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Minor Losses in Pipes: Determining Energy Losses and Pressure Differences, Lecture notes of Geometry

Pipe FlowHydraulicsFluid MechanicsTurbulence

An in-depth analysis of minor losses in pipes, including energy losses due to sudden and gradual enlargements, contractions, and fittings. It includes examples of how to calculate energy loss and pressure difference using given pipe diameters, velocities, and loss factors (K).

What you will learn

  • What is the optimum angle for minimum energy losses in pipes?
  • What is the role of loss factor (K) in calculating energy losses in pipes?
  • How does the diameter ratio affect energy losses in pipes?
  • How are minor losses in pipes calculated?
  • What are minor losses in pipes?

Typology: Lecture notes

2021/2022

Uploaded on 09/27/2022

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Download Minor Losses in Pipes: Determining Energy Losses and Pressure Differences and more Lecture notes Geometry in PDF only on Docsity! MINOR LOSSES IN PIPES โ€ข Losses caused by fittings, bends, valves, etc. 1 โ€ข Minor in comparison to friction losses which are considered major. โ€ข Losses are proportional to โ€“ velocity of flow, geometry of device. )2/( 2 gvKhL = โ€ข The value of K is typically provided for various devices. โ€ข Energy lost โ€“ units โ€“ N.m/N or lb-ft/lb 2 D2/D1 = 1.0 -> 10.0 -> to infinity Analytical expression of K - If the velocity v1 < 1.2 m/s or 4 ft/s, the K values can be given as [ ] 22 21 2 21 ])/(1[)/(1 DDAAK โˆ’=โˆ’= 5 Example 10.1 Determine energy loss when 100 L/min of water moved from 1โ€ copper tube to 3โ€ copper tube Procedure - Find velocity of flow and then find K. D1 = 25.3 mm A1 = 0.0005017 m2 D2 = 73.8 mm A2 = 0.004282 m2 V1 = Q1/A1 = [(100 L/min)/(60,000)] / 0.0005017 = 3.32 m/s (convert L/min to m3/s) D2/D1 = 2.92 Use graph โ€“ Figure 10.2 6 K = 0.72 Therefore, hL = 0.72 * (3.32)2 /2*9.81 = 0.40 m 7 Gradual Enlargement If the enlargement is gradual (as opposed to our previous case) โ€“ the energy losses are less. The loss again depends on the ratio of the pipe diameters and the angle of enlargement. )2/( 2 1 gvKhL = K can be determined from Fig 10.5 and table 10.2 - 10 se coefficient K Figure 10.5 - Diameter ratio D,/D, 20ยฐ cone angle 11 Note โ€“ โ€ข If angle increases (in pipe enlargement) โ€“ minor losses increase โ€ข If angle decreases โ€“ minor losses decrease, but you also need a longer pipe to make the transition โ€“ that means more FRICTION losses - therefore there is a tradeoff! 12 โ€ข The section at which the flow is the narrowest โ€“ Vena Contracta โ€ข At vena contracta, the velocity is maximum. K can be computed using Figure 10.7 and table 10.3 โ€“ Again based on diameter ratio and velocity of flow 15 โ€ข Energy losses for sudden contraction are less than those for sudden enlargement 16 Greater loss 17 Note that K values increase for very small angles (less than 15 degrees) Why โ€“ the plot values includes both the effect flow separation and friction! 20 Entrance Losses Fluid moves from zero velocity in tank to v2 21 Resistance Coefficients for Valves & Fittings Loss is given by โ€“ )2/( 2 gvKhL = Where K is computed as โ€“ te fDLK *)/(= Le = equivalent length (length of pipe with same resistance as the fitting/valve) fT = friction factor 22
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