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NOTES
SEPT. 13. 2022
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PROBLEM: Given THE Ear.
2 -
3x* + 327 -5' eA,yzhye
Godlee) (x49) LR aD
[fF Atroringtor is equal
BLSoLVE foe A ~ gertal en
as v2 ot al
#2. SOLVE FoR B®
a4 os ee de
4s Sows for c
aS be erelds
wre D
a
maT CHL:
d@ 432-6) AB
(i) 67) Gra) WH
jeting ign: >, 4, s
ges por Wtyd
gee
Het, wede 6,2
PROBLEM: In the given equation.
Find the value of B
£
are #0 'ha
hb of A
wrt wale
= - 6
3
¥
t
5
Meg oe
| ear oe of, 3, (4-€) (ats)
ge bleed) + G(4-8)
uhen 4e-2
va = wat) +6(-2-9)
“ye -48
BS
va
PROBLEM: FIND THE MEAN
PROPORTION OF 4 & 36 mean proton!
2 GEOMETRIC WEA!
4G 69 ce dw
Gin ay
% a, Y
4, %, 3%
oe i
a 4, 7 y
pel2
wr
PROBLEM: FIND X IF 71S THE FOURTH
PROPORTIONAL TO 36 AND 28 AND X.
a4 oF co) ay
26, a8, 4, +
PROBLEM:
WHAT PERCENTAGE OF THE TIDE OF THE WATER LEVEL WHICH
IS SAFE TO SHIPS DEPTH OF BERTH?
a. 88% b198% c.92% d. 95%
PROBLEM:
WHAT IS THE STANDARD SIGN SHAPE WHICH IS GENERALLY
USED FOR GUIDE SIGNS.
a. TRIANGLE beRECTANGLE c. CIRCLE d. SAUARE
PROBLEM:
TO WHICH OF THE FF SHAPES THE AREA CAN’T BE
CALCULATED IF THE PERIMETER IS GIVEN.
a. CIRCLE‘b)RECTANGLE c. REGULAR HEXAGON d. SQUARE
PROBLEM:
ALPHA, BETA, & GAMMA ARE INNER ANGLES OF TRIANGLE. IS
ALPHA= BETA+GAMMA, WHAT CAN’T BE THE SIZE OF BETA?
a. 44b. 45 c. 89 d:90"
PROBLEM:
WHAT DOES MLLW STANDS FOR,
a. MIN LOWER LEVEL WATER
_b. MEAN LOWER LOW WATER:
c. MAX LEVEL LASER WATER
d. MEAN LOW LEVEL WATER
PROBLEM:
WHAT IS THE SINGLE MOST IMPORTANT ENVIRONMENTAL
FACTOR CONSIDERED IB COASTAL ENGG?
a. Tides / Waves
-b. Coastal Erosion —
c. Coastal Lights
d. Coastal Guards
PROBLEM:
IT IS DESCRIBED AS THE EXPECTED NUMBER OF PRODUCTION.
«agMeam b. Standard Deviation c. Reliability d. Variance
When inside the building one may notice unusual sounds the change in the
building. What causes these events?
.asTemperaturesb. Ductility c. Atoms d. lons
When train passes on curves.which have no super elevation. It will give
thrust on the;
a. Outside of the outer rail
b. Outside of inner rail d. Inside of inner rail
Refers to daily meeting among workers and their respective supervisors for
the purpose of instruction, discussion and proper briefing on the planned
work
a. Morning meeting b. Coffee talk. T66!'bOx” d.fun box
Anything (source,situation,act) with the potential to cause harm.
a. Joy. b. Risk cxHazard d. Plan
The combination of the likelihood of an incident to happen and the severity
of the consequences of such an incident
a. Joy bURISk'c. Hazard d. Plan
Identify the hazard before the incident occur
a. Plan b. Curves . Investigation
Identify the hazards after incident occur
a. Plan b, Steps c. Inspection dillnvestigation?
BOARD PROBLEMS: PROBLEM:
1. HOW MANY SIGNIFICANT DIGITS DO 10.097 IF “A” CAN DO AWORK IN “X” DAYS AND “B” IN
HAVE? “¥" DAYS. HOW LONG WILL THEY FINISH THE
a. 2b.30. 4055" JOB WORKING TOGETHER.
2. ROUND OFF 34.2814 TO FOUR SIGNIFICANT Oalyt bt cole dey
FIGURES. xy % ay ay
qaw84i28b. 34, 2814 c. 0.34 x1042d. 34
3, ROUND OFF 149.691 TO TWO DECIMAL ( Spe L \ayt
PLACES. wry ey 9
1149.69 'b. 149.70 c. 1.49 x1042 d. 14.97 x10
4, WHICH OF TEH FOLLOWING GIVES THE len = oY
SMALLEST EVEN PRIME NUMBER. *
a. 1bi2c. 3d. 162 ye FY
tT
Sy
5. MCMXCIV IS A ROMAN NUMERAL et
EQUIVALENT TO
M= 1000 1994
D=500 IF TANK IS FILLED WITH 2 PIPES. THE FIRST PIPE
c=100 CAN FILL THE TANK IN 10 HRS. BUT AFTER IT
L=50 HAS BEEN OPENED FOR 3 1/3 hrs. THE SECOND
X=10 PIPE IS OPENED AND THE TANK IS FILLED UP IN
Ve5 4hrs MORE. HOW LONGS WOULD IT TAKE THE
SECOND PIPE ALONE TO FILL THE TANK.
a. 8b. 12.33.6095 d. 17.33
. (3-2) LL W) + w =!
vo
PROBLEM
ATEAM OF 24 WORKERS WAS ON AJOB.
THAT COULD FINISH IN 70 DAYS. 10 MORE
WORKERS WERE HIRED ON THE 21st DAY &
8 MORE ON THE 36th DAY, HOW MANY DAYS
EARLIER WOULD THE JOB BE COMPLETED.
a.16.4b.18.6c.14.6d. 21.8
490) + 24(20) + 94( 15) + 42(n)
a= |b.
TTL queation= sor tx
* gots tle-y vel
= BY days joo”
Wo. OF 004s toy
Geld gintth Hhe * W-sid or
“ph cier = (BG days
PROBLEM: CE BOARD
TWENTY EIGHT (28) MEN CAN FINISH THE JOB IN 60 DAYS. AT
THE START OF THE 16th DAY, 5S MEN WERE LAID OFF AND AFTER
THE 45th DAY 10 MORE MEN WERE LAID HIRED. HOW MANY DAYS
WERE THEY DELAYED IN FINISHING THE JOB.
A(tdt b- at comauate d.3.at
a8ua) = aeliE) + 23 (d0) + 390%)
= IT gt dows
We + lst~ 62-2
pened <a. at GD
PROBLEM:
IN HOW MANY MINUTES AFTER 3 OCLOCK WILL THE HANDS
OF THE CLOCK BE
4. TOGETHER FOR THE FIRTS TIME
a. 12.36 b. 15.36 016.36 d. 17.36
2. OPPOSITE FOR THE FIRST TIME
a. 32.73 bv49109'c. 50.09 d. 48.09
3. PERPENDICULAR FOR THE FIRST TIME
(ai32073b. 33.73 c. 34.73 d. 35.73
t+ (40 -0) = [6.36
4 (% un) 2 49.09
+
3 (% ¥40) = 92.83
PROBLEM: CE BOARD
WHAT TIME BETWEEN 2 & 30’CLOCK WILL THE HANDS OF THE
CLOCK BE BISECTED BY THE LINE CONNECTING THE CENTER
OF THE CLOCK AND THE 30’CLOCK MARK.
aeeet he
acer
ma
26g
PROBLEM: CE BOARD
DETERMINE THE TIME OF OSCILLATION OF A PENDULUM HAVING A
LENGTH OF 12m LONG IN MINUTES.
a. 6.956) 0.1158 c. 4.09 d. 0.2093
Note:
Tar} Bly asc + Lee
t at [ 9% Ws
TH 0.1S8 mia