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Methane - Organic Chemistry I - Lecture Slides, Slides of Organic Chemistry

Organic chemistry is one of core subject in chemistry. It is about reactions. It explains why, when and how chemical reactions occur. Key points in this lecture are: Methane, Hydrocarbons, Chemistry of Methane, Combustion, Halogenation, Reactions of Methane, Homolytic Bond, Heat Energy, Collision Frequency, Probability Factor

Typology: Slides

2012/2013

Uploaded on 09/26/2013

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Download Methane - Organic Chemistry I - Lecture Slides and more Slides Organic Chemistry in PDF only on Docsity! Methane docsity.com Hydrocarbons – compounds containing only carbon and hydrogen. hydrocarbons aliphatic aromatic alkanes alkenes alkynes docsity.com Chemistry of methane (reactions)? CH4 + H2O  CH4 + conc. H2SO4  CH4 + conc. NaOH  CH4 + sodium metal  CH4 + KMnO4  CH4 + H2/Ni  CH4 + Cl2  NR (no reaction) NR NR NR NR NR NR docsity.com Methane is typically unreactive. It does not react with water, acids, bases, active metals, oxidizing agents, reducing agents, or halogens. Reactions of methane: 1. Combustion (oxidation;complete & partial) 2. Halogenation docsity.com Reactions of Methane 1. Combustion (oxidation) a) complete oxidation CH4 + 2 O2 , flame or spark  CO2 + H2O + energy b) partial oxidation 6 CH4 + O2 , 1500 o  CO + H2 + H2C2 (acetylene) CH4 + H2O , Ni, 850 o  CO + H2 docsity.com CH4 + Cl2, hv  CH3Cl + HCl methyl chloride chloromethane CH3Cl + Cl2, hv  CH2Cl2 + HCl methylene chloride dichloromethane CH2Cl2 + Cl2, hv  CCl3H + HCl chloroform trichloromethane CCl3H + Cl2, hv  CCl4 + HCl carbon tetrachloride tetrachloromethane docsity.com CH4 + Br2, hv  CH3Br + HBr methyl bromide bromomethane CH3Br + Br2, hv  CH2Br2 + HBr methylene bromide dibromomethane CH2Br2 + Br2, hv  CBr3H + HBr bromoform tribromomethane CBr3H + Br2, hv  CBr4 + HBr carbon tetrabromide tetrabromomethane docsity.com CH3I CH2I2 iodomethane diiodomethane methyl iodide methylene iodide CHI3 CI4 triiodomethane tetraiodomethane iodoform carbon tetraiodide docsity.com Mechanism for the monochlorination of methane initiating step: 1) Cl2  2 Cl• propagating steps: 2) Cl• + CH4  HCl + CH3• 3) CH3• + Cl2  CH3Cl + Cl• then 2), then 3), then 2), etc. terminating steps: 4) Cl• + Cl•  Cl2 5) Cl• + CH3•  CH3Cl 6) CH3• + CH3•  CH3CH3 docsity.com Energy Changes? ΔH Homolytic bond dissociation energies (see inside the front cover of M&B) H—Cl 103 Kcal/mole Cl—Cl 58 Kcal/mole CH3—H 104 Kcal/mole CH3—Cl 84 Kcal/mole docsity.com We need only consider those bonds that are broken or formed in the reaction. CH3—H + Cl—Cl  CH3—Cl + H—Cl +104 +58 -84 -103 PE: +162 -187 ΔH = +162 –187 = -25 Kcal/mole (exothermic, gives off heat energy) docsity.com Rates of chemical reactions depend on three factors: Collision frequency (collision per unit time) Probability factor (fraction of collisions with correct geometry) Energy factor (fraction of collisions with sufficient energy) ―sufficient energy‖ = Energy of activation, minimum energy required for a collision to go to the product. docsity.com FE] Collisions with energy > Ei Collisions with energy > Es —> —> Number of molecules of particular energy Number of molecules of particular energy Average Energy —> Energy —> Figure 2.5. Distribution of kinetic energy Figure 2.6. Distribution of kinetic energy among molecules. among collisions, Wh Alntethutinn AC anMicinn anacniane ne tn mioht awnant be dacerihed hu a ® docsity.com Eact/RTePZrate  ** Z = collision frequency P = probability factor e-Eact/RT = fraction of collisions with E > Eact Note: rate decreases exponentially as the Eact increases! docsity.com Rate determining step (RDS) = the step in the mechanism that determines the overall rate of a reaction. In a ―chain reaction‖ this will be the slowest propagating step. For chlorination of methane, which propagating step is slower? Step 2) ΔH = +1 Kcal/mole Eact > +1 Kcal (estimated) Step 3) ΔH = -26 Kcal/mole Eact > 0 Kcal (estimated) Step 2 is estimated to be slower than step 3 and is the RDS docsity.com An ―alternate mechanism: 2) Cl• + CH4  CH3Cl + H• 3) H• + Cl2  HCl + Cl• Why not this mechanism? Step 2: ΔH = +104-84 = +20 Kcal/mole; Eact > +20 Kcal Step 3: ΔH = +58-103 = -45 Kcal/mole; Eact > 0 Kcal RDS for this mechanism is step 2 and requires a minimum of 20Kcal/mole! Unlikely compared to our mechanism where the RDS only requires an estimated minimum of 1 Kcal! docsity.com 2. Halogenation Δ or hυ CH4 + X2  CH3X + HX requires heat or light X2: Cl2 > Br2  I2 why?…how?…mechanism docsity.com ΔH for each step in the mechanism by halogen: F Cl Br I 1 +38 +58 +46 +36 2 -32 +1 +16 +33 3 -70 -26 -24 -20 4 -38 -58 -46 -36 5 -108 -84 -70 -56 6 -88 -88 -88 -88 docsity.com Estimation of Eact for the propagating steps: Eact (est.) F Cl Br I 2 >0 >+1 >+16 >+33 3 >0 >0 >0 >0 Step 2 is the RDS Rate Cl2 > Br2 because in the RDS Eact(Cl2) < Eact(Br2) NR with I2 because RDS Eact(I2) > +33 Kcal/mole only 1/1012 collisions would have E > +33 at 275o docsity.com Potential energy ——> CH, + Cl: —> CH; + HCI Progress of reaction —> 2.3 Potential energy changes during the progress of reaction: the methane-chlorine atom reaction. docsity.com Hammond’s Postulate: the higher the Eact of a step in a mechanism, the later the transition state is reached and the more the transition state will look like the products. In step 2 of the mechanism for the bromination of methane, the Eact is estimated to be > +16 Kcal/mole. Since the Eact is high, the transition state is reached later in this step than it is in chlorination and will look more like the products: [ Br----H-----------CH3 ] ‡ δ• δ• docsity.com Reactions of Methane 1. Combustion (oxidation) a) complete oxidation CH4 + 2 O2 , flame or spark  CO2 + H2O + heat b) partial oxidation 6 CH4 + O2, 1500 oC  CO + H2 + H2C2 CH4 + H2O, 850 o, Ni  CO + H2 2. Halogenation CH4 + X2, heat or hv  CH3X + HX requires heat or light Cl2 > Br2 NR with I2 docsity.com
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