in the modern world, Assignments of Mathematics

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Typology: Assignments

2020/2021

Uploaded on 04/21/2021

em.ay.ey
em.ay.ey ๐Ÿ‡ต๐Ÿ‡ญ

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Download mathematics in the modern world and more Assignments Mathematics in PDF only on Docsity! THE DERIVATIVE y=f(x) y+โˆ†y=f(x+โˆ†x) , โˆ†y=f(x+โˆ†x)-f(x) then we will form โˆ†๐‘ฆ โˆ†๐‘ฅ ๐‘Ž๐‘›๐‘‘ ๐‘กโ„Ž๐‘–๐‘  ๐‘Ÿ๐‘Ž๐‘ก๐‘–๐‘œ ๐‘–๐‘  ๐‘๐‘Ž๐‘™๐‘™๐‘’๐‘‘ ๐‘Ž ๐‘ ๐‘™๐‘œ๐‘๐‘’ or derivative of y with respect to x when โˆ†x approches 0 lim โˆ†๐‘ฅ 0 โˆ†๐‘ฆ โˆ†๐‘ฅ = ๐‘‘๐‘ฆ ๐‘‘๐‘ฅ = lim โˆ†๐‘ฅ 0 ๐‘“(๐‘ฅโˆ’โˆ†๐‘ฅ)โˆ’๐‘“(๐‘ฅ) โˆ†๐‘ฅ Other symbol for derivative yโ€™, fโ€™(x), Dxy , ๐‘‘ ๐‘‘๐‘ฅ ๐‘“(๐‘ฅ) To obtain of any function the general process is as follows: 1. Replace x by x+โˆ†x and y by y+โˆ†y 2. Subtract y by both side to obtain a formula for โˆ†y in terms of x and โˆ†x 3. By some suitable transformation, throw the right member into form w/c contains โˆ†x as explicity factor. 4. Divide through by โˆ†x 5. Determine the limit as โˆ†x approches 0 Example: y=x 1. Y+โˆ†y=x+โˆ†x 2. โˆ†y=x+โˆ†x-x 3. โˆ†y=โˆ†x 4. โˆ†๐‘ฆ โˆ†๐‘ฅ = โˆ†๐‘ฅ โˆ†๐‘ฅ =1 5. lim โˆ†๐‘ฅ 0 1 = 1 Example : Differentiate the function y=๐‘ฅ3 โˆ’ 2๐‘ฅ 1. y+โˆ†y=(๐‘ฅ + โˆ†๐‘ฅ)3 โˆ’ 2(๐‘ฅ โˆ’ โˆ†๐‘ฅ) 2. โˆ†y=(๐‘ฅ + โˆ†๐‘ฅ)3 โˆ’ 2(๐‘ฅ โˆ’ โˆ†๐‘ฅ) - ๐‘ฅ3 + 2๐‘ฅ 3. โˆ†y= ๐‘ฅ3 + 3๐‘ฅ2โˆ†๐‘ฅ + 3โˆ†๐‘ฅ2๐‘ฅ + โˆ†๐‘ฅ3 โˆ’ 2๐‘ฅ โˆ’ 2โˆ†๐‘ฅ โˆ’ ๐‘ฅ3 + 2๐‘ฅ โˆ†y= 3๐‘ฅ2โˆ†๐‘ฅ + 3โˆ†๐‘ฅ2๐‘ฅ + โˆ†๐‘ฅ3 โˆ’ 2โˆ†๐‘ฅ 4. โˆ†๐‘ฆ โˆ†๐‘ฅ = 3๐‘ฅ2 + 3๐‘ฅโˆ†๐‘ฅ + โˆ†๐‘ฅ2 โˆ’ 2 5. yโ€™=3๐‘ฅ2 โˆ’ 2 Example: Differentiate y=4๐‘ฅ2 โˆ’ 3๐‘ฅ โˆ’ 2 1. y+โˆ†y=4(๐‘ฅ + โˆ†๐‘ฅ)2 โˆ’ 3(๐‘ฅ + โˆ†๐‘ฅ) โˆ’ 2 2. โˆ†y= 4(๐‘ฅ + โˆ†๐‘ฅ)2 โˆ’ 3(๐‘ฅ + โˆ†๐‘ฅ) โˆ’ 2 - 4๐‘ฅ2 + 3๐‘ฅ + 2 3. โˆ†y=4๐‘ฅ2 โˆ’ 8๐‘ฅโˆ†๐‘ฅ + 4โˆ†๐‘ฅ2 โˆ’ 3๐‘ฅ + 3โˆ†๐‘ฅ โˆ’ 4๐‘ฅ2 + 3๐‘ฅ โˆ†y=8xโˆ†x+4โˆ†๐‘ฅ2 + 3โˆ†๐‘ฅ 4. โˆ†๐‘ฆ โˆ†๐‘ฅ = 8๐‘ฅ + 4โˆ†๐‘ฅ + 3 5. yโ€™= 8x+3 Example: Differentiate y=โˆš๐‘ฅ 1. y+โˆ†y=โˆš๐‘ฅ + โˆ†๐‘ฅ 2. โˆ†y=โˆš๐‘ฅ + โˆ†๐‘ฅ-โˆš๐‘ฅ 3. โˆ†y=โˆš๐‘ฅ + โˆ†๐‘ฅ-โˆš๐‘ฅ . โˆš๐‘ฅ+โˆ†๐‘ฅ+โˆš๐‘ฅ โˆš๐‘ฅ+โˆ†๐‘ฅ+โˆš๐‘ฅ = (โˆš๐‘ฅ+โˆ†๐‘ฅ) 2 โˆ’(โˆš๐‘ฅ) 2 โˆš๐‘ฅ+โˆ†๐‘ฅ+โˆš๐‘ฅ = ๐‘ฅ+โˆ†๐‘ฅโˆ’๐‘ฅ โˆš๐‘ฅ+โˆ†๐‘ฅ+โˆš๐‘ฅ = โˆ†๐‘ฅ โˆš๐‘ฅ+โˆ†๐‘ฅ+โˆš๐‘ฅ 4. โˆ†๐‘ฆ โˆ†๐‘ฅ = โˆ†๐‘ฅ โˆš๐‘ฅ+โˆ†๐‘ฅ+โˆš๐‘ฅ . 1 โˆ†๐‘ฅ = 1 โˆš๐‘ฅ+โˆ†๐‘ฅ+โˆš๐‘ฅ 5. yโ€™= 1 โˆš๐‘ฅ+โˆš๐‘ฅ = 1 2โˆš๐‘ฅ Example: y=โˆš๐‘ฅ + 2 1. y+โˆ†y= โˆš๐‘ฅ + โˆ†๐‘ฅ + 2 2. โˆ†y= โˆš๐‘ฅ + โˆ†๐‘ฅ + 2-โˆš๐‘ฅ + 2
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